问题
I have a problem with the constructor, which is not working as I'd expect.
If I try to initialize my class like that, it will work and I get a usable object:
vector<float> v;
MyClass<2> a(v);
However, if I try to build a class like below (which should be equivalent) the results are quite unexpected. There is no error message/warning when compiling or running the program. But if you try to use this variable a somewhere and call its methods (for example a.doSomething()), it will crash.
I put some code inside the constructor to notify me if it is used. It turned out that no code inside the constructor was actually executed in this case.
MyClass<2> a(vector<float>());
So I am wondering why this is happening? Is the 2nd declaration illegal?
EDIT: I will post some code of the class
template <int x>
class MyClass {
public:
vector<float> v;
MyClass<x>(vector<float> v1) {
v = v1;
}
};
回答1:
MyClass<2> a(vector<float>());
This is not a variable declaration. It is the declaration of a function named a
that returns a MyClass<2>
object and takes as an argument a "pointer to a function that takes no arguments and returns a vector<float>
." Confusing? Yes. This is what is referred to as the "most vexing parse."
You need extra parentheses:
MyClass<2> a((vector<float>()));
^ ^
Or, you can use copy initialization:
MyClass<2> a = MyClass<2>(vector<float>());
Or, since your constructor isn't explicit
, you could use:
MyClass<2> a = vector<float>();
(Though, unless you mean for vector<float>
objects to be implicitly convertible to MyClass<N>
objects, you probably want to make this constructor explicit
.)
A good compiler should warn you about this sort of thing. Visual C++ warns:
warning C4930: '
MyClass<x> a(std::vector<_Ty> (__cdecl *)(void))
': prototyped function not called (was a variable definition intended?)
Clang warns:
warning: parentheses were disambiguated as a function declarator
MyClass<2> a(vector<float>()); ^~~~~~~~~~~~~~~~~
来源:https://stackoverflow.com/questions/5363748/constructor-not-returning-usable-object