ssid

How to get SSID and RSSI for Win7 using C#

妖精的绣舞 提交于 2019-12-30 09:55:07
问题 I am very new to Win7 and WMI. Please advice me where to see for active access point from WiFi and how to get ssid/rssi for each access point. I have use: ManagementClass mc = new ManagementClass("root\\WMI", "MSNdis_80211_ServiceSetIdentifier", null); ManagementObjectSearcher searcher1 = new ManagementObjectSearcher(@"root\wmi","SELECT * FROM MSNdis_80211_BSSIList"); but I got 0 results. Is this class support Win7? Anybody can help? 回答1: I had a similar problem where I needed to get the SSID

How to get my wifi hotspot ssid in my current android system

耗尽温柔 提交于 2019-12-28 10:05:17
问题 I have a problem that I couldn't find my wifi hotspot ssid in my Android system. I found many information from google, but nothing helpful. Please help me to solve it. 回答1: You can use WifiManager and WifiInfo for getting Wifi SSID WifiManager wifiManager = (WifiManager) getSystemService(WIFI_SERVICE); WifiInfo wifiInfo = wifiManager.getConnectionInfo(); Log.d("wifiInfo", wifiInfo.toString()); Log.d("SSID",wifiInfo.getSSID()); Also add Permission in your Manifest file. <uses-permission

How to find a list of wireless networks (SSID's) in Java, C#, and/or C?

牧云@^-^@ 提交于 2019-12-28 04:58:04
问题 Is there a toolkit/package that is available that I could use to find a list of wireless networks (SSID's) that are available in either Java, C#, or C for Windows XP+? Any sample code would be appreciated. 回答1: For C#, take a look at the Managed Wifi API, which is a wrapper for the Native Wifi API provided with Windows XP SP2 and later. I have not tested this code, but looking at the Managed Wifi API sample code, this should list the available SSIDs. WlanClient client = new WlanClient();

How connect Android to no SSID public and no Password requered

百般思念 提交于 2019-12-25 05:36:13
问题 i can't connect Android on SSID established, i try WifiConfiguration but unsucessfull, my ssid is open (without password). In Android UI i can connect, but on code i can't. Anybody help me? Tankyou. EDIT: my code: String networkSSID = "DL63.0.0.0.1"; String networkPass = ""; WifiConfiguration conf = new WifiConfiguration(); conf.SSID = "\"" + networkSSID + "\""; // conf.wepKeys[0] = "\"" + networkPass + "\""; // conf.wepTxKeyIndex = 0; conf.allowedKeyManagement.set(WifiConfiguration.KeyMgmt

a connection cannot be made to redirector. Ensure that 'sql browser' service is running

狂风中的少年 提交于 2019-12-23 20:25:50
问题 So Im trying this sql server 2012, and I cant open any ssis package due to this error a connection cannot be made to redirector. Ensure that 'sql browser' service is running my Sql Browser is running for sure, I tried changing it under local service, local system and network, still no result yet, any help would be appreciated Thanks 回答1: This error seems to related only to named instances. The reason is SQL client is not able to resolve instance because SQL client has no access SQL Browser

failed to connect to specific WiFi in android programmatically

北城余情 提交于 2019-12-23 15:49:08
问题 I'm using the following code to detect and connect to specific WiFi ssid when I press a button in android. Below is the code. Any help will be appreciated. ssid :- "myHotspot" & password:- "12345678" Button b1 = (Button) findViewById(R.id.button); <br> b1.setOnClickListener(new View.OnClickListener() { <br><br>@Override <br>public void onClick(View v) { wifiConfiguration.SSID = "\"myHotspot\""; wifiConfiguration.preSharedKey ="\"12345678\""; WifiManager wifiManager = (WifiManager)

duplicate SSID in scanning wifi result

旧时模样 提交于 2019-12-21 20:09:56
问题 i'm trying to make an app that can create a list of available wifi access point. here's part of the code i used: x = new BroadcastReceiver() { @Override public void onReceive(Context c, Intent intent) { results = wifi.getScanResults(); size = results.size(); if (results != null) { for (int i=0; i<size; i++){ ScanResult scanresult = wifi.getScanResults().get(i); String ssid = scanresult.SSID; int rssi = scanresult.level; String rssiString = String.valueOf(rssi); textStatus.append(ssid + "," +

On Oreo (8.1.0) not getting the correct Wifi SSID. It's showing <unknown ssid> though it is connected to a wifi with SSID

你。 提交于 2019-12-21 08:22:16
问题 I need to check the current connected wifi SSID on android. I checked with Nokia 6 and OnePlus 5 with respectively Oreo 8.1.0 and Oreo 8.0. Other phones with different OS version is working fine with this code. Is there anything wrong with my code? private WifiInfo wifiInfo; private String ssid = ""; private WifiManager wifiManager; private boolean getWifiStatus() { wifiManager= (WifiManager) context.getSystemService(Context.WIFI_SERVICE); wifiInfo = wifiManager.getConnectionInfo(); ssid = ""

Jelly Bean Issue - wifiManager.getConnectionInfo().getSSID() - extra “”

落爺英雄遲暮 提交于 2019-12-20 10:23:59
问题 Hi all bug reporting for your information. link Problem details : The Code - wifiManager.getConnectionInfo().getSSID() The above code to returns the current SSID, it is returning the current SSID with extra quotations around it. For eg. the SSID internet is returned as "internet" . This is only seen on Jelly bean 4.2 using device Nexus 7. This bug is causing errors in our app as we compare the current SSID with the SSID that we are trying to connect too. The code wifiManager.getScanResults();

WlanOpenHandle fails with error code 1062

江枫思渺然 提交于 2019-12-19 10:41:21
问题 I am using the native Wifi Api to fetch the ssid on windows 8 machine but the "WlanOpenHandle" call always fails with the error code 1062. Any help? Note: there is no wzc service on windows 8. 回答1: As confirmed by the OP, the proximate cause of the error was that the service "WLAN AutoConfig" was not running. This requirement does not seem to be documented; I've added a note in the community contributions section. 来源: https://stackoverflow.com/questions/37333171/wlanopenhandle-fails-with