tuples

问题 lst = [(u'course', u'session'), (u'instructor', u'session'), (u'session', u'trainee'), (u'person', u'trainee'), (u'person', u'instructor'), (u'course', u'instructor')] I've above list of tuple, I need to sort it with following logic.... each tuple's 2nd element is dependent on 1st element, e.g. (course, session) -> session is dependent on course and so on.. I want a sorted list based on priority of their dependency, less or independent object will come first so output should be like below,

问题 lst = [(u'course', u'session'), (u'instructor', u'session'), (u'session', u'trainee'), (u'person', u'trainee'), (u'person', u'instructor'), (u'course', u'instructor')] I've above list of tuple, I need to sort it with following logic.... each tuple's 2nd element is dependent on 1st element, e.g. (course, session) -> session is dependent on course and so on.. I want a sorted list based on priority of their dependency, less or independent object will come first so output should be like below,

问题 lst = [(u'course', u'session'), (u'instructor', u'session'), (u'session', u'trainee'), (u'person', u'trainee'), (u'person', u'instructor'), (u'course', u'instructor')] I've above list of tuple, I need to sort it with following logic.... each tuple's 2nd element is dependent on 1st element, e.g. (course, session) -> session is dependent on course and so on.. I want a sorted list based on priority of their dependency, less or independent object will come first so output should be like below,

问题 I'm looking for the most memory efficient way to solve this problem. I have a list of tuples representing partial string matches in a sentence: [(0, 2), (1, 2), (0, 4), (2,6), (23, 2), (22, 6), (26, 2), (26, 2), (26, 2)] The first value of each tuple is the start position for the match, the second value is the length. The idea is to collapse the list so that only the longest continue string match is reported. In this case it would be: [(0,4), (2,6), (22,6)] I do not want just the longest

问题 I'm looking for the most memory efficient way to solve this problem. I have a list of tuples representing partial string matches in a sentence: [(0, 2), (1, 2), (0, 4), (2,6), (23, 2), (22, 6), (26, 2), (26, 2), (26, 2)] The first value of each tuple is the start position for the match, the second value is the length. The idea is to collapse the list so that only the longest continue string match is reported. In this case it would be: [(0,4), (2,6), (22,6)] I do not want just the longest

问题 I have a class with copy & move ctor deleted. struct A { A(int a):data(a){} ~A(){ std::cout << "~A()" << this << " : " << data << std::endl; } A(A const &obj) = delete; A(A &&obj) = delete; friend std::ostream & operator << ( std::ostream & out , A const & obj); int data; }; And I want to create a tuple with objects of this class. But the following does not compile: auto p = std::tuple<A,A>(A{10},A{20}); On the other hand, the following does compile, but gives a surprising output. int main()

问题 I am fairly new to python, but I haven't been able to find a solution to my problem anywhere. I want to count the occurrences of a string inside a list of tuples. Here is the list of tuples: list1 = [ ('12392', 'some string', 'some other string'), ('12392', 'some new string', 'some other string'), ('7862', None, 'some other string') ] I've tried this but it just prints 0 for entry in list1: print list1.count(entry[0]) As the same ID occurs twice in the list, this should return: 2 1 I also

问题 I am fairly new to python, but I haven't been able to find a solution to my problem anywhere. I want to count the occurrences of a string inside a list of tuples. Here is the list of tuples: list1 = [ ('12392', 'some string', 'some other string'), ('12392', 'some new string', 'some other string'), ('7862', None, 'some other string') ] I've tried this but it just prints 0 for entry in list1: print list1.count(entry[0]) As the same ID occurs twice in the list, this should return: 2 1 I also

问题 I know questions similar to this have been asked many, many times on Stack Overflow, but I need to remove duplicate tuples from a list, but not just if their elements match up, their elements have to be in the same order. In other words, (4,3,5) and (3,4,5) would both be present in the output, while if there were both (3,3,5) and (3,3,5) , only one would be in the output. Specifically, my code is: import itertools x = [1,1,1,2,2,2,3,3,3,4,4,5] y = [] for x in itertools.combinations(x,3): y

问题 I know questions similar to this have been asked many, many times on Stack Overflow, but I need to remove duplicate tuples from a list, but not just if their elements match up, their elements have to be in the same order. In other words, (4,3,5) and (3,4,5) would both be present in the output, while if there were both (3,3,5) and (3,3,5) , only one would be in the output. Specifically, my code is: import itertools x = [1,1,1,2,2,2,3,3,3,4,4,5] y = [] for x in itertools.combinations(x,3): y