square-bracket

Bash double bracket regex comparison using negative lookahead error return 2

怎甘沉沦 提交于 2020-01-24 18:51:30
问题 On Bash 4.1 machine, I'm trying to use " double bracket " [[ expression ]] to do REGEX comparison using " NEGATIVE LOOKAHEAD ". I did " set +H " to disable BASH variable' ! ' expansion to command history search. I want to match to " any string " except " arm-trusted-firmware ". set +H if [[ alsa =~ ^(?!arm-trusted-firmware).* ]]; then echo MATCH; else echo "NOT MATCH"; fi I expect this to print "MATCH" back, but it prints "NOT MATCH". After looking into the return code of "double bracket", it

Overloading multi-dimensional brackets [duplicate]

折月煮酒 提交于 2020-01-22 02:06:07
问题 This question already has answers here : Operator[][] overload (18 answers) Closed 3 years ago . How can I overload multi-dimensional brackets? Let's say that I have a class which enables me to access points in an n -vector space. For example: class NSpaceVector { private: int vectorSpace[8][8][8][8][8][8][8]; public: const NSpaceVector operator[][][][][][][](int i, int j, int k, int l, int m, int n, int p)const {return vectorSpace[i][j][k][l][m][n][p]; } NSpaceVector operator[][][][][][][]

what do the square brakets mean in vb.net in this string

冷暖自知 提交于 2020-01-15 11:54:42
问题 What do the square brakets mean in vb.net in this variable below defining as [String] Dim client As New WebClient() Dim htmlCode As [String] = client.DownloadString("http://www.stackoverflow.com") 回答1: It's useless in your example. Brackets are there to use reserved keywords for what they aren't, for example Dim [String] = "asdf" which will create a var named "String" (which is stupid, but...) 回答2: It allows you to use a reserved word in your code. There is some mis-information about this as

what do the square brakets mean in vb.net in this string

对着背影说爱祢 提交于 2020-01-15 11:54:29
问题 What do the square brakets mean in vb.net in this variable below defining as [String] Dim client As New WebClient() Dim htmlCode As [String] = client.DownloadString("http://www.stackoverflow.com") 回答1: It's useless in your example. Brackets are there to use reserved keywords for what they aren't, for example Dim [String] = "asdf" which will create a var named "String" (which is stupid, but...) 回答2: It allows you to use a reserved word in your code. There is some mis-information about this as

Regex for getting information from square brackets

家住魔仙堡 提交于 2019-12-31 03:12:09
问题 I'm attempting to make something like shortcodes in WordPress, and I'm looking for a regex that will take something like [title:This is a title] and turn it to just This is a title . It would also be useful if someone could suggest a way to take something like [code:some code] and turn that into an array in the form of array( [0] => 'code' [1] => 'some code') or array( 'code' => 'some code' I've tried a few different regexes I've found here and there, but none of them seem to work. Thanks 回答1

Trying to write a c# program that parses a text file that contains data seperated by headers in square brackets

这一生的挚爱 提交于 2019-12-25 00:52:44
问题 Im writting a program that parses a specific text file that has data in it that im going to prcess later. Each part is seperated by a header in square brackets i was wondering how i could put each segment into an array using the header as a name for the array. Below is an example of the begining of the text file. ive set up a form that lets you choose a file you want to process and ive also set up a way of processing it line by line using objReader.ReadLine in a loop [Params] Version=106

Double square brackets in Ruby

淺唱寂寞╮ 提交于 2019-12-23 14:35:03
问题 Given the following code: def map(char, charmap) unless map = charmap[[char]] unless map = charmap[[char, c = input.getc]] input.ungetc(c) if c map = '' end end map end What is the double square brackets doing? Thanks 回答1: It is application of the method [] taking an array as the argument. Since the OP did not make clear, we cannot tell what charmap is, but for example if it were a hash, then charmap[[char, c = input.getc]] would return the value in charmap that corresponds to the key [char,

python regex match optional square brackets

断了今生、忘了曾经 提交于 2019-12-22 08:13:05
问题 I have the following strings: 1 "R J BRUCE & OTHERS V B J & W L A EDWARDS And Ors CA CA19/02 27 February 2003", 2 "H v DIRECTOR OF PROCEEDINGS [2014] NZHC 1031 [16 May 2014]", 3 '''GREGORY LANCASTER AND JOHN HENRY HUNTER V CULLEN INVESTMENTS LIMITED AND ERIC JOHN WATSON CA CA51/03 26 May 2003''' I am trying to find a regular expression which matches all of them. I don't know how to match optional square brackets around the date at the end of the string eg [16 May 2014]. casename = re.compile

Strange C++ syntax

白昼怎懂夜的黑 提交于 2019-12-18 04:52:35
问题 I have 8 years of coding experience, but I have never seen the operator [] passed as a parameter to the function definition. For example, the following code (from an open source project): bree::porder(m_root, [] (treenode* node) { delete node; }); Throughout my coding life, I have always defined [] as an operator overloader, not as a parameter. So what does this new syntax signify? I am using the compiler that comes with Visual Studio 2003. How can I change the above code so that it will

Nested maps in Golang

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-17 23:38:24
问题 func main() { var data = map[string]string{} data["a"] = "x" data["b"] = "x" data["c"] = "x" fmt.Println(data) } It runs. func main() { var data = map[string][]string{} data["a"] = append(data["a"], "x") data["b"] = append(data["b"], "x") data["c"] = append(data["c"], "x") fmt.Println(data) } It also runs. func main() { var w = map[string]string{} var data = map[string]map[string]string{} w["w"] = "x" data["a"] = w data["b"] = w data["c"] = w fmt.Println(data) } It runs again! func main() {