while-loop

问题 Why does SwiftUI like to throw errors like Closure containing control flow statement cannot be used with function builder 'ViewBuilder' When I simply try something like VStack { for i in 0...10 { Text("Hello, world!") } } It will not compile. Why does swift care? How does the SwiftUI framework even detect if there are control flow statements, and throw errors? 回答1: How does the SwiftUI framework even detect if there are control flow statements, and throw errors? It doesn't. The Swift language

问题 Why does SwiftUI like to throw errors like Closure containing control flow statement cannot be used with function builder 'ViewBuilder' When I simply try something like VStack { for i in 0...10 { Text("Hello, world!") } } It will not compile. Why does swift care? How does the SwiftUI framework even detect if there are control flow statements, and throw errors? 回答1: How does the SwiftUI framework even detect if there are control flow statements, and throw errors? It doesn't. The Swift language

问题 I just learn my first python and try to make a continuous loop that has a user input condition. #Make the calculating func def data_cal(): pennies = int(input("What's your pennies?")) dollars = pennies // 100 cents = pennies % 100 print("You have $", dollars, "and", cents, "cents") data_cal() #User input for answer repeat = input("Do you want to try again?") answer = ['yes','YES','Yes','y','Y'] #Loop for answer while repeat in answer data_cal() else: print("Bye then") I was thinking if I can

问题 I just learn my first python and try to make a continuous loop that has a user input condition. #Make the calculating func def data_cal(): pennies = int(input("What's your pennies?")) dollars = pennies // 100 cents = pennies % 100 print("You have $", dollars, "and", cents, "cents") data_cal() #User input for answer repeat = input("Do you want to try again?") answer = ['yes','YES','Yes','y','Y'] #Loop for answer while repeat in answer data_cal() else: print("Bye then") I was thinking if I can

问题 I just learn my first python and try to make a continuous loop that has a user input condition. #Make the calculating func def data_cal(): pennies = int(input("What's your pennies?")) dollars = pennies // 100 cents = pennies % 100 print("You have $", dollars, "and", cents, "cents") data_cal() #User input for answer repeat = input("Do you want to try again?") answer = ['yes','YES','Yes','y','Y'] #Loop for answer while repeat in answer data_cal() else: print("Bye then") I was thinking if I can

问题 I´m currently working on my semester work and this is a piece of my code. As you can see there is a for loop with some if statements where I am working with a structure. I was thinking of converting this for loop onto a while loop but I´m not quite sure how. Maybe someone may give me a hint? for(X = 1; X <= 100; X++) { if(structure[X].number == -1) { structure[X].number = number; structure[X].first_info = position; structure[X].second_info = position; break; } if(structure[X].number == number

问题 I've written a function trailing_zeroes(int n) that returns the number of the trailing zeroes in the binary representation of a number. Example : 4 in binary is 100 , so the function in this case returns 2 . unsigned trailing_zeroes(int n) { unsigned bits; bits = 0; while (n >= 0 && !(n & 01)) { ++bits; if (n != 0) n >>= 1; else break; } return bits; } The reason of the if statement is because in case n equals to 0, there will be a loop. I think it's pretty ugly this code written like this;

问题 I've written a function trailing_zeroes(int n) that returns the number of the trailing zeroes in the binary representation of a number. Example : 4 in binary is 100 , so the function in this case returns 2 . unsigned trailing_zeroes(int n) { unsigned bits; bits = 0; while (n >= 0 && !(n & 01)) { ++bits; if (n != 0) n >>= 1; else break; } return bits; } The reason of the if statement is because in case n equals to 0, there will be a loop. I think it's pretty ugly this code written like this;

问题 [Community edit to give reproducible example:] def main(): e = None print(locals()) while not e: try: raise Exception except Exception as e: pass main() produces ~/coding$ python3.3 quiz2.py {'e': None} Traceback (most recent call last): File "quiz2.py", line 11, in <module> main() File "quiz2.py", line 5, in main while not e: UnboundLocalError: local variable 'e' referenced before assignment [EDITED] to include a reproducible code I am trying to run a while-loop, and the condition I use is

问题 I am trying to write a program that reads numbers input by the user until the user types done. If the user types a non-number other than "done," I want to return an error message like "please enter a number number. When the user types "done", I want to calculate the total of the numbers, the number count and the average. I have tried to create a while loop with try and except to catch the non-numeric error other than done. That is part of the trick, a string entry is an error unless the