unzip

What is the fastest way to extract 1 file from a zip file which contain a lot of file?

由 爷，独闯天下 提交于 2019-12-20 09:38:41
问题 I tried the java.util.zip package, it is too slow. Then I found LZMA SDK and 7z jbinding but they are also lacking something. The LZMA SDK does not provide a kind of documentation/tutorial of how-to-use, it is very frustrating. No javadoc. While the 7z jbinding does not provide a simple way to extract only 1 file, however, it only provide way to extract all the content of the zip file. Moreover, it does not provide a way to specify a location to place the unzipped file. Any idea please??? 回答1

zip and unzip in java

由 对着背影说爱祢 提交于 2019-12-20 07:54:36
问题 I know that it is an easy task, but after changing my code it stopped working and I can't get it back! I use two functions to zip and unzip, even though what it actually does is "jar" and "unjar", but that shouldn't make a huge difference public static void zipit(File[] infiles, JarOutputStream jos) throws Exception { zipit(infiles,"", jos); } public static void zipit(File[] infiles, String root, JarOutputStream jos) throws Exception { byte[] buffer = new byte[4096]; for(int i=0; i<infiles

How to unzip all the password protected zip files in a directory using Java

由 牧云@^-^@ 提交于 2019-12-20 07:25:31
问题 I am new to java and trying to write an program which will unzip all the password protected zip files in an directory, I am able to unzip all the normal zip files (Without password) but I am not sure how to unzip password protected files. Note: All zip files have same password import java.io.OutputStream; import java.nio.file.Files; import java.nio.file.Path; import java.nio.file.PathMatcher; import java.nio.file.Paths; import java.util.List; import java.util.stream.Stream; import java.util

Zip and Unzip file

由 穿精又带淫゛_ 提交于 2019-12-20 04:35:08
问题 I'm working on a project that needed to unzip file and store in a specific folder. But the problem is, I don't know how to do it. It is my first time to work on this kind of project. I'm using visual studio 2010. And I'm not gonna use any third party applications. Can anyone suggest how could I do this? i've tried this code but the ZIPFILE is not recognizable. It has a red line on it. using System; using System.IO; using System.IO.Compression; namespace UnzipFile { /// <summary> ///

ZLib Inflate() failing with -3 Z_DATA_ERROR

由 ╄→гoц情女王★ 提交于 2019-12-19 16:51:03
问题 I am trying to unzip a file by calling the inflate function but it always fails with Z_DATA_ERROR even when I use the example program from the website. I am thinking that maybe the zip file I have is not supported. I have attached a picture of the zip header below. And here is the function that I wrote to perform the unzipping. I read in the whole file at once (about 34KB) and pass it into this function. Note I have tried passing the whole zip file with the zip header as well as skipping over

Linux下使用FastDFS

由 醉酒当歌 提交于 2019-12-19 09:56:43
本教程所有操作均在CentOS 6.x环境下进行。 将课前资料中的所需文件，上传到/usr/local/leyou目录下： 1.1.单节点FastDFS 整个安装过程非常复杂，很容易出错，建议进行多次备份。 我们这里不打算安装多台虚拟机，因此会把tracker和storage都安装在一起。 1.1.1.安装gcc GCC用来对C语言代码进行编译运行，使用yum命令安装： yum -y install gcc 后面会用到解压命令（unzip），所以这里可以用yum把unzip 也装一下 yum install -y unzip zip 1.1.2.安装libevent yum -y install libevent 1.1.3.安装libfastcommon-master 解压刚刚上传的libfastcommon-master.zip unzip libfastcommon-master.zip 进入解压完成的目录 cd libfastcommon-master 编译并且安装： ./make.sh ./make.sh install 1.1.4.安装fastdfs tar -zxvf FastDFS_v5.08.tar.gz cd FastDFS ./make.sh ./make.sh install 如果安装成功，会看到/etc/init.d/下看到提供的脚本文件： ll /etc

Is there a library to unzip .Z files using VB.NET?

由 主宰稳场 提交于 2019-12-19 08:13:29
问题 I need to unzip a list of .Z files which will be kept in a folder using Visual Basic.NET. For example, consider that there is a folder like C:\FilesToBeUnzipped . Inside this folder there will some 5 to 6 files with .Z as extension. I need to unzip all these .Z files and save the unzipped files in a folder like C:\UnzippedDataFiles . Is this possible in VB.NET? Is there any free component or class library to achive it? 回答1: I also ran into this issue as well, just needed to decompress a *.Z

How to extract zip file recursively in Python

由 安稳与你 提交于 2019-12-19 05:31:17
问题 I have a zip file which contains three zip files in it like this: zipfile.zip\ dirA.zip\ a dirB.zip\ b dirC.zip\ c I want to extract all the inner zip files that are inside the zip file in directories with these names (dirA, dirB, dirC). Basically, I want to end up with the following schema: output\ dirA\ a dirB\ b dirC\ c I have tried the following: import os, re from zipfile import ZipFile os.makedirs(directory) # where directory is "\output" with ZipFile(self.archive_name, "r") as archive:

How to extract zip file recursively in Python

由 帅比萌擦擦* 提交于 2019-12-19 05:30:17
问题 I have a zip file which contains three zip files in it like this: zipfile.zip\ dirA.zip\ a dirB.zip\ b dirC.zip\ c I want to extract all the inner zip files that are inside the zip file in directories with these names (dirA, dirB, dirC). Basically, I want to end up with the following schema: output\ dirA\ a dirB\ b dirC\ c I have tried the following: import os, re from zipfile import ZipFile os.makedirs(directory) # where directory is "\output" with ZipFile(self.archive_name, "r") as archive:

Unzip file from zip archive of multiple files using ZipFile class

由 那年仲夏 提交于 2019-12-18 17:25:38
问题 I'd like to use the ZipFile class to unzip a file using its name from an archive of multiple files. How can I get the string of the zip file name and directory to pass to the ZipFile constructor? 回答1: You can use the AssetManager and ZipInputStream http://developer.android.com/reference/android/content/res/AssetManager.html ZipInputStream in = null; try { final String zipPath = "data/sample.zip"; // Context.getAssets() in = new ZipInputStream(getAssets().open(zipPath)); for (ZipEntry entry =
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