shift

问题 Is there a built in way to obtain the equivalent of a key combined with the Shift key e.g: a + Shift -> A 1 + Shift -> ! I currently have all the keys mapped in a dictionary in pretty much the same way as illustrated above. I'm using windows forms. 回答1: You can achieve what you want by first calling vkKeyScan to get the virtual-keycode for the char you're interested in. With the outcome of that call you can feed ToUnicode to translate what the characters would be when the Shift key is pressed

问题 having two columns A and B in a dataframe: A B 0 1 6 1 2 7 2 1 8 3 2 9 4 1 10 I would like to create a column C. C must have values of B shifted by value of A: A B C 0 1 6 NaN 1 2 7 NaN 2 1 8 7 3 2 9 7 4 1 10 9 The command: df['C'] = df['B'].shift(df['A']) does not work. Do you have any other ideas? 回答1: This is tricky due to index alignment, you can define a user func and apply row-wise on your df, here the function will perform a shift on the B column and return the index value (using .name

问题 This question already has answers here : Pygame: Is there any easy way to find the letter/number of ANY alphanumeric pressed? (2 answers) Closed last year . I have a Pygame program that needs text input. The way it does this is to get keyboard input and when a key is pressed it renders that key so it is added to the screen. Essentially it acts like a text field. The problem is, when you hold shift it doesn't do anything. I realize this is because the program ignores shift input and instead

问题 Is there a way to get a standard Windows Forms application to detect if the Shift key is being held down on application startup - without using Windows hooks? I ideally would like the workflow to change from normal if the shift key is held down when the EXE file is run. 回答1: Here is an article about reading the key states (and mouse) directly. 回答2: The ModifierKeys property looks ideal: private void Form1_Load(object sender, EventArgs e) { if ( (ModifierKeys & Keys.Shift) != 0) { MessageBox

问题 I'm currently trying to understand the 2d fourier shift theorem. According to what I've learnd so far a translation in the image space leads to differences in phase but not the magnitude in frequency space. I tried to demonstrate this with a little example but it only worked for shifts in rows but not in columns. Here's the little demo (I'm only showing the magnitude plots here) clear all close all Iin = zeros(128); Iin(10:20,10:20)=1; figure,imagesc(Iin) Y = fft(Iin); figure, imagesc

问题 I thought I had it with, void shiftArray(NSMutableArray *mutableArray, NSUInteger shift) { for (NSUInteger i = 0; i < [mutableArray count]; i++) { NSUInteger newIndex = (i + shift) % [mutableArray count]; [mutableArray exchangeObjectAtIndex:i withObjectAtIndex:newIndex]; } } which turns 0,1,2,3,4 into 0,2,3,4,1 when I shift by one. The expected result is 4,0,1,2,3 I feel like I'm missing something obvious... Update: Thanks Matthieu, this is what my function looks like now. void

问题 I have the following pandas Dataframe: import pandas as pd data = {'one' : pd.Series([1.], index=['a']), 'two' : pd.Series([1., 2.], index=['a', 'b']), 'three' : pd.Series([1., 2., 3., 4.], index=['a', 'b', 'c', 'd'])} df = pd.DataFrame(data) df = df[["one", "two", "three"]] one two three a 1.0 1.0 1.0 b NaN 2.0 2.0 c NaN NaN 3.0 d NaN NaN 4.0 I know how to shift elements by column upwards/downwards, e.g. df.two = df.two.shift(-1) one two three a 1.0 2.0 1.0 b NaN NaN 2.0 c NaN NaN 3.0 d NaN

问题 I want to write a program that shifts an array by a set number of positions right or left based on the user's input (positive ->, negative <-). The program has to have O(n) complexity. I've written it this way but it doesn't work as it should. In the example the output should be "2, 3, 4, 5, 6, 1" but in my version is "6, 2, 3, 4, 5, 1". #include <stdio.h> #include <string.h> #include <math.h> void rotate(int *array, int N, int D); int main(){ int i; int array[] = {1, 2, 3, 4, 5, 6}; rotate

问题 I adopted the code from this post and made this fiddle. Try clicking the first row, then shift-clicking the last row. If you notice this code does very well, except the last row, the row that you click on, does not get selected. I have been scratching my head on this one. Can anyone help me alter the code so that the multiselect selects the last row too? Thanks! 回答1: try replacing this: if ((shouldSelectRow = id == startID || shouldSelectRow)) { with this: if ((shouldSelectRow = id == startID

问题 I am trying to figure out why if I shift the negative integer -1 I always get -1, e.g.: echo -1 >> 64; // -1 echo -1 >> 5; // -1 echo -1 >> 43; // -1 echo -1 >> 1; // -1 Whatever second operand of the right shift is given, -1 remains -1... I do understand that when you perform a right shift you're actually doing this: x >> y = x / 2^y But in the case of x being -1, if so, I do: -1 >> 3 = -1 / 2^3 Shouldn't this value be -1/8 = -0.125? Thanks for the attention. 回答1: Bitwise shift operators don