问题
I'm trying to replace only the first character of a string, but it isn't working, it replaces all the "0" on the string, here's my code:
$mes2 = str_replace('0', '', $mes[0]);
I want to replace the first character only if its a 0, example:
07 becomes 7
I don't want to replace all the time, example:
11 becomes 1, i don't want it.
I also tried this way, but it didn't work the way i want, because it's replacing also the second character if it's 0, like 10 becomes 1.
$mes2 = preg_replace('/0/', '', $mes, 1);
回答1:
OK, based on refinements to your question, what you probably want is ltrim
.
$out = ltrim($in, "0");
This will strip all leading zeroes from $in
. It won't remove zeroes from anywhere else, and it won't remove anything other than zeroes. Be careful; if you give it "000" you'll get back "" instead of "0".
You could use typecasting instead, as long as $in
is always a number (or you want it to result in 0 if it isn't):
$out = (int) $in;
- 007 becomes 7
- 000 becomes 0
- 100 stays as 100
- 456 stays as 456
- 00a becomes 0
- 56a becomes 0
- ab4 becomes 0
- -007 becomes -7
...etc.
Now, in the unlikely event that you only want to replace the first 0, so for example "007" becomes "07", then your latest attempt mentioned in your question is almost there. You just need to add a "caret" character to make sure it only matches the start of the string:
$out = preg_replace('/^0/', '', $in);
回答2:
$str = '1ere is the solution';
echo preg_replace('/1/', 'h', $str, 1); // outputs 'here is the solution'
回答3:
Use substr
:
$mes2 = substr($mes, 1);
This will remove the first character, which is what it looks like you're trying to achieve. If you want to replace it with something, use this:
$mes2 = $new_char . substr($mes, 1);
Edit
I may have misread your question - if $mes[0]
is the original string, use $mes[0]
in place of $mes
above.
回答4:
Strings in PHP can be accessed just like array
<?php
$var = "test";
$var[0] = "1";
var_dump($var);
?>
Will output string(4) "1est"
回答5:
You may simple use $mes[0] = '';
or if you need specific substitution something like $mes[0] = $mes[0] == '<replaced character>' ? '' : $mes[0];
回答6:
My long approach:
$first_letter = substr($mes[0], 0, 1);
$rest = substr($mes[0], 1);
$mes2 = str_replace('0', '', $first_letter);
$result = $mes2.$rest;
Or shorter:
$result = str_replace('0', '', substr($mes[0], 0, 1)).substr($mes[0], 1);
回答7:
This is how I would have done it:
$mes2 = substr_replace($mes[0],'',strpos($mes[0], '0'),1);
回答8:
You could do that like this:
$mes2 = "07 test subject";
if($mes2['0']=='0') { $mes2['0']=''; }
echo $mes2;
This will output:
7 test subject
来源:https://stackoverflow.com/questions/33927140/replace-only-the-first-character-of-a-string-with-str-replace