str-replace

Best way to remove '\xad' in Python?

风格不统一 提交于 2020-07-20 09:15:10
问题 I'm trying to build a corpus from the .txt file found at this link. I believe the instances of \xad are supposedly 'soft-hyphens', but do not appear to be read correctly under UTF-8 encoding. I've tried encoding the .txt file as iso8859-15 , using the code: with open('Harry Potter 3 - The Prisoner Of Azkaban.txt', 'r', encoding='iso8859-15') as myfile: data=myfile.read().replace('\n', '') data2 = data.split(' ') This returns an array of 'words', but '\xad' remains attached to many entries in

Best way to remove '\xad' in Python?

元气小坏坏 提交于 2020-07-20 09:13:39
问题 I'm trying to build a corpus from the .txt file found at this link. I believe the instances of \xad are supposedly 'soft-hyphens', but do not appear to be read correctly under UTF-8 encoding. I've tried encoding the .txt file as iso8859-15 , using the code: with open('Harry Potter 3 - The Prisoner Of Azkaban.txt', 'r', encoding='iso8859-15') as myfile: data=myfile.read().replace('\n', '') data2 = data.split(' ') This returns an array of 'words', but '\xad' remains attached to many entries in

Best way to remove '\xad' in Python?

你。 提交于 2020-07-20 09:13:18
问题 I'm trying to build a corpus from the .txt file found at this link. I believe the instances of \xad are supposedly 'soft-hyphens', but do not appear to be read correctly under UTF-8 encoding. I've tried encoding the .txt file as iso8859-15 , using the code: with open('Harry Potter 3 - The Prisoner Of Azkaban.txt', 'r', encoding='iso8859-15') as myfile: data=myfile.read().replace('\n', '') data2 = data.split(' ') This returns an array of 'words', but '\xad' remains attached to many entries in

Replace multiple words in R easily; str_replace_all gives error that two objects are not equal lengths

瘦欲@ 提交于 2020-07-19 06:20:21
问题 I'm trying to use str_replace_all to replace many different values (i.e. "Mod", "M2", "M3", "Interviewer") with one the consistent string (i.e. "Moderator:"). I'm doing this with multiple different categories, and I want avoid having to write each unique value out as there are a lot. So I made a tibble consisting of all the unique values that I want to make standardized and read it in and then pulled out each column (there are 5 but only 2 shown for simplicity) to make them into vectors:

Remove white spaces from string between comma and any letter

蓝咒 提交于 2020-06-22 12:59:50
问题 I use RegExp and "string".match very rarely so I'm not so sure how to use them for some little bit complex things.Here's what I would like to do and don't know how to do it. Here I have a string in javascript. var str= " I would like to know how to use RegExp , string.match and string.replace" I would like to delete all white spaces BETWEEN comma and any letter.So after that this string will look like this. str= " I would like to know how to use RegExp,string.match and string.replace" I only

Replace only the first character of a string with str_replace?

ⅰ亾dé卋堺 提交于 2020-06-08 17:23:19
问题 I'm trying to replace only the first character of a string, but it isn't working, it replaces all the "0" on the string, here's my code: $mes2 = str_replace('0', '', $mes[0]); I want to replace the first character only if its a 0, example: 07 becomes 7 I don't want to replace all the time, example: 11 becomes 1, i don't want it. I also tried this way, but it didn't work the way i want, because it's replacing also the second character if it's 0, like 10 becomes 1. $mes2 = preg_replace('/0/', '

Replace only the first character of a string with str_replace?

◇◆丶佛笑我妖孽 提交于 2020-06-08 17:23:12
问题 I'm trying to replace only the first character of a string, but it isn't working, it replaces all the "0" on the string, here's my code: $mes2 = str_replace('0', '', $mes[0]); I want to replace the first character only if its a 0, example: 07 becomes 7 I don't want to replace all the time, example: 11 becomes 1, i don't want it. I also tried this way, but it didn't work the way i want, because it's replacing also the second character if it's 0, like 10 becomes 1. $mes2 = preg_replace('/0/', '