zipfile

Extract uncompressed size of zip file embedded in jar

狂风中的少年 提交于 2019-12-13 07:04:27
问题 I have a zip file embedded in my jar and want to read the uncompressed size. My current way of doing this: ZipFile zipFile = new ZipFile(new File(this.getClass().getClassLoader().getResource("files.zip").toURI())); Enumeration<? extends ZipEntry> e = zipFile.entries(); long installedSize = 0; while (e.hasMoreElements()) { ZipEntry entry = e.nextElement(); installedSize += entry.getSize(); } This is of course rather dirty and also doesn't work when I embed my jar file into an exe file using

Bulk download of images rendered under mulitple categories in a single html page

家住魔仙堡 提交于 2019-12-13 03:48:07
问题 I have lot of images stored in a single folder in a S3 bucket. There are three categories(let's say A, B and C) and an image would fall into only one of the three categories. I am rendering all the images category wise on view-all.html page. What I am trying to do is add a separate download button beside the name of each category in the view-all.html. Upon clicking on a particular download button, the images present only under that category should be downloaded as a zip-file. Currently the

Python - ZipFile' object has no attribute 'seek'

僤鯓⒐⒋嵵緔 提交于 2019-12-13 02:51:48
问题 got a problem with my code here. I am trying to get a script working that can make an ePub file. They are compressed zip files that are deflated (i.e. without compression) and have to be done in order. This current script will create a .zip but it is unusable a creates errors both in Python Shell and on the Terminal app when running the zip -t command. The error in question is as follows on the Python shell: Traceback (most recent call last): File "/Users/Hal/Documents/GitHub/Damore-essay

I need to extract .tar.Z file using java [duplicate]

試著忘記壹切 提交于 2019-12-13 02:45:51
问题 This question already has answers here : Read a .Z file (unix compresses file) in Java (2 answers) Closed 2 years ago . Do anyone have coding in java to extract .tar.Z files. Assume that i am having file called home.tar.Z I need extract this file using java code, can you give any sample code. Thanks 回答1: The .Z extension is not the gzip extension, it is from compress . You can launch shell scripts from Java, I'd do it like that, since I don't know any compress library for Java. For tar/gz you

Selective extracting and opening for zipfile in python

最后都变了- 提交于 2019-12-13 01:04:38
问题 From the docs, it looks like it's possible to perform selective file extract and open using the zipfile module in native python, http://docs.python.org/2/library/zipfile using ZipFile.extract(member[, path[, pwd]]) Extract a member from the archive to the current working directory; member must be its full name or a ZipInfo object). Its file information is extracted as accurately as possible. path specifies a different directory to extract to. member can be a filename or a ZipInfo object. pwd

How to create symlink in zipfile in python

本小妞迷上赌 提交于 2019-12-13 00:40:01
问题 I have a zipfile which is stored in memory as io.BytesIO buffer. Within, the zipfile, I need to create a symlink to one of the directories. Below is what I have tried so far (from this similar question on SO) but it is not creating the link as I want at top level. Link to be created to : root/scale/lib/hypervisor/kvm/pika_3_5 Link name : 'pika' Link location : at top level Existing Zipfile : data['egg_buffer'] with zipfile.ZipFile(data['egg_buffer'], 'a') as zip_buffer: dest = 'root/scale/lib

Reading CSV files from zip archive with python-3.x

丶灬走出姿态 提交于 2019-12-12 12:33:10
问题 I have a zipped archive that contains several csv files. For instance, assume myarchive.zip contains myfile1.csv , myfile2.csv , myfile3.csv In python 2.7 I was able to load iteratively all the myfiles in pandas using import pandas as pd import zipfile with zipfile.ZipFile(myarchive.zip, 'r') as zippedyear: for filename in ['myfile1.csv', 'myfile2.csv', 'myfile3.csv']: mydf = pd.read_csv(zippedyear.open(filename)) Now doing the same thing with Python 3 throws the error ParserError: iterator

Extracting a .app from a zip file in Python, using ZipFile

冷暖自知 提交于 2019-12-12 10:02:30
问题 I'm trying to extract new revisions of Chromium.app from their snapshots, and I can download the file fine, but when it comes to extracting it, ZipFile either extracts the chrome-mac folder within as a file, says that directories don't exist, etc. I am very new to python, so these errors make little sense to me. Here is what I have so far. import urllib2 response = urllib2.urlopen('http://build.chromium.org/buildbot/snapshots/chromium-rel-mac/LATEST') latestRev = response.read() print

Read binary file from a zip file from C# without unzipping it

拈花ヽ惹草 提交于 2019-12-12 09:49:07
问题 I would like to read a binary file from a zip file without unzipping it . The zip file structure: zipFolderName/subFolder/BinFile In the BinFile, I have: Id1, id2, value1 // id1, id2 are string, value1 is int In C#: ZipEntry binFileName = …; // it has been got from zipFile entries MemoryStream ms = new MemoryStream(); binFileName.Extract(ms); using (BinaryReader reader = new BinaryReader(ms)) { string id1 = reader.ReadString(); // error popped here string id2 = reader.ReadString(); int value1

How to create compressed Zip archive using ZipOutputStream so that method getSize() of ZipEntry returns correct size?

末鹿安然 提交于 2019-12-12 07:59:18
问题 Consider the code example that put a single file test_file.pdf into zip archive test.zip and then read this archive: import java.io.*; import java.util.zip.ZipEntry; import java.util.zip.ZipInputStream; import java.util.zip.ZipOutputStream; public class Main { public static void main(String[] args) { File infile = new File("test_file.pdf"); try ( FileInputStream fis = new FileInputStream(infile); ZipOutputStream zos = new ZipOutputStream(new FileOutputStream("test.zip")); ) { int bytesRead;