word

Python: Find a list of words in a text and return its index

由 廉价感情. 提交于 2020-01-23 15:14:06
问题 I have to process a document in plain text, looking for a word list and returning a text window around each word found. I'm using NLTK. I found posts on Stack Overflow where they use regular expressions for finding words, but without getting their index, just printing them. I don't think use RE is right, cause I have to find specific words. 回答1: This is what you are looking for: You can either use str.index or str.find: Contents of file: Lorem ipsum dolor sit amet, consectetur adipiscing elit

How to find index of an exact word in a string in Python

由 五迷三道 提交于 2020-01-20 05:48:45
问题 word = 'laugh' string = 'This is laughing laugh' index = string.find ( word ) index is 8, should be 17. I looked around hard, but could not find an answer. 回答1: You should use regex (with word boundary) as str.find returns the first occurrence. Then use the start attribute of the match object to get the starting index. import re string = 'This is laughing laugh' a = re.search(r'\b(laugh)\b', string) print(a.start()) >> 17 You can find more info on how it works here. 回答2: try this: word =

Noun / Adjective / Etc Word Lists or Dictionaries (Common Words)

由 Deadly 提交于 2020-01-17 01:21:29
问题 I am looking for dictionaries that are split up by parts of speech and are preferably more common words. I am trying to generate random band names for fun. I found a set of dictionaries HERE which was compiled from the MOBY Word Lists and the UK Advanced Cryptics Dictionary , however, when I generate random band names I get stuff like this: bandName = "Nummulite Repercussions" bandName = "Lemures DebasementsEarphones" which is obviously dumb. Any suggestions? 回答1: http://dictionary-thesaurus

How to Remove line if word exists? (PHP)

由 淺唱寂寞╮ 提交于 2020-01-15 11:13:50
问题 Hey, I want to remove the whole line if a word exists in it? through PHP? Example: hello world, this world rocks . What it should do is: if it finds the word hello it should remove the whole line. How can i do that and there could be words in between brackets and inverted commas also. Thanks. 回答1: If you have an array of lines like so $lines = array( 'hello world, this world rocks', 'or possibly not', 'depending on your viewpoint' ); You can loop through the array and look for the word

Get current word on caret position

由 落爺英雄遲暮 提交于 2020-01-13 02:11:59
问题 How can I get a word in textarrea by its current caret position? I tried something like this, however this returns just the words first letter upto the character at caret position. For example: if the cursor is between fo and o it returns fo and not foo as excpected. Fo | o bar is not equal to bar foo. => Fo expects Foo Foo bar is not equ | al to bar foo. => equ expects equal . Here's what I've done so far: function getCaretPosition(ctrl) { var start, end; if (ctrl.setSelectionRange) { start

Get current word on caret position

由 删除回忆录丶 提交于 2020-01-13 02:11:26
问题 How can I get a word in textarrea by its current caret position? I tried something like this, however this returns just the words first letter upto the character at caret position. For example: if the cursor is between fo and o it returns fo and not foo as excpected. Fo | o bar is not equal to bar foo. => Fo expects Foo Foo bar is not equ | al to bar foo. => equ expects equal . Here's what I've done so far: function getCaretPosition(ctrl) { var start, end; if (ctrl.setSelectionRange) { start

C++ int vs long long in 64 bit machine

由 旧巷老猫 提交于 2020-01-12 01:13:54
问题 My computer has 64 bit processor and when I look for sizeof(int) , sizeof(long) , and sizeof(long long) , it turns out that int and long are 32 bits, and long long is 64 bit. I researched the reason, and it appears that popular assumption telling that int in C++ fits machine's word size is wrong. As I understood it is up to compiler to define what will be the size, and mine is Mingw-w64. The reason for my research was understanding that if the usage of types smaller than word size is

C++ int vs long long in 64 bit machine

由 房东的猫 提交于 2020-01-12 01:13:42
问题 My computer has 64 bit processor and when I look for sizeof(int) , sizeof(long) , and sizeof(long long) , it turns out that int and long are 32 bits, and long long is 64 bit. I researched the reason, and it appears that popular assumption telling that int in C++ fits machine's word size is wrong. As I understood it is up to compiler to define what will be the size, and mine is Mingw-w64. The reason for my research was understanding that if the usage of types smaller than word size is

使用POI读写word doc文件

由 拟墨画扇 提交于 2020-01-09 14:12:46
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> Apache poi的hwpf模块是专门用来对word doc文件进行读写操作的。在hwpf里面我们使用 HWPFDocument 来表示一个word doc文档。在HWPFDocument里面有这么几个概念： l Range ：它表示一个范围，这个范围可以是整个文档，也可以是里面的某一小节（Section），也可以是某一个段落（Paragraph），还可以是拥有共同属性的一段文本（CharacterRun）。 l Section ：word文档的一个小节，一个word文档可以由多个小节构成。 l Paragraph ：word文档的一个段落，一个小节可以由多个段落构成。 l CharacterRun ：具有相同属性的一段文本，一个段落可以由多个CharacterRun组成。 l Table ：一个表格。 l TableRow ：表格对应的行。 l TableCell ：表格对应的单元格。 Section、Paragraph、CharacterRun和Table都继承自Range。 1 读word doc文件 在日常应用中，我们从word文件里面读取信息的情况非常少见，更多的还是把内容写入到word文件中。使用POI从word doc文件读取数据时主要有两种方式：通过 WordExtractor

python pandas dataframe words in context: get 3 words before and after

由 我的梦境 提交于 2020-01-06 15:43:27
问题 I am working in jupyter notebook and have a pandas dataframe "data": Question_ID | Customer_ID | Answer 1 234 Data is very important to use because ... 2 234 We value data since we need it ... I want to go through the text in column "Answer" and get the three words before and after the word "data". So in this scenario I would have gotten "is very important"; "We value", "since we need". Is there an good way to do this within a pandas dataframe? So far I only found solutions where "Answer"
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