shift

问题 Hopefully this is a simple question but I cannot for the life of me figure out how to do a bitshift in binary. This is being done in the LC3 environemnt. I just need to know how to arithmetical divide by two and shift to the right. I know going left is simple by just adding the binary value to itself, but I have tried the opposite for bitshift right(subtracting from itself, NOTing and then subtracting etc etc.) Would be much appreciated. Or if you have a better way to move x00A0 to x000A that

问题 I'm trying to use one column's values to shift another columns values by that amount. Pandas shift() , per the documentation, takes an integer, but is there a way to instead use a Series? Current Code: import pandas as pd df = pd.DataFrame({ 'a':[1,2,3,4,5,6,7,8,9,10], 'b':[0,0,0,0,4,4,4,0,0,0]}) df['a'] = df['a'].shift(df['b']) ...which is of course not working. Desired output: a b 0 1 0 1 2 0 2 3 0 3 4 0 4 1 4 5 2 4 6 3 4 7 8 0 8 9 0 9 10 0 If it makes it easier, the shift will always be

问题 I'm having a problem where when I ask my program to quit out it prints like I ask it to, however shows my menu of options as well continuously. So I'm getting this: >>> (S)huffle a message. (U)nshuffle a message. (Q)uit program. Choose a option to begin: q Goodbye! (S)huffle a message. (U)nshuffle a message. (Q)uit program. Choose a option to continue: Where I want it to display this if I choose 'q': >>> (S)huffle a message. (U)nshuffle a message. (Q)uit program. Choose a option to begin: q

问题 Array: arr = np.ones([4,4]) array([[ 1., 1., 1., 1.], [ 1., 1., 1., 1.], [ 1., 1., 1., 1.], [ 1., 1., 1., 1.]]) I use shift from scipy.ndimage.interpolation as follows: shift(arr,1, cval=np.nan) array([[ nan, nan, nan, nan], [ nan, 1., 1., 1.], [ nan, 1., 1., 1.], [ nan, 1., 1., 1.]]) HOWEVER, I want: array([[ nan, nan, nan, nan], [ 1., 1., 1., 1.], [ 1., 1., 1., 1.], [ 1., 1., 1., 1.]]) Basically, I want to SHIFT all columns data down the rows and boot the last row out of my data set. Pandas

问题 I need to insert a column (vector) with non-numeric data cells (one or multiple strings) into a cell of non-numeric data at an arbitrary location and retain old data columns by shifting them to the right. my_word = 's' 'i' 'p' 's' 'i' 'p' 's' 'i' 'p' 's' 'i' 'p' 's' 'i' 'p' my_column = 'a' 'b' 'c' 'd' 'e' result_cell_1 = 's' 'a' 'i' 'p' 's' 'b' 'i' 'p' 's' 'c' 'i' 'p' 's' 'd' 'i' 'p' 's' 'e' 'i' 'p' result_cell_2 = 's' 'i' 'a' 'p' 's' 'i' 'b' 'p' 's' 'i' 'c' 'p' 's' 'i' 'd' 'p' 's' 'i' 'e' 'p

问题 I have a __int64 variable x = 0x8000000000000000 . I try to shift it right by byte : x >> 4 I`ve thought that the result should be 0x0800000000000000 , but unfortunately I get 0xf800000000000000 . I use VS10. Why is it so? And how can I solve that? 回答1: The reason is because shifting signed numbers is only defined by the language if the left operand is at least 0. In your case I assume it's a twos-complement representation and your number is negative making the result unspecified (or

问题 X = 712360810625491574981234007851998 is represented using a linked list and each node is an unsigned int Is there a fast way to do X << 8 X << 591 other than X * 2^8 X * 2^591 ? 回答1: Bit shifting is very easy in any arbitrary number of bits. Just remember to shift the overflowed bits to the next element. That's all Below is a left shift by 3 example uint64_t i1, i2, i3, o1, o2, o3; // {o3, o2, o1} = {i3, i2, i1} << 3; o3 = i3 << 3 | i2 >> (32 - 3); o2 = i2 << 3 | i1 >> (32 - 3); o1 = i1 << 3

问题 Is there any way to detect the shift key being pressed while the mouse is already over a particular element? Right now, what I have is this: $( "body" ).on("mouseover", ".topic:not(.loadable) > p", function ( event ){ if(event.shiftKey){ this.style.color = 'goldenrod'; } }); $( "body" ).on("mouseleave", ".topic:not(.loadable) > p", function ( event ){ this.style.color = 'black'; }); But it only changes color if the shift key was being held prior to entering the element. 来源： https:/

问题 In my Android studio project I have a fragment with constraint layout inside. Here is XML. <android.support.constraint.ConstraintLayout android:id="@+id/pinLayout" android:layout_width="match_parent" android:layout_height="250dp" app:layout_constraintEnd_toEndOf="parent" app:layout_constraintHorizontal_bias="0.5" app:layout_constraintStart_toStartOf="parent" app:layout_constraintTop_toBottomOf="@+id/topLayout"> <android.support.constraint.ConstraintLayout android:layout_width="0dp" android

问题 I am currently struggling writing a loop that starts at a certain point in an Array and pushes it down to the right one spot to that a new value can be placed where the existing one is, an insertion sort. So far I have a loop that finds which spot the value goes: int hold=0; for (int j = 0; j < nElements; j++) { int temp = list[j]; if (temp <= value) { hold = j; } } I am now writing for for loop that shifts everything over. I have: for (int j = hold; j >= numElements; j--) { int temp = list[j