问题
I have a simplified version of the standard interpreter monad transformer generated by FreeT
:
data InteractiveF p r a = Interact p (r -> a)
type Interactive p r = FreeT (InteractiveF p r)
p
is the "prompt", and r
is the "environment"...one would run this using something like:
runInteractive :: Monad m => (p -> m r) -> Interactive p r m a -> m a
runInteractive prompt iact = do
ran <- runFreeT iact
case ran of
Pure x -> return x
Free (Interact p f) -> do
response <- prompt p
runInteractive prompt (f resp)
instance MonadFix m => MonadFix (FreeT (InteractiveF p r)) m a)
mfix = -- ???
I feel like this type is more or less just a constrained version of StateT
...if anything, an Interactive p r IO
is I think a constrained version of IO
...I think...but... well, in any case, my intuiton says that there should be a good instance.
I tried writing one but I can't really seem to figure out. My closest attempt so far has been:
mfix f = FreeT (mfix (runFreeT . f . breakdown))
where
breakdown :: FreeF (InteractiveF p r) a (FreeT (InteractiveF p r) m a) -> a
breakdown (Pure x) = x
breakdown (Free (Interact p r)) = -- ...?
I also tried using a version taking advantage of the MonadFix
instance of the m
, but also no luck --
mfix f = FreeT $ do
rec ran <- runFreeT (f z)
z <- case ran of
Pure x -> return x
Free iact -> -- ...
return -- ...
Anyone know if this is really possible at all, or why it isn't? If it is, what's a good place for me to keep on looking?
Alternatively, in my actual application, I don't even really need to use FreeT
...I can just use Free
; that is, have Interactive
be just a monad and not just a monad transformer, and have
runInteractive :: Monad m => (p -> m r) -> Interactive p r a -> m a
runInteractive _ (Pure x) = return x
runInteractive prompt (Free (Interact p f) = do
response <- prompt p
runInteractive prompt (f response)
If something is possible for this case and not for the general FreeT case, I would also be happy :)
回答1:
Imagine you already had an interpreter for Interactive
.
interpret :: FreeT (InteractiveF p r) m a -> m a
interpret = undefined
It would be trivial to write a MonadFix
instance:
instance MonadFix m => MonadFix (FreeT (InteractiveF p r) m) where
mfix = lift . mfix . (interpret .)
We can directly capture this idea of "knowing the interpeter" without committing to an interpreter ahead of time.
{-# LANGUAGE RankNTypes #-}
data UnFreeT t m a = UnFree {runUnFreeT :: (forall x. t m x -> m x) -> t m a}
-- given an interpreter from `t m` to `m` ^ |
-- we have a value in `t m` of type a ^
UnFreeT
is just a ReaderT
that reads the interpreter.
If t
is a monad transformer, UnFreeT t
is also a monad transformer. We can easily build an UnFreeT
from a computation that doesn't require knowing the interpreter simply by ignoring the interpeter.
unfree :: t m a -> UnFreeT t m a
--unfree = UnFree . const
unfree x = UnFree $ \_ -> x
instance (MonadTrans t) => MonadTrans (UnFreeT t) where
lift = unfree . lift
If t
is a monad transormer, m
is a Monad
, and t m
is also a Monad
, then UnFree t m
is a Monad
. Given an interpreter we can bind together two computations that require the interpeter.
{-# LANGUAGE FlexibleContexts #-}
refree :: (forall x. t m x -> m x) -> UnFreeT t m a -> t m a
-- refree = flip runUnFreeT
refree interpreter x = runUnFreeT x interpreter
instance (MonadTrans t, Monad m, Monad (t m)) => Monad (UnFreeT t m) where
return = lift . return
x >>= k = UnFree $ \interpreter -> runUnFreeT x interpreter >>= refree interpreter . k
Finally, given the interpreter, we can fix computations as long as the underlying monad has a MonadFix
instance.
instance (MonadTrans t, MonadFix m, Monad (t m)) => MonadFix (UnFreeT t m) where
mfix f = UnFree $ \interpreter -> lift . mfix $ interpreter . refree interpreter . f
We can actually do anything the underlying monad can do, once we have the interpreter. This is because, once we have an interpreter :: forall x. t m x -> m x
we can do all of the following. We can go from m x
through t m x
all the way up to UnFreeT t m x
and back down again.
forall x.
lift :: m x -> t m x
unfree :: t m x -> UnFreeT t m x
refree interpreter :: UnFreeT t m x -> t m x
interpreter :: t m x -> m x
Usage
For your Interactive
, you'd wrap the FreeT
in UnFreeT
.
type Interactive p r = UnFreeT (FreeT (InteractiveF p r))
Your interpreters would still be written to produce a FreeT (InteractiveF p r) m a -> m a
. To interpret the new Interactive p r m a
all the way to an m a
you'd use
interpreter . refree interpreter
The UnFreeT
no longer "frees the interpreter as much as possible". The interpreter can no longer make arbitrary decisions about what to do wherever it wants. The computation in UnFreeT
can beg for an interpreter. When the computation begs for and uses an interpreter, the same interpreter will be used to interpret that portion of the program as was used to start interpreting the program.
回答2:
It is not possible to write a MonadFix m => MonadFix (Interactive p r)
instance.
Your InteractiveF
is the base functor of the well studied Moore machines. A Moore machine provides an output, in your case the prompt, then determines the next thing to do based on an input, in your case the environment. A Moore machine always outputs first.
data MooreF a b next = MooreF b (a -> next)
deriving (Functor)
If we follow C. A. McCann's argument about writing MonadFix
instances for Free
but constrain ourselves to the specific case of Free (MooreF a b)
, we will eventually determine that if there's a MonadFix
instance for Free (MooreF a b)
then there must exist a function
mooreFfix :: (next -> MooreF a b next) -> MooreF a b next
To write this function, we must construct a MooreF b (f :: a -> next)
. We don't have any b
s to output. It's conceivable that we could get a b
if we already had the next a
, but a Moore machine always outputs first.
Like the let in State
You can write something close to mooreFfix
if you are reading just one a
ahead.
almostMooreFfix :: (next -> MooreF a b next) -> a -> MooreF a b next
almostMooreFfix f a = let (MooreF b g) = f (g a)
in (MooreF b g)
It then becomes imperative that f
be able to determine g
independently of the argument next
. All of the possible f
s to use are of the form f next = MooreF (f' next) g'
where f'
and g'
are some other functions.
almostMooreFFix :: (next -> b) -> (a -> next) -> a -> MooreF a b next
almostMooreFFix f' g' a = let (MooreF b g) = f (g a)
in (MooreF b g)
where
f next = MooreF (f' next) g'
With some equational reasoning we can replace f
on the right side of the let
almostMooreFFix :: (next -> b) -> (a -> next) -> a -> MooreF a b next
almostMooreFFix f' g' a = let (MooreF b g) = MooreF (f' (g a)) g'
in (MooreF b g)
We bind g
to g'
.
almostMooreFFix :: (next -> b) -> (a -> next) -> a -> MooreF a b next
almostMooreFFix f' g' a = let (MooreF b _) = MooreF (f' (g' a)) g'
in (MooreF b g')
When we bind b
to f' (g' a)
the let
becomes unnecessary and the function has no recursive knot.
almostMooreFFix :: (next -> b) -> (a -> next) -> a -> MooreF a b next
almostMooreFFix f' g' a = MooreF (f' (g' a)) g'
All of the almostMooreFFix
es that aren't undefined
don't even need a let
.
来源:https://stackoverflow.com/questions/29161923/monadfix-instance-for-interpreter-monad-transformer-generated-by-freet