Get value of a string after a slash in JavaScript

瘦欲@ 提交于 2019-11-27 17:39:18
T.J. Crowder

At least three ways:

A regular expression:

var result = /[^/]*$/.exec("foo/bar/test.html")[0];

...which says "grab the series of characters not containing a slash" ([^/]*) at the end of the string ($). Then it grabs the matched characters from the returned match object by indexing into it ([0]); in a match object, the first entry is the whole matched string. No need for capture groups.

Live example

Using lastIndexOf and substring:

var str = "foo/bar/test.html";
var n = str.lastIndexOf('/');
var result = str.substring(n + 1);

lastIndexOf does what it sounds like it does: It finds the index of the last occurrence of a character (well, string) in a string, returning -1 if not found. Nine times out of ten you probably want to check that return value (if (n !== -1)), but in the above since we're adding 1 to it and calling substring, we'd end up doing str.substring(0) which just returns the string.

Using Array#split

Sudhir and Tom Walters have this covered here and here, but just for completeness:

var parts = "foo/bar/test.html".split("/");
var result = parts[parts.length - 1]; // Or parts.pop();

split splits up a string using the given delimiter, returning an array.

The lastIndexOf / substring solution is probably the most efficient (although one always has to be careful saying anything about JavaScript and performance, since the engines vary so radically from each other), but unless you're doing this thousands of times in a loop, it doesn't matter and I'd strive for clarity of code.

You don't need jQuery, and there are a bunch of ways to do it, for example:

var parts = myString.split('/');
var answer = parts[parts.length - 1];

Where myString contains your string.

var str = "foo/bar/test.html";
var lastSlash = str.lastIndexOf("/");
alert(str.substring(lastSlash+1));

Try;

var str = "foo/bar/test.html";
var tmp = str.split("/");
alert(tmp.pop());
Xar E Ahmer
String path ="AnyDirectory/subFolder/last.htm";
int pos = path.lastIndexOf("/") + 1;

path.substring(pos, path.length()-pos) ;

Now you have the last.htm in the path string.

When I know the string is going to be reasonably short then I use the following one liner... (remember to escape backslashes)

// if str is C:\windows\file system\path\picture name.jpg
alert( str.split('\\').pop() );

alert pops up with picture name.jpg

Shailesh Sonare

light weigh

string.substring(start,end)

where

start = Required. The position where to start the extraction. First character is at index 0`.

end = Optional. The position (up to, but not including) where to end the extraction. If omitted, it extracts the rest of the string.

    var string = "var1/var2/var3";

    start   = string.lastIndexOf('/');  //console.log(start); o/p:- 9
    end     = string.length;            //console.log(end);   o/p:- 14

    var string_before_last_slash = string.substring(0, start);
    console.log(string_before_last_slash);//o/p:- var1/var2

    var string_after_last_slash = string.substring(start+1, end);
    console.log(string_after_last_slash);//o/p:- var3

OR

    var string_after_last_slash = string.substring(start+1);
    console.log(string_after_last_slash);//o/p:- var3

Jquery:

var afterDot = value.substr(value.lastIndexOf('_') + 1);

Javascript:

var myString = 'asd/f/df/xc/asd/test.jpg'
var parts    = myString.split('/');
var answer   = parts[parts.length - 1];
console.log(answer);

Replace '_' || '/' to your own need

As required in Question::

var string1= "foo/bar/test.html";
  if(string1.contains("/"))
  {
      var string_parts = string1.split("/");
    var result = string_parts[string_parts.length - 1];
    console.log(result);
  }  

and for question asked on url (asked for one occurence of '=' )::
[http://stackoverflow.com/questions/24156535/how-to-split-a-string-after-a-particular-character-in-jquery][1]

var string1= "Hello how are =you";
  if(string1.contains("="))
  {
      var string_parts = string1.split("=");
    var result = string_parts[string_parts.length - 1];
    console.log(result);
  }
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