rmiregistry

Please see the passage "RMI Registry Issue" of this article for the background on Java Update 1.6.0_29 first. If I understand correctly (I'm german), the update introduces a bug in the rmiregistry which fails to work with the file: pattern in the codebase. I.E. the following won't work any more with 1.6.0_29: -Djava.rmi.server.codebase="file:myproject/bin/ ..." We are currently using the feature of having a codebase with file: syntax. Does anyone know a workaround for making this work? Note: No, we do not want to start a local webserver or ftp server. Update: On Naming.bind this exception is

I am trying to get a rmi connection going. I have ran into many security issues but have been unable to find a way past all this. I execute my jar file with: java -Djava.security.policy=java.security.AllPermission -jar "myjarfile" The code I have been using to create this is: public class server { public static void main(String args[])throws Exception { if (System.getSecurityManager() == null) System.setSecurityManager ( new RMISecurityManager() { public void checkConnect (String host, int port) {} public void checkConnect (String host, int port, Object context) {} }); try { sampleserverimpl

For RMI on server-side, do we need to start rmiregistry program, or just call LocateRegistry.createRegistry ? If both are possible, what are the advantages and disadvantages? They're the same thing... rmiregistry is a separate program, which you can run from a command line or a script, while LocateRegistry.createRegistry does the same thing programatically. In my experience, for "real" servers you will want to use rmiregistry so that you know it's always running regardless of whether or not the client application is started. createRegistry is very useful for testing, as you can start and stop

I have a service object that can be connected to via RMI. Currently I'm doing this: Server Registry r = LocateRegistry.createRegistry(1234); r.bind("server", UnicastRemoteObject.exportObject(remoteServer, 0)); Client RemoteServer s = LocateRegistry.getRegistry("example.com", 1234).lookup("server"); The registry on the server has only one use, to link to the single server object. I figured I might just as well do this on the server: UnicastRemoteObject.exportObject(remoteServer, 1234); But then how would I connect to the server object from the client? The RMI Registry exists to solve the RMI

I am working on Java RMI. I am having little issue with running my rmiregistry on port 2028 as I allready used that one to run my test program. I can run my program using other port but I would like to know, How we can close rmiregistry running on perticular port ? If you want to do this in programming, we do something like: // create the registry Registry rmiRegistry = LocateRegistry.createRegistry(port); ... // connect to it JMXConnectorServer connector = JMXConnectorServerFactory.newJMXConnectorServer(url, new HashMap<String, Object>(), ManagementFactory.getPlatformMBeanServer()); // do

I'm trying to make a Java RMI client/server app. I'm running into problems starting up the server side of my app, as it keeps running into a ClassNotFoundException during the call to the Registry.bind() method when I attempt to start up the server side of the app. I started with the simple tutorial here: http://docs.oracle.com/javase/1.5.0/docs/guide/rmi/hello/hello-world.html . After following those instructions, it was initially throwing a ClassNotFoundException complaining that it couldn't find "example.hello.Hello". I was able to resolve that by starting the rmiregistry FROM the destDir