temporaries

Are all temporaries rvalues in C++?

北城以北 提交于 2019-11-27 19:39:28
I have been coding in C++ for past few years. But there is one question that I have not been able to figure out. I want to ask, are all temporaries in C++, rvalues? If no, can anyone provide me an example where temporary produced in the code is an lvalue ? No. The C++ language specification never makes such a straightforward assertion as the one you are asking about. It doesn't say anywhere in the language standard that "all temporary objects are rvalues". Moreover, the question itself is a bit of misnomer, since the property of being an rvalue in the C++ language is not a property of an

If temporaries are implicitly non-modifiable, how does this work?

我怕爱的太早我们不能终老 提交于 2019-11-27 04:33:19
I'm told that, in C++03, temporaries are implicitly non-modifiable. However, the following compiles for me on GCC 4.3.4 (in C++03 mode): cout << static_cast<stringstream&>(stringstream() << 3).str(); How is this compiling? (I am not talking about the rules regarding temporaries binding to references.) fredoverflow I'm told that, in C++03, temporaries are implicitly non-modifiable. That is not correct. Temporaries are created, among other circumstances, by evaluating rvalues, and there are both non-const rvalues and const rvalues. The value category of an expression and the constness of the

Are all temporaries rvalues in C++?

冷暖自知 提交于 2019-11-26 19:57:11
问题 I have been coding in C++ for past few years. But there is one question that I have not been able to figure out. I want to ask, are all temporaries in C++, rvalues? If no, can anyone provide me an example where temporary produced in the code is an lvalue ? 回答1: No. The C++ language specification never makes such a straightforward assertion as the one you are asking about. It doesn't say anywhere in the language standard that "all temporary objects are rvalues". Moreover, the question itself

If temporaries are implicitly non-modifiable, how does this work?

半城伤御伤魂 提交于 2019-11-26 11:14:51
问题 I\'m told that, in C++03, temporaries are implicitly non-modifiable. However, the following compiles for me on GCC 4.3.4 (in C++03 mode): cout << static_cast<stringstream&>(stringstream() << 3).str(); How is this compiling? (I am not talking about the rules regarding temporaries binding to references.) 回答1: I'm told that, in C++03, temporaries are implicitly non-modifiable. That is not correct. Temporaries are created, among other circumstances, by evaluating rvalues, and there are both non