substring

问题 The count() function returns the number of times a substring occurs in a string, but it fails in case of overlapping strings. Let's say my input is: ^_^_^-_- I want to find how many times ^_^ occurs in the string. mystr=input() happy=mystr.count('^_^') sad=mystr.count('-_-') print(happy) print(sad) Output is: 1 1 I am expecting: 2 1 How can I achieve the desired result? 回答1: New Version You can solve this problem without writing any explicit loops using regex. As @abhijith-pk's answer

问题 I want to emphasise the last 3 characters of a string, example: 123456 789 Easy to wrap the last three with <strong> or <span class=""> , but I was wondering if it could be done with CSS only? So the html would be something like: <span class="mytext">123456789</span> With the emphasis added in CSS mytext class? 回答1: Here is a crazy idea using filter and SVG to simulate a bold effect on the last 3 digits. Works only on chrome .mytext { display: inline-block; margin: 10px; font-size: 50px; font

问题 I'm new in XSL programming and I guess it is a simple question: How can I get the filename without the path? At the moment my code looks like this and I get the whole path: Result.xml: <?xml version="1.0" encoding="UTF-8" ?> <All_Results> <Result> <id>1</id> <workid>144</workid> <rank>100000000</rank> <title>Test Dokument</title> <author_multival>Test</author_multival> <author>Test</author> <size>34185</size> <url>https://test.test.com/docs/globalit/Lists/Documents/Datumtest/Test.docx</url>

问题 I'm new in XSL programming and I guess it is a simple question: How can I get the filename without the path? At the moment my code looks like this and I get the whole path: Result.xml: <?xml version="1.0" encoding="UTF-8" ?> <All_Results> <Result> <id>1</id> <workid>144</workid> <rank>100000000</rank> <title>Test Dokument</title> <author_multival>Test</author_multival> <author>Test</author> <size>34185</size> <url>https://test.test.com/docs/globalit/Lists/Documents/Datumtest/Test.docx</url>

问题 I would like to return new table in ORACLE where all rows that have same the values in 'col' columns group together and the 'description' column will contain only the mutual sub strings when the different characters will replaced by '...' how can I do that? May i get your help please? Basic code to start with: SELECT col,description FROM table group by col; Example 1: col description 1 Today is 1 Today is a good day 1 Today is perfect day 2 Hello world 2 Hello results: col description 1 Today

问题 This code I'm using is from this previously asked question. This question has been asked and answered plenty of times but I'm specifically asking for the order to be listed by size from largest to smallest. public static void main(String[] args) { String inputedWord = "ABIGWORD"; for (String str : breakStringIntoPieces(inputedWord, 2)) { System.out.print("\n") + str; } } //Pass in word and minimum //substring length to print public static List<String> breakStringIntoAllPossibleSubstrings

问题 I have a string: myString = "mystring" I would simply like to get the first 5 characters which is the easiest way to do that in Swift? 回答1: Correct answer from Choppin, but if you want to do it in the pure swift way (without casting to NS String : myString = myString.substringToIndex(advance(myString.startIndex, 5)) 回答2: let substring: String = (myString as NSString).substringToIndex(5) 回答3: Use these extensions: Swift 2.3 extension String { func substringFromIndex(index: Int) -> String { if

问题 I have a string: myString = "mystring" I would simply like to get the first 5 characters which is the easiest way to do that in Swift? 回答1: Correct answer from Choppin, but if you want to do it in the pure swift way (without casting to NS String : myString = myString.substringToIndex(advance(myString.startIndex, 5)) 回答2: let substring: String = (myString as NSString).substringToIndex(5) 回答3: Use these extensions: Swift 2.3 extension String { func substringFromIndex(index: Int) -> String { if

问题 I need to check a short string for matches with a list of substrings. Currently, I do this like shown below (working code on ideone) bool ContainsMyWords(const std::wstring& input) { if (std::wstring::npos != input.find(L"white")) return true; if (std::wstring::npos != input.find(L"black")) return true; if (std::wstring::npos != input.find(L"green")) return true; // ... return false; } int main() { std::wstring input1 = L"any text goes here"; std::wstring input2 = L"any text goes here black";

问题 How to remove the last two characters of String in MongoDB? I have tried below solution but it did not work. $substr: [ "$document.field", 0, { $strLenCP: "$document.field" } - 2 ] 回答1: You have to use $add or $subrtract to evaluate the length of a new string: db.collection.aggregate([ { $project: { newStr: { $substr: [ "$document.field", 0, { $add: [ { $strLenCP: "$document.field" }, -2 ] } ] } } } ]) MongoDB Playground 来源： https://stackoverflow.com/questions/56537076/mongodb-remove-last-two