What does it mean “xvalue has identity”?

依然范特西╮ 提交于 2019-12-04 05:02:07

The xvalue does have an identity, but there's a separate rule in the language that a unary &-expression requires an lvalue operand. From [expr.unary.op]:

The result of the unary & operator is a pointer to its operand. The operand shall be an lvalue [...]

You can look at the identity of an xvalue after performing rvalue-to-lvalue conversion by binding the xvalue to a reference:

int &&r = std::move(a);
int *p = &r;  // OK
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