问题
I am trying to print an integer alongside a string but it's not really working out and am getting confused.
int cmdSeries = 3;
Serial.println("Series : " + cmdSeries);// That's where the problem occur
In visual basic we used to do it this way:
Dim cmdSeries As Integer
Console.Writeline(""Series : {0}", cmdSeries)
So i've tried it with Serial.println but it returns this error : call of overloaded 'println(const char [14], int&)' is ambiguous
Can anyone help my out, I want to achieve this without using any libraries and in a clean way.
回答1:
There is a huge difference between Arduino String class and regular C-string. The first one overloads addition operator, but there is almost excessive usage of dynamic memory. Mainly if you use something like:
String sth = String("blabla") + intVar + "something else" + floatVar;
Much better is just using:
Serial.print("Series : ");
Serial.println(cmdSeries);
Btw, this string literal resides in Flash and RAM memory, so if you want to force using flash only:
Serial.print(F("Series : "));
But it's for AVR
based Arduinos only. This macro can save a lots of RAM, if you are using lots of literals.
EDIT: Sometimes I use this:
template <class T> inline Print & operator<<(Print & p, const T & val) {
p.print(val);
return p;
}
// ...
Serial << F("Text ") << intVar << F("...") << "\n";
It prints each part separately, no concatenations or so.
回答2:
Try this
int cmdSeries = 3;
Serial.println(String("Series : ") + cmdSeries);
来源:https://stackoverflow.com/questions/43325379/how-to-print-integer-alongside-string-arduino