问题
The following is in FSI:
> System.Math.Round(0.2916, 2);;
val it : float = 0.29
> it * 100.;;
val it : float = 29.0
> int it;;
val it : int = 28
The result is the same everywhere I tried - a compiled F# 3.1/.NET 4.0 application, FSI in Visual Studio 2013 and 2015, .NET Fiddle, @fsibot....
Surely this is a bug somewhere, isn't it? What's going on here?
回答1:
This is just how floating point numbers work. The number that appears as 29 in the output is actually slightly smaller than 29 (because floating point numbers are not precise):
> (System.Math.Round(0.2916, 2) * 100.0) - 29.0;;
val it : float = -3.552713679e-15
回答2:
float is binary floating point data type. Not all decimal floating point values can be represented exactly as binary floating point. What FSI shows as 29 is actually 28.999999999999996.
If you want to store precise decimal floating point values, use decimal data type (to make a number literal decimal instead of float add m to it - e.g. 0.2916m).
> System.Math.Round(0.2916m, 2);;
val it : decimal = 0.29M
> it * 100m;;
val it : decimal = 29.00M
> int it;;
val it : int = 29
回答3:
You can change the F# FSI Pretty Printer like Matlab "format long"
fsi.AddPrinter( fun (x:float) -> sprintf "%26.16e" x);;
FSI output
System.Math.Round( 0.2916, 2) // 2.8999999999999998e-001
1./3. // 3.3333333333333331e-001
来源：https://stackoverflow.com/questions/33271337/apparent-f-bcl-floating-point-bug