sum

问题 I have a table with the following structure and sample data: STORE_ID | INS_TIME | TOTAL_AMOUNT 2 07:46:01 20 3 19:20:05 100 4 12:40:21 87 5 09:05:08 5 6 11:30:00 12 6 14:22:07 100 I need to get the hourly sum of TOTAL_AMOUNT for each STORE_ID. I tried the following query but i don't know if it's correct. SELECT STORE_ID, SUM(TOTAL_AMOUNT) , HOUR(INS_TIME) as HOUR FROM VENDAS201302 WHERE MINUTE(INS_TIME) <=59 GROUP BY HOUR,STORE_ID ORDER BY INS_TIME; 回答1: SELECT STORE_ID, HOUR(INS_TIME) as

问题 I have a table with the following structure and sample data: STORE_ID | INS_TIME | TOTAL_AMOUNT 2 07:46:01 20 3 19:20:05 100 4 12:40:21 87 5 09:05:08 5 6 11:30:00 12 6 14:22:07 100 I need to get the hourly sum of TOTAL_AMOUNT for each STORE_ID. I tried the following query but i don't know if it's correct. SELECT STORE_ID, SUM(TOTAL_AMOUNT) , HOUR(INS_TIME) as HOUR FROM VENDAS201302 WHERE MINUTE(INS_TIME) <=59 GROUP BY HOUR,STORE_ID ORDER BY INS_TIME; 回答1: SELECT STORE_ID, HOUR(INS_TIME) as

问题 My apologies for the length of this but I want to explain as fully as possible. I am completely stumped on how to solve this. The Setup: I have two dataframes the first has a list of all possible values in the first column there are no duplicate values in this column. Let's call it df_01. Theses are all the common possible values in each list. All additional columns represent independent lists. Each contains a number that represents how many days any given value of all possible values has

问题 I have a data which have the difference between the start and end time of an event. Now I want to add the difference. the problem is the difference time is in format difference_time _______________ 00:10:00 00:30:12 01:09:09 00:09:03 01:09:30 01:09:03 00:09:08 01:00:09 09:00:01 But if I do sum(df$difference_time) it throws the error that invalid type of arguement. I want the result to be something like below format: 51975 seconds. Any help is appreciated UPDATE: I tried period_to_seconds(hms

问题 I was wondering how you get the sum of multiple arrays within an array of objects. My code is as follows: const employeeList = [ { "name": "Ahmed", "scores": [ "5", "1", "4", "4", "5", "1", "2", "5", "4", "1" ] }, { "name": "Jacob Deming", "scores": [ "4", "2", "5", "1", "3", "2", "2", "1", "3", "2" ] }]; var sum = 0; for(let i = 0; i < employeeList.length; i++){ var eachScore = employeeList[i].scores; const b = eachScore.map(Number); console.log(b); sum += parseInt(b);//this is the code that

问题 I have a table in a dataadapter . I want to get the count and sum of a specific column of it. How is that possible? This is the code for reach to the column, what after that? DataColumn buy_count = myDataSet.Tables["all_saled"].Columns["how_much_buy"] I know that we have sum, count,... in SQL, but how can I do it in C#? 回答1: You can use LINQ to DataSets var sales = myDataSet.Tables["all_saled"].AsEnumerable(); var buy_total = sales.Sum(datarow => datarow.Field<int>("how_much_buy")); Check the

问题 I was using sum function in pyhton, and i am clear about it's general structure sum(iterable, start) , but i am unable to get the logic behind the following code test = sum(5 for i in range(5) ) print("output: ", test) output: 25 Please can anyone describe what is happening here, basically here 5 is getting multiplied with 5, and same pattern is there for every sample input. 回答1: Your code is shorthand for: test = sum((5 for i in range(5))) The removal of extra parentheses is syntactic sugar:

问题 I was using sum function in pyhton, and i am clear about it's general structure sum(iterable, start) , but i am unable to get the logic behind the following code test = sum(5 for i in range(5) ) print("output: ", test) output: 25 Please can anyone describe what is happening here, basically here 5 is getting multiplied with 5, and same pattern is there for every sample input. 回答1: Your code is shorthand for: test = sum((5 for i in range(5))) The removal of extra parentheses is syntactic sugar:

问题 I have data in MySQL. The data is created by json datas. But I can't change to array from data keys. I want to set this data in order and according to the number of stock. [ {"size":"36","stock":"1"}, {"size":"37","stock":"2"}, {"size":"38","stock":"1"}, {"size":"40","stock":"1"}, {"size":"36","stock":"1"}, {"size":"37","stock":"3"}, {"size":"38","stock":"2"}, {"size":"39","stock":"3"}, {"size":"40","stock":"2"} ] I want change to: array( '36' => '2', '37' => '5', '38' => '3', '39' => '3',

问题 I need to create a program which calculates the cumulative sum of a dynamically allocated vector and the vector should be filled with random values (not values from stdin) ​​using only pointers . I couldn't think of a version that uses only pointers (i'm kinda new to this matter). This is the code I have so far: #include <stdio.h> #include <malloc.h> int main() { int i, n, sum = 0; int *a; printf("Define size of your array A \n"); scanf("%d", &n); a = (int *)malloc(n * sizeof(int)); printf(