wan

Is it possible to have basic wan replication for hazelcast open-source edition?

由 别说谁变了你拦得住时间么 提交于 2019-12-25 05:47:07
问题 I'm aware that on hazelcast editions comparison page: https://hazelcast.com/pricing/ it is clearly specified that WAN replication is only for enterprise edition. But, on the other hand, this hazelcast documentation is divided into two parts: https://docs.hazelcast.org/docs/latest/manual/html-single/#wan Only the second part is explicit about enterprise edition, making one assume that the first part refers to non enterprise edition. I also noticed that the parameters are a bit diferent between

Is it possible to have basic wan replication for hazelcast open-source edition?

由 给你一囗甜甜゛ 提交于 2019-12-25 05:46:02
问题 I'm aware that on hazelcast editions comparison page: https://hazelcast.com/pricing/ it is clearly specified that WAN replication is only for enterprise edition. But, on the other hand, this hazelcast documentation is divided into two parts: https://docs.hazelcast.org/docs/latest/manual/html-single/#wan Only the second part is explicit about enterprise edition, making one assume that the first part refers to non enterprise edition. I also noticed that the parameters are a bit diferent between

UDP Client receives only 1 message

由 情到浓时终转凉″ 提交于 2019-12-25 03:52:34
问题 I have a server client application that I am currently working on. The server is receiving data fine over a WAN and the client seems to receive the data, but the client is only receiving one communication. Is there anything over a WAN that would make a client always only receive the first return UDP communication and none of the subsequent. Thanks for the help. Client UDP Listening code private void receiveUDP() { System.Net.IPEndPoint test = new System.Net.IPEndPoint(System.Net.IPAddress.Any

How to make an android peer to peer without using intermediate server? [closed]

由 你说的曾经没有我的故事 提交于 2019-12-18 11:29:01
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed last year . I need to make an android peer to peer app that should work with any Internet connectivity and without using intermediate server. Can somebody plz give me any start up ideas. I haven't find any answer while googling. Any help would be appreciated. Regards, Pawan 回答1: Adobe AIR,

Broadcast on different subnets

由 陌路散爱 提交于 2019-12-13 00:58:57
问题 Please if you can help me about my problem. On one side I have server with IP 172.27.13.2 connected to the WAN interface of router 172.27.13.1 ...Then on wireless LAN of my router 192.168.1.1 I have connected a few clients. Now I will write code in C where client are requesting some UDP streams from server, then server broadcasts streams to clients, and if some packets get lost clients must send NACK to server. My questions is: Because server and clients are on different subnets how can I

数据包在不同网段间传送过程中mac及ip的变化

由 二次信任 提交于 2019-12-11 08:09:05
一、前言 最近一直在做网络编程的项目，编程和调试过程中关注的点始终是收发数据是否正常，只是为了确保数据能够被正常收到就好，那么数据包从一台主机发出，去往另外一台主机的过程是怎么样的？数据包经历了什么，有没有变化，ip地址变化还是mac地址变了？每天陪伴我们的电脑又是如何正常上网的呢？上网的数据包又是怎么传输的？这些问题成为我最新的关注点，这篇文章将一一为大家揭开这些神秘的面纱，详细介绍一下数据包的走向。 二、网络拓扑： 我们假设现有的网络拓扑图如图1所示： 图1 整个网络拓扑中有三个路由器R1,R2,R3;俩台主机PC1,PC2。其中R3 wan口是接外网环境，lan口接R1,R2构造俩个内部的局域网，PC1，PC2分别在R1,R2所构造的局域网内。 路由器wan，lan配置如下： R3： wan :218.205.167.2，lan:10.66.0.1 R1: wan:10.66.0.3，lan:192.168.33.1 R2: wan:10.66.0.2，lan:192.168.22.1 主机IP配置如下： PC1:192.168.33.105 PC2:192.168.22.103 三、跨网段访问内网： 如图1所示(假设PC2向PC1发送一个Ping请求)： PC1与PC2从属不同的网段，数据包是如何传输的呢？我们暂且做如下假设： ①假定传输的有效数据不管；

consul配置参数大全、详解、总结

由 与世无争的帅哥 提交于 2019-12-05 19:55:20
命令行选项 以下选项全部在命令行中指定。 -advertise - 通告地址用于更改我们通告给集群中其他节点的地址。 默认情况下， -bind 地址是通告的。 但是，在某些情况下，可能存在无法绑定的可路由地址。 这个标志使闲聊不同的地址来支持这一点。 如果此地址不可路由，则节点将处于持续振荡状态，因为其他节点会将非可路由性视为故障。 在Consul 1.0和更高版本中，这可以设置为 go-sockaddr 模板。 -advertise-wan - 广告WAN地址用于更改我们向通过WAN加入的服务器节点发布的地址。 这也可以在与 translate_wan_addrs 配置选项 结合使用时在客户端代理上设置 。 默认情况下， -advertise 地址是通告的。 但是，在某些情况下，所有数据中心的所有成员都不能位于同一个物理或虚拟网络上，尤其是混合云和专用数据中心的混合设置。 该标志使服务器节点能够通过WAN的公共网络闲聊，同时使用专用VLAN来相互闲聊以及彼此的客户端代理，并且如果远程数据中心是远程数据中心，则允许客户端代理在从远程数据中心访问时访问此地址配置 translate_wan_addrs 。 在Consul 1.0和更高版本中，这可以设置为 go-sockaddr 模板 -bootstrap - 该标志用于控制服务器是否处于“引导”模式。 每个 数据中心 最多 只能运行

python computer info look

由 喜欢而已 提交于 2019-12-04 23:15:42
计算机信息查看-. import platform import platform def TestPlatform(): print("---------SYSTEM INFO--------") #获取Python版本 3.7.1 print(platform.python_version()) #获取Python版本 v3.7.1 print(platform.python_branch()) #获取操作系统可执行程序的结构 (’32bit’, ‘WindowsPE’) print(platform.architecture()) # 计算机的名称 DESKTOP-90JE76G print(platform.node()) # 获取操作系统名称及版本号，Windows-7-6.1.7601-SP1 print(platform.platform()) # 计算机处理器信息， Intel64 Family 6 Model 158 Stepping 10, GenuineIntel print(platform.processor()) # 获取操作系统中Python的构建日期 ('v3.7.1:260ec2c36a', 'Oct 20 2018 14:57:15') print(platform.python_build()) # 获取系统中python解释器的信息 MSC

TCP and UDP Socket Server on a WAN

由 醉酒当歌 提交于 2019-12-04 09:45:04
问题 I am attempting to create a server and client that utilizes both TCP and UDP. The server works very well in a LAN setting but the UDP messages are not being received when transmitted over a WAN. I believe it is because the UDP socket used to send the data is not remaining in the NAT tables long enough to return any information. Is there a way to either make the UDP port stay open in the router (without port forwarding) or use the same port for UDP as the already connected TCP connection?

Get my WAN IP address

由 我怕爱的太早我们不能终老 提交于 2019-12-03 20:44:43
How can i go about programaticaly getting the IP address of my network as seen from the Internet? Its obviously a property that my router has access to when it connects to the ISP. Is there any way to get this info from a router using a standard protocol. My only other option is to either find a WS which returns my IP address (suprisingly difficult to do), or just go to something like whatismyip.com and strip out all the HTML (very dirty and susceptable to change). Is there any other way??? Don't scrape whatismyip.com, see here for how you can call their API which just returns your address. If
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