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LINQ Partition List into Lists of 8 members [duplicate]

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This question already has an answer here: Split List into Sublists with LINQ 27 answers How would one take a List (using LINQ) and break it into a List of Lists partitioning the original list on every 8th entry? I imagine something like this would involve Skip and/or Take, but I'm still pretty new to LINQ. Edit: Using C# / .Net 3.5 Edit2: This question is phrased differently than the other "duplicate" question. Although the problems are similar, the answers in this question are superior: Both the "accepted" answer is very solid (with the yield statement) as well as Jon Skeet's suggestion to

Skip first couple of lines while reading lines in Python file

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问题 I want to skip the first 17 lines while reading a text file. Let\'s say the file looks like: 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 good stuff I just want the good stuff. What I\'m doing is a lot more complicated, but this is the part I\'m having trouble with. 回答1: Use a slice, like below: with open('yourfile.txt') as f: lines_after_17 = f.readlines()[17:] If the file is too big to load in memory: with open('yourfile.txt') as f: for _ in range(17): next(f) for line in f: # do stuff 回答2: Use

read.csv, header on first line, skip second line [duplicate]

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问题 This question already has an answer here: How can I read the header but also skip lines - read.table()? 5 answers I have a CSV file with two header rows, the first row I want to be the header, but the second row I want to discard. If I do the following command: data <- read.csv(\"HK Stocks bbg.csv\", header = T, stringsAsFactors = FALSE) The first row becomes the header and the second row of the file becomes the first row of my data frame: Xaaaaaaaaa X X.1 Xbbbbbbbbbb X.2 X.3 1 Date PX_LAST