variable-assignment

问题 For our Code Igniter application we are loading all of our javascript just before the closing body tag. so in our controllers we have $this->load->view('head', $this->head); $this->load->view('main_view_for_controller', $data); $this->load->view('foot', $this->foot); And in the foot view we have a bunch of <script src="master.js"></script> tags. These include jQuery jQuery-ui shared-functions Now this works great, until you think about JS used only on specific pages, or inline js. You can't

问题 In Python, is there a way to make a, b, c, d, e = 'dog' so that a = 'dog' b = 'dog' #etc. or a, b, c, d, e = list() so that type(a through e) returns type 'list' 回答1: This has already been answered here: Set multiple variables to the same value in Javascript in python it would be: a = b = c = d = e = 'dog' its the same in javascript but with 'var' at the beginning: var a = b = c = d = e = 'dog' 回答2: In c# in would be as simple as declaring the variables and then setting them all equal. string

问题 Using python, one can set an attribute of a instance via either of the two methods below: >>> class Foo(object): pass >>> a = Foo() >>> a.x = 1 >>> a.x 1 >>> setattr(a, 'b', 2) >>> a.b 2 One can also assign properties via the property decorator. >>> class Bar(object): @property def x(self): return 0 >>> a = Bar() >>> a.x 0 My question is, how can I assign a property to an instance? My intuition was to try something like this... >>> class Doo(object): pass >>> a = Doo() >>> def k(): return 0 >

问题 I'm confused about '=' operator, and tf.identity() , I thought '=' is to just make a reference of the tensor, and identity is to make a copy, e.g., with ref = x ref = ref*0 sess.run(x) I will get x all been set to 0 element-wise, and with copy = tf.identity(x) copy = ref*0 sess.run(x) x would not be changed, since identity make copy, not a reference, but with experiment, '=' also make a copy and x is not set to 0, so what's the difference? 回答1: The difference is only in tensorlfow graph

问题 Is it possible to use destructuring assignment in a JavaScript class' constructor to assign the instance variables similar to how you can do it to normal variables? The following example works: var options = {one: 1, two: 2}; var {one, two} = options; console.log(one) //=> 1 console.log(two) //=> 2 But I cannot get something like the following to work: class Foo { constructor(options) { {this.one, this.two} = options; // This doesn't parse correctly and wrapping in parentheses doesn't help }

问题 This question already has answers here : When I change a parameter inside a function, does it change for the caller, too? (4 answers) Closed 5 years ago . I've been having a problem in c++ where I call a function which assigns some values to things, but those assignments are lost after the function has been completed. Here is my code: #include <iostream> #include <string> using namespace std; void Input(string a, string b){ cout << "Input a: \n"; cin >> a; cout << endl; cout << "Input b: \n";

问题 This question already has answers here : When I change a parameter inside a function, does it change for the caller, too? (4 answers) Closed 5 years ago . I've been having a problem in c++ where I call a function which assigns some values to things, but those assignments are lost after the function has been completed. Here is my code: #include <iostream> #include <string> using namespace std; void Input(string a, string b){ cout << "Input a: \n"; cin >> a; cout << endl; cout << "Input b: \n";

问题 In C#, can someone help me assign multiple string arrays to a 2d string array? Here is my code: string[] test1 = new string[5] { "one", "two", "three", "four", "five" }; string[] test2 = new string[5] { "one", "two", "three", "four", "five" }; string[] test3 = new string[5] { "one", "two", "three", "four", "five" }; string[] test4 = new string[5] { "one", "two", "three", "four", "five" }; string[,] allTestStrings = new string [4, 5]; allTestStrings[0] = test1; allTestStrings[1] = test2;

问题 This question already has answers here : Logical Operators in C (8 answers) Closed 7 years ago . main( ) { int i = 4, j = -1, k = 0, w, x, y, z ; w = i || j || k ; x = i && j && k ; y = i || j && k ; z = i && j || k ; printf ( "\nw = %d x = %d y = %d z = %d", w, x, y, z ) ; } I'm just learning C and I came across this code. I honestly dont know what w, x, y and z are assigned to. Apparently the output is as follows: w = 1 x = 0 y = 1 z = 1 How is 'w' equal to 1? I dont get it. 回答1: || is the

问题 This question already has answers here : Logical Operators in C (8 answers) Closed 7 years ago . main( ) { int i = 4, j = -1, k = 0, w, x, y, z ; w = i || j || k ; x = i && j && k ; y = i || j && k ; z = i && j || k ; printf ( "\nw = %d x = %d y = %d z = %d", w, x, y, z ) ; } I'm just learning C and I came across this code. I honestly dont know what w, x, y and z are assigned to. Apparently the output is as follows: w = 1 x = 0 y = 1 z = 1 How is 'w' equal to 1? I dont get it. 回答1: || is the