uint16

I have a basic question. Say I have a Uint16Array and I have number 4 in it. data_16=new Uint16Array([4]); Now I have a length 1 and byteLength 2; how do i convert this to Uint8Array. I do not want to create a new view. data_8 = new Uint8Array(data_16) If I do this I get array length 1 and byteLength 1. This is not what I want. I need to stretch that 16 bit value in 16array into 8 bit values so that 8bit array so it would end up with 2 values int 8 bit array. I can just create a funtion which converts with shif and to all that stuff. But Can it be done with Array manipulation only? You can use

I need to use printf() to print a uint16_t. This SO answer ( How to print uint32_t and uint16_t variables value? ) says I need to use inttypes.h. However, I'm working on an embedded system and inttypes.h is not available. How do I print a uint16_t when the format specifier for a uint16_t is not available? An obvious way is: printf("%u\n", (unsigned int)x); The unsigned int is guaranteed to be at least 16 bits, so this is not a lossy conversion. You should use the style of inttypes.h but define the symbols yourself. For example: #define PRIu8 "hu" #define PRId8 "hd" #define PRIx8 "hx" #define

I'm new on C programming and I'm testing some code where I receive and process an UDP packet formatted as follow: UINT16 port1 UINT16 port2 The corresponding values on this test are: 6005 5555 If I print the whole packet buffer I get something like this: u^W³^U><9e>^D So I thought that I would just have to break it and process as an unsigned int of 16 bytes. So I've tried something like this: int l = 0; unsigned int *primaryPort = *(unsigned int) &buffer[l]; AddToLog(logInfo, "PrimaryPort: %u\n", primaryPort); l += sizeof(primaryPort); unsigned int *secondaryPort = *(unsigned int) &buffer[l];