I have an object of type
Arc<RwLock<SessionData>>
And I have a method that is supposed to take some kind of reference to SessionData
fn some_method(session: ...)
I'm using Rocket (a web-framework for Rust), and I can't directly invoke the method, because it is invoked by Rocket. However, I can provide it with an implementation that creates an object that will be passed to the handler. It looks a bit like this:
impl<'a, 'r> request::FromRequest<'a, 'r> for SomeType {
type Error = ();
fn from_request(request: &'a request::Request<'r>) -> request::Outcome<Self, Self::Error> {
// return object here
}
}
I want to avoid returning an RwLock
directly, because I want the handler to have an already-locked object passed to it. However, I can't return a reference or a RwLockReadGuard
, because both of them depend on the RwLock
, which would go out of scope.
Instead, I am trying to create some kind of self-sufficient type that would contain an Arc<RwLock<SessionData>>
, contain the lock guard to this lock, and deref to a SessionData
object.
So far, I have tried some combinations of the following:
- A
Session
object that contains anArc<RwLock<SessionData>>
and aRwLockReadGuard<SessionData>
- An object that contains an
Arc<RwLock<SessionData>>
and aRwLockReadGuardRef<SessionData>
from the owning-ref library. - An object that would use the
OwnedHandle
type from the owning-ref library.
However, I haven't been able to do what I want to do, running into various lifetime borrowing issues and whatnot.
Is it at all possible to create a sort of a self-contained 'Handle'-like object that would contain both the lock and the lock guard to the object that it points to?
This is a similar, but slightly different situation than described in How to return reference to a sub-value of a value that is under a mutex?. In there, the MutexGuardRef
internally depends on Mutex
, and cannot exist if the Mutex
(or MyStruct
) goes out of scope. In order to achieve similar behaviour, I'd have to pass a struct that contains my RwLock
and then do the locking inside the method. This is fine, but I'm wondering if I can go another step further, and pass a struct that is both independent and serves as a RwLockGuard
, avoiding the need to lock manually.
Basically, I want to move the locking of the RwLock
from the client to the provider of the value.
As described in Why can't I store a value and a reference to that value in the same struct?, the Rental crate allows for self-referential structs in certain cases.
#[macro_use]
extern crate rental;
use std::sync::{Arc, RwLock};
struct SessionData;
impl SessionData {
fn hello(&self) -> u8 { 42 }
}
rental! {
mod owning_lock {
use std::sync::{Arc, RwLock, RwLockReadGuard};
#[rental(deref_suffix)]
pub struct OwningReadGuard<T>
where
T: 'static,
{
lock: Arc<RwLock<T>>,
guard: RwLockReadGuard<'lock, T>,
}
}
}
use owning_lock::OwningReadGuard;
fn owning_lock(session: Arc<RwLock<SessionData>>) -> OwningReadGuard<SessionData> {
OwningReadGuard::new(session, |s| s.read().unwrap())
}
fn main() {
let session = Arc::new(RwLock::new(SessionData));
let lock = owning_lock(session.clone());
println!("{}", lock.hello());
assert!(session.try_read().is_ok());
assert!(session.try_write().is_err());
drop(lock);
assert!(session.try_write().is_ok());
}
See also:
来源:https://stackoverflow.com/questions/50496879/returning-a-rwlockreadguard-independently-from-a-method