urlparse

来源： https://stackoverflow.com/questions/53048792/equivalent-urllib-parse-unquote-in-python-2-7

问题 I recently started working on a project using just vim as my text editor with a virtualenv setup. I installed a few API's on this virtualenv from GitHub. Eventually, the project got a little bigger than vim could handle so I had to move the project to an IDE. I chose Aptana Studio 3. When I started up Aptana, I pointed the project directory to the virtualenv folder that I had created to house my project. I then pointed the interpreter at the Python executable in App/bin (created from

问题 I recently started working on a project using just vim as my text editor with a virtualenv setup. I installed a few API's on this virtualenv from GitHub. Eventually, the project got a little bigger than vim could handle so I had to move the project to an IDE. I chose Aptana Studio 3. When I started up Aptana, I pointed the project directory to the virtualenv folder that I had created to house my project. I then pointed the interpreter at the Python executable in App/bin (created from

问题 I have a huge list of urls that are all like this: http://www.example.com/site/section1/VAR1/VAR2 Where VAR1 and VAR2 are the dynamic elements of the url. What I want to do is to extract from this url string only the VAR1. I've tried to use urlparse but the output look like this: ParseResult(scheme='http', netloc='www.example.com', path='/site/section1/VAR1/VAR2', params='', query='', fragment='') 回答1: Alternatively, you can apply the split() method: >>> url = "http://www.example.com/site

问题 I'm parsing a url in Python, below you can find a sample url and the code, what i want to do is splitting the (74743) from the url and make a for loop which will be taking it from a parts list. Tried to use urlparse but couldn't complete it to the end mostly because of the changing parts in the url. Ijust want the easiest and fastest way to do this. Sample url: http://example.com/wps/portal/lYuxDoIwGAYf6f9aqKSjMNQ/?PartNo=74743&IntNumberOf=&is= (http://example.com/wps/portal) Always fixed

问题 I am attempting to run my own scrapy project. The code is based off a well written book and the author provides a great VM playground to run scripts exampled in the book. In the VM the code works fine. However, in an attempt to practice on my own, I received the following error: File "(frozen importlib._bootstrap)", line 978, in _gcd_import File "(frozen importlib._bootstrap)", line 961, in _find_and_load File "(frozen importlib._bootstrap)", line 950, in _find_and_load_unlocked File "(frozen

问题 My application creates custom URIs (or URLs?) to identify objects and resolve them. The problem is that Python's urlparse module refuses to parse unknown URL schemes like it parses http. If I do not adjust urlparse's uses_* lists I get this: >>> urlparse.urlparse("qqqq://base/id#hint") ('qqqq', '', '//base/id#hint', '', '', '') >>> urlparse.urlparse("http://base/id#hint") ('http', 'base', '/id', '', '', 'hint') Here is what I do, and I wonder if there is a better way to do it: import urlparse

问题 I want to parse query part from url, this is my code to do this: >>> from urlparse import urlparse, parse_qs >>> url = '/?param1&param2=2' >>> parse_qs(urlparse(url).query) >>> {'param2': ['23']} This code looks good, but "parse_qs" method loses query parameters like "param1" or "param1=". Can I parse query part with stantard library and save all parameters? 回答1: You want: from urlparse import parse_qs, urlparse parse_qs(urlparse(url).query, keep_blank_values=True) # {'param2': ['2'], 'param1

问题 I am new to groovy scripting and looking on to parse the URL and print it's parameter. This url is : https://www.google.com/?aaa=111&bbb=222&ccc=33&dd=1484088989_b23f248ac6e5d9a9b47475526bb92ee1 How can i fetch dd parameter from the URL? I appreciate your help! 回答1: You need to add a groovy script. def groovyUtils = new com.eviware.soapui.support.GroovyUtils( context ); def testCase = context.testCase; def testStep = testCase.getTestStepByName("NAME_TESTStepRequest"); def endpoint =testStep

问题 I am working on an app which needs to parse URLs (mostly HTTP URLs) in HTML pages - I have no control over the input and some of it is, as expected, a bit messy. One problem I'm encountering frequently is that urlparse is very strict (and possibly even buggy?) when it comes to parsing and joining URLs that have double-slashes in the path part, for example: testUrl = 'http://www.example.com//path?foo=bar' urlparse.urljoin(testUrl, urlparse.urlparse(testUrl).path) Instead of the expected result