usertype

Hibernate doesn't support accessing fields on usertypes for projection criterias?

由 流过昼夜 提交于 2019-12-23 20:34:16
问题 My Classes: public class User { @Type(type="AccountType") private AccountType accountType; } public class AccountType { private String name; private AccountType(String name) { this.name = name; } public static AccountType User = new AccountType("User"); public static AccountType Administrator = new AccountType("Administrator"); } I also have a properly setup AccountTypeUserType. My Query: List results = session.createCriteria(User.class) .setProjection(Projections.projectionList() .add

NHibernate property mapping: columns and formula

由 若如初见. 提交于 2019-12-23 18:34:09
问题 When i map columns from the inspected table, i do this: <property name="InstanceName" type="MyNameUserType, MyApp.MyNamespace"> <column name="Name"/> <column name="Name2"/> </property> How can I make property mapping initialize a UserType with data retrieved by the formula's sql query? <property name="InstanceName" type="MyNameUserType, MyApp.MyNamespace" formula="(...)"/> fails with an exception "wrong number of columns". Thanks in advance! 回答1: MyUserNameType should be a class level mapping

How to redirect into different page by user type in php and mysql

由 北慕城南 提交于 2019-12-23 00:49:43
问题 I want to redirect the users from the same log-in page. folder structure... root | --------/application/app.php <---------- for normal user | --------/administration/admin.php <------- for admin user | -------- index.php (Log-in page) User Table ID USER_NAME PASSWORD USER_TYPE 1 admin pass@admin admin 2 user pass@user user If the login user's user type is admin then he/she will be redirected to /administration/admin.php else /application/app.php . How can I do it ? Regards, 回答1: After

Best way to implement a Hibernate UserType after deprecations?

由 不想你离开。 提交于 2019-12-19 05:14:43
问题 I recently got the latest version of Hibernate and noticed that my UserTypes now have warnings about AbstractStandardBasicType's nullSafeGet(ResultSet,String) and nullSafeSet(PreparedStatement,T,int) methods being deprecated in favor of their corresponding methods that take a SessionImplementor argument. The problem is that when you implement a UserType, the SessionImplementor doesn't get passed to you the way that is does in BasicType, CompositeUserType, etc. I checked the Hibernate manual

NHibernate mapping: UserTypes with many-to-one

由 独自空忆成欢 提交于 2019-12-12 10:11:43
问题 New to NHibernate and learning it as we are modifying an existing solution to use this ORM. Ideally, the storage structure and object classes need to stay the same, so Ive come across one or two mapping problems. One class 'Money' has a value and currency. The value is a double and the currency is a foreign key to a list table of currencies. Money can appear as a type on many objects/tables, so Ive created a CompositeUserType to map it along with a standard mapping to currency. This works

Hibernate/JPA/HSQL : How to create a Dialect mapping for User Type ARRAY

由 守給你的承諾、 提交于 2019-12-10 11:38:54
问题 I have successfully created User Types with Postgres, and can read and write successfully. @org.hibernate.annotations.Type(type = "com.xxx.datamodel.ext.FooType" ) @Column(name = "foo", nullable = false) private int[] foo @org.hibernate.annotations.Type(type = "com.xxx.datamodel.ext.BarType" ) @Column(name = "bar", nullable = false) private double[] bar However, when I try to use the HSQLDialect (for unit testing) I get: Caused by: org.hibernate.MappingException: No Dialect mapping for JDBC

nhibernate : read write list of string

由 青春壹個敷衍的年華 提交于 2019-12-10 10:57:16
问题 I know I can read write list of string like below using nhibernate HasMany(x => x.Attachments) .KeyColumn("RowId") .Table("PostTable").Element("PostKey"); But this creates an extra table, is there a way e.g. UserType or something else, so that we can directly write to list... if yes any example of custom UserType using nhibernate?? with sample code... I also want that If i add value to list that also should be saved. I have seen below example code which breaks in case we add value to list...

Hibernate Entities from Multiple Databases

由 我只是一个虾纸丫 提交于 2019-12-10 02:29:08
问题 Our data model is separated into schemas on two databases. The schemas are used in isolation except for a few single-key relationships that bridge between the two. There are no write transactions that will span both databases. Similar to this question Doing a join over 2 tables in different databases using Hibernate, we want to use Hibernate to handle joining the entities. We cannot use the database solution (Federated views on DB2). We have set up Hibernate with two separate database

Hibernate/JPA/HSQL : How to create a Dialect mapping for User Type ARRAY

由 六眼飞鱼酱① 提交于 2019-12-09 07:39:26
I have successfully created User Types with Postgres, and can read and write successfully. @org.hibernate.annotations.Type(type = "com.xxx.datamodel.ext.FooType" ) @Column(name = "foo", nullable = false) private int[] foo @org.hibernate.annotations.Type(type = "com.xxx.datamodel.ext.BarType" ) @Column(name = "bar", nullable = false) private double[] bar However, when I try to use the HSQLDialect (for unit testing) I get: Caused by: org.hibernate.MappingException: No Dialect mapping for JDBC type: 2003 at org.hibernate.dialect.TypeNames.get(TypeNames.java:79) at org.hibernate.dialect.TypeNames

When UserType represents Set of Objects in single line. How to query Hibernate custom UserType with like criteria?

由 五迷三道 提交于 2019-12-08 14:06:59
问题 We are using custom Hibernate UserType to store a Set of Strings in a single line. When trying to Query this set with like criteria, using JPA CriteriaBuilder Hibernate throws IllegalArgumentException Parameter value String did not match expected type java.util.Set Is there a workaround for this? Here is a UserType we are using: public class SetStringType implements UserType, LiteralType<Set<String>> { final private static String SEPARATOR = "|"; final private static String SEPARATOR_REGEXP =
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