transpose

问题 I looked number different solutions online, but count not find what I am trying to achine. Please help me on this. I am using Apache Spark 2.1.0 with Scala. Below is my dataframe: +-----------+-------+ |COLUMN_NAME| VALUE | +-----------+-------+ |col1 | val1 | |col2 | val2 | |col3 | val3 | |col4 | val4 | |col5 | val5 | +-----------+-------+ I want this to be transpose to, as below: +-----+-------+-----+------+-----+ |col1 | col2 |col3 | col4 |col5 | +-----+-------+-----+------+-----+ |val1 |

问题 I have a list of industries with a adjacent list of industries to categorize them. I would like to know which industries are the most common but I don't manage to make Sheets interpret two-word categories as one. First, I would like to know which 5 categories are the most common overall. Also I would like to know the top 5 one-word (black), two-word (red) and three-word (blue) categories. Plus, I would like to get rid of the commas. Here's what I want to achieve and a link to a google sheets

问题 I have a list of industries with a adjacent list of industries to categorize them. I would like to know which industries are the most common but I don't manage to make Sheets interpret two-word categories as one. First, I would like to know which 5 categories are the most common overall. Also I would like to know the top 5 one-word (black), two-word (red) and three-word (blue) categories. Plus, I would like to get rid of the commas. Here's what I want to achieve and a link to a google sheets

问题 I have a square boolean matrix M of size N, stored by rows and I want to count the number of bits set to 1 for each column. For instance for n=4: 1101 0101 0001 1001 M stored as { { 1,1,0,1}, {0,1,0,1}, {0,0,0,1}, {1,0,0,1} }; result = { 2, 2, 0, 4}; I can obviously transpose the matrix M into a matrix M' popcount each row of M'. Good algorithms exist for matrix transposition and popcounting through bit manipulation. My question is: would it be possible to "merge" such algorithms into a

问题 In Oracle SQL query we got 40 records having 13 columns . I want to merge all these records into one column means 40 * 13 = 520 column in 1 record . Eg- Sample table having few records col1 col2 city cntry conti 1 abc NYC USA NA 2 def LON UK EU 3 xyz DUB UAE ASIA then after merge all the records & get into the one record then it should be like the below one- col1 col2 city cntry conti col1 col2 city cntry conti col1 col2 city cntry conti 1 abc NYC USA NA 2 def LON UK EU 3 xyz DUB UAE ASIA 回答1

问题 I'm trying to figure out how to encrypt a columnar transposition cipher in Python given a plaintext uppercase string and a number key of any length. For example, if the key is 3124 and the string is 'IHAVETWOCATS', it would organize the string like so: 3124 IHAV ETWO CATS and then return the characters in column 1 first, then column 2, etc, until finally returning the encrypted string 'HTAAWTIECVOS' . So far I know that I'll need to use an accumulator, and I've been toying with the idea of

问题 Using basic R, I can transpose a dataframe, say mtcars , which has all columns of the same class: as.data.frame(t(mtcars)) Or with pipes: library(magrittr) mtcars %>% t %>% as.data.frame How to accomplish the same within tidyr or tidyverse packages? My attempt below gives: Error: Duplicate identifiers for rows library(tidyverse) mtcars %>% gather(var, value, everything()) %>% spread(var, value) 回答1: Try with add_rownames add_rownames(mtcars) %>% gather(var, value, -rowname) %>% spread(rowname

问题 Using basic R, I can transpose a dataframe, say mtcars , which has all columns of the same class: as.data.frame(t(mtcars)) Or with pipes: library(magrittr) mtcars %>% t %>% as.data.frame How to accomplish the same within tidyr or tidyverse packages? My attempt below gives: Error: Duplicate identifiers for rows library(tidyverse) mtcars %>% gather(var, value, everything()) %>% spread(var, value) 回答1: Try with add_rownames add_rownames(mtcars) %>% gather(var, value, -rowname) %>% spread(rowname

问题 This question already has answers here : Transpose list of lists (10 answers) Closed 6 years ago . I have a 2d list like this: 1 2 3 4 5 6 and I want to make this: 1 4 2 5 3 6 I've tried to do a for loop and switch each value but I keep getting an index out of bound error. Here's what I have: for i in results: for j in range(numCenturies): rotated[i][j] = results [j][i] 回答1: From python documentation on zip function: This function returns a list of tuples, where the i-th tuple contains the i

问题 I have developed a public and open source App for Splunk (Nmon performance monitor for Unix and Linux Systems, see https://apps.splunk.com/app/1753/) A master piece of the App is an old perl (recycled, modified and updated) script automatically launched by the App to convert the Nmon data (which is some kind of custom csv), reading it from stdin and writing out to formerly formatted csv files by section (a section is a performance monitor) I want now to fully rewrite this script in Python,