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I'm trying to create a search and replace string like this: src=\"/path/file.jpg\" into src=\"http://mysite.com/path/file.jpg\" By searching for the property src and the equals slash quote. The problem is creating the search string, every time I do it, it becomes a search for src=\\"/ instead of src=\"/ if property = "src" in this segment, how can I get it to work? string equalsSlashQuote = "=" + @"\" + "\""; string search = property + equalsSlashQuote + "/"; string replace = property + equalsSlashQuote + SiteURL + "/"; input = input.Replace(search, replace); The problem is the \, I even tried

I am using the following htaccess rul to remove double or more slashes from web urls: #remove double/more slashes in url RewriteCond %{REQUEST_URI} ^(.*)//(.*)$ RewriteRule . %1/%2 [R=301,L] This is working fine for slashes occured in the middle of uris, such as, If use url: http://demo.codesamplez.com/html5//audio Its being redirected to proper single slahs url: http://demo.codesamplez.com/html5/audio But if the url contains double slashes in the beginning, JUST AFTER the domain name, then there its not working, example: http://demo.codesamplez.com//html5/audio its not being redirected. How I

R Tutorial: How to Integrate R With Java Using Rserve http://codophile.com/2015/05/02/how-to-integrate-r-with-java-using-rserve/ Introduction Building Machine Learning based analytics applications require usage of a range of technologies. Java proves to be a great language for building enterprise solutions, however java lacks on analytics front. To compensate this gap we have languages like R which has a rich set of Machine Learning and Statistical libraries. Integrating both these technologies we could create high end Machine Learning based applications. In the previous post R Tutorial: How

I'm porting the existing website from PHP to Ruby on Rails 3 and I have to keep the urls unchanged. I have the route: get 'companies/' => 'companies#index', :as => :companies In a view file I have: link_to 'Companies', companies_path and this generates the url "http://website.com/companies" instead of "http://website.com/companies/". I want the slash at the end of the url. Is it possible? You can add this to your application.rb: config.action_controller.default_url_options = { :trailing_slash => true } This way all routes will be generated with a trailing slash automatically, with no need to

Possible Duplicate: JSON: why are forward slashes escaped? json.org states, that forward slashes (aka solidus, / ) can be escaped: "\/" However, unescaped slashes are valid, too: "/" What's the rational behind this? Does it come from the Javascript roots? (I.e., "</script>" is a problem in browser-based Javascript, see Douglas Crockford's comment ) Or has it any other reason? I've just published a review of this issue on my blog. I think you are right, that's the only reason. Also note that the slash is the only standard character allowed to be escaped. Usually JSON encoders do it wrong and

Is there any difference between using new RegExp("regex"); and /same_regex/ to test against a target string? I am asking this question because I got different validating result while use these two approaches. Here is the snippet I used to validate an email field: var email="didxga@gmail.comblah@foo.com"; var regex1 = new RegExp("^[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?$"); var regex2 = /^[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a

I am already trying for over an hour and cant figure out the right way to do it, although it is probably pretty easy: I have something like this : foo/bar/test.html I would like to use jQuery to extract everything after the last / . In the example above the output would be test.html . I guess it can be done using substr and indexOf() , but I cant find a working solution. T.J. Crowder At least three ways: A regular expression: var result = /[^/]*$/.exec("foo/bar/test.html")[0]; ...which says "grab the series of characters not containing a slash" ( [^/]* ) at the end of the string ( $ ). Then it