xsd

Validate XML against XSD with JavaScript on client side

╄→гoц情女王★ 提交于 2021-01-20 04:27:57
问题 I am required to show a user an XMLfile in a friendly way as a result I am creating a tree like structure such as: http://thecodeplayer.com/walkthrough/css3-family-tree instead of showing the user the raw XML. Right now when creating a new node I am validating that on the server side. If the server validates the new proposed XML(tree) then I go ahead and create a new node for example. Anyways now I will like to allow the user to drag these nodes. When dragging the nodes if I validate the

Validate XML against XSD with JavaScript on client side

谁说我不能喝 提交于 2021-01-20 04:25:43
问题 I am required to show a user an XMLfile in a friendly way as a result I am creating a tree like structure such as: http://thecodeplayer.com/walkthrough/css3-family-tree instead of showing the user the raw XML. Right now when creating a new node I am validating that on the server side. If the server validates the new proposed XML(tree) then I go ahead and create a new node for example. Anyways now I will like to allow the user to drag these nodes. When dragging the nodes if I validate the

Parse an XSD file using python

浪子不回头ぞ 提交于 2021-01-04 07:34:25
问题 I am trying to generate an XML file from a given XML schema. I have been able to do it with pyxb library in python. But the problem is as the XSD gets huge it is impossible to manually encode each and evey tag. Is there any python library which creates a data structure from a given XSD file which can be iterated through 回答1: You can generate XML file from XSD file: import requests with open('file.xsd', 'r') as f: data = f.read() r = requests.post('https://www.liquid-technologies.com/api

Parse an XSD file using python

北慕城南 提交于 2021-01-04 07:34:06
问题 I am trying to generate an XML file from a given XML schema. I have been able to do it with pyxb library in python. But the problem is as the XSD gets huge it is impossible to manually encode each and evey tag. Is there any python library which creates a data structure from a given XSD file which can be iterated through 回答1: You can generate XML file from XSD file: import requests with open('file.xsd', 'r') as f: data = f.read() r = requests.post('https://www.liquid-technologies.com/api

Element cannot have character [children], because the type's content type is element-only

旧街凉风 提交于 2020-12-25 02:03:14
问题 I tried validating my XML file with a XSD file but I get the following error message: [Error]: cvc-complex-type.2.3: Element 'paragraph' cannot have character [children], because the type's content type is element-only Which (if i am understanding it correctly) means a complex type cannot have a combination of simple and complex typed elements as children. But how do I fix this? I'm still kinda new to this, so the solution could be simple? My code is shown below: XSD: <?xml version="1.0"

Element cannot have character [children], because the type's content type is element-only

人走茶凉 提交于 2020-12-25 02:02:19
问题 I tried validating my XML file with a XSD file but I get the following error message: [Error]: cvc-complex-type.2.3: Element 'paragraph' cannot have character [children], because the type's content type is element-only Which (if i am understanding it correctly) means a complex type cannot have a combination of simple and complex typed elements as children. But how do I fix this? I'm still kinda new to this, so the solution could be simple? My code is shown below: XSD: <?xml version="1.0"

Create XML from SQL select query

拟墨画扇 提交于 2020-12-15 08:32:42
问题 I am trying to create a xml from a SQL select, but I can not insert ":" (like cac:PartyTaxScheme), neither can put 2 data in one element, look element "cbc:CompanyID" (<cbc:CompanyID schemeName="31" schemeID="0" schemeAgencyID="195">900711000</cbc:CompanyID> ), how can I do it ? Next is the example I want to expect: <cac:PartyTaxScheme> <cbc:RegistrationName>GRUPO FAM</cbc:RegistrationName> <cbc:CompanyID schemeName="31" schemeID="0" schemeAgencyID="195">900711000</cbc:CompanyID> <cbc

XML schema, why xs:group can't be child of xs:all?

有些话、适合烂在心里 提交于 2020-12-12 17:41:09
问题 According to this page (and my practice), xs:group element cannot be child of xs:all . So something like <xs:group name="g"> <xs:element name="first" type="xs:string"/> <xs:element name="last" type="xs:string"/> </xs:group> <xs:all> <xs:group ref="g" minOccurs="0" maxOccurs="1"/> <xs:element name="id" type="xs:string"/> </xs:all> is not valid because group cannot be inside xs:all . But I want to define a schema, in which two elements ( first and last in above example) both exist or neither of

XML schema, why xs:group can't be child of xs:all?

女生的网名这么多〃 提交于 2020-12-12 17:39:11
问题 According to this page (and my practice), xs:group element cannot be child of xs:all . So something like <xs:group name="g"> <xs:element name="first" type="xs:string"/> <xs:element name="last" type="xs:string"/> </xs:group> <xs:all> <xs:group ref="g" minOccurs="0" maxOccurs="1"/> <xs:element name="id" type="xs:string"/> </xs:all> is not valid because group cannot be inside xs:all . But I want to define a schema, in which two elements ( first and last in above example) both exist or neither of

How to Add schemaLocation attribute to an XML document

落花浮王杯 提交于 2020-12-06 04:15:53
问题 Please view following XML namespace and schemaLocation. <agr:ABWInvoice xsi:schemaLocation = " http://services.agresso.com/schema/ABWInvoice/2011/11/14 http://services.agresso.com/schema/ABWInvoice/2011/11/14/ABWInvoice.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:agrlib = "http://services.agresso.com/schema/ABWSchemaLib/2011/11/14" xmlns:agr = "http://services.agresso.com/schema/ABWInvoice/2011/11/14" > </agr:ABWInvoice> I have added namespaces in following way, which