xmlnode

I know there is no direct method of doing it but still.. Can we convert XElement element into XmlNode . Options like InnerText and InnerXml are XmlNode specific. so,if i want to use these options, what can be done to convert XElement into XmlNode and vice versa. Here is converting from string to XElement to XmlNode and back to XElement. ToString() on XElement is similar to OuterXml on XmlNode. XElement xE = XElement.Parse("<Outer><Inner><Data /></Inner></Outer>"); XmlDocument xD = new XmlDocument(); xD.LoadXml(xE.ToString()); XmlNode xN = xD.FirstChild; XElement xE2 = XElement.Parse(xN

I need to have a script which can insert / append new xml child nodes to a pre-existing xml parent node. --New child nodes DECLARE @XMLChildData XML SET @XMLChildData = ' <Persons> <Person> <Firstname>Gary</Firstname> <Surname>Smith</Surname> <Telephone>0115547899</Telephone> <Address> <AddressLine>1 Church Lane</AddressLine> <AddressLine>Rosebank</AddressLine> <AddressLine>Houghton</AddressLine> <AddressLine>South Africa</AddressLine> </Address> </Person> <Person> <Firstname>Wayne</Firstname> <Surname>Farmey</Surname> <Telephone>0117453269</Telephone> <Address> <AddressLine>51 Oak Street<

I have been working with a 3rd party java based REST webservice, that returns an array of xmlNodes. The xmlNode[] respresent an object and I am trying to work out the best way to Deserialize the xmlNode[] in the object? is it to build up a xmlDocument first and the Deserialize ? Thanks If you have the WCF Rest Starter Kit preview installed, there's a neat trick: open Visual Studio select your XML node contents (the XML that makes up one of your nodes) and copy it to the clipboard from your "Edit" menu in Visual Studio, pick "Paste XML as Types" This will paste your XML that's on the clipboard

I want to load up an XmlNode without getting an XmlException when an unrecognized namespace is present. The reason is because I need to pass an XMLNode instance to a method. I'm loading up arbitrary XML fragments having namespaces out of their original context (e.g. MSWord formatting and other software products with various schemas that "pollute" the content with their namespace prefixes). The namespaces are not important to me or to the target method to which it's passed. (This is because the target method uses it as HTML for rendering and namespaces will be ignored or suppressed naturally.)

In my application, I'm converting from one web service to another. I get an XML response as an XmlDocument . I'm trying to get specific nodes in the document. I know there will only ever be one instance of the node I'm looking for. The previous implementer was able to get exactly what he wants with: XmlNode node = xmlDoc.SelectSingleNode("//result/geometry/location/lat/text()"); I'm trying to do the same with my response, but always get null back. I know (vaguely) what his XML response looked like, and know mine. But I can't use his syntax. I get null no matter what. I'm using a more complex

I have a XML node with a value which is a white space. Example: <sampleNode> </sampleNode> I am using a Serializer to get the data from XML document to store it in an object. Now, the problem I am facing is: If the XML node value contains nothing but a white space, as does the sample node above, the serializer interpretates it as a string.Empty. How can I overcome this? I need get the actual white space, i.e. " ". Thanks a bunch! Assuming you are using XmlDocument, you should set the PreserveWhiteSpace property to True. If using and XmlReader set the WhitespaceHandling property

I need a XSLT function which will return me the xpath to the node from which it called. XML <root> <node> <subnode /> <subnode /> <subnode /> </node> <node> <subnode> <subsubnode > <xsl:value-of select="fn:generateXPath()" /> </subsubnode > </subnode> </node> </root> XSL <xsl:template match="root/node/subnode/sub" > <xsl:value-of select="fn:generateXPath()" /> </xsl:template> <xsl:function name="fn:generateXPath" > <xsl:for-each select="ancestor::*"> <xsl:value-of select="name()" /> </xsl:for-each> <xsl:value-of select="name()" /> </xsl:function> I tried with the above function but it throws