rmiregistry

问题 I have written java programs for Client and Server. But, to run the program I need to start rmi registry manually! How to start RMI registry through java code (through Server)? 回答1: Use LocateRegistry.createRegistry(port) . See javadoc. 回答2: First, you need execute in java bin folder "start rmiregistry" throught shell/command line (create CLASSPATH system var to java class/jar to the project to register in RMI Register, RMI Registry need know their classes). Before you can use LocateRegistry

问题 I have written java programs for Client and Server. But, to run the program I need to start rmi registry manually! How to start RMI registry through java code (through Server)? 回答1: Use LocateRegistry.createRegistry(port) . See javadoc. 回答2: First, you need execute in java bin folder "start rmiregistry" throught shell/command line (create CLASSPATH system var to java class/jar to the project to register in RMI Register, RMI Registry need know their classes). Before you can use LocateRegistry

问题 I have written java programs for Client and Server. But, to run the program I need to start rmi registry manually! How to start RMI registry through java code (through Server)? 回答1: Use LocateRegistry.createRegistry(port) . See javadoc. 回答2: First, you need execute in java bin folder "start rmiregistry" throught shell/command line (create CLASSPATH system var to java class/jar to the project to register in RMI Register, RMI Registry need know their classes). Before you can use LocateRegistry

问题 I have written java programs for Client and Server. But, to run the program I need to start rmi registry manually! How to start RMI registry through java code (through Server)? 回答1: Use LocateRegistry.createRegistry(port) . See javadoc. 回答2: First, you need execute in java bin folder "start rmiregistry" throught shell/command line (create CLASSPATH system var to java class/jar to the project to register in RMI Register, RMI Registry need know their classes). Before you can use LocateRegistry

问题 This is the whole exception: Computeappengine exceptionRemoteException occurred in server thread; nested exception is: java.rmi.UnmarshalException: error unmarshalling arguments; nested exception is: java.lang.ClassNotFoundException: Client.prog (no security manager: RMI class loader disabled) java.rmi.ServerException: RemoteException occurred in server thread; nested exception is: java.rmi.UnmarshalException: error unmarshalling arguments; nested exception is: java.lang

问题 I have several services which export an RMI interface. They used to offer this by creating their own registry (with LocateRegistry.createRegistry ) and binding it there. However, that became impossible when the services were moved to run as separate applications in the same VM (Tomcat), because for some reason only one registry can be present there. I worked around this by using a central registry for all the services. Even then, I'm not really interested in the multi-object registry role of

问题 I am running a Hello World example for java RMI 1) I run the registry in an empty folder motta@motta-laptop ~/tmp $ rmiregistry 2) I start the HTTP server to retrieve the classes at runtime. The download folder contains the remote interface for the client-server motta@motta-laptop ~/download $ java NanoHTTPD 8080 3) I start the server passing the java.rmi.server.codebase property as suggested in the java RMI tutorial motta@motta-laptop ~/server $ java -Djava.rmi.server.codebase="http:/

问题 For RMI on server-side, do we need to start rmiregistry program, or just call LocateRegistry.createRegistry ? If both are possible, what are the advantages and disadvantages? 回答1: They're the same thing... rmiregistry is a separate program, which you can run from a command line or a script, while LocateRegistry.createRegistry does the same thing programatically. In my experience, for "real" servers you will want to use rmiregistry so that you know it's always running regardless of whether or

问题 What is the difference between the Registry class and Naming class. In my application I am using Registry class. But I want to know about Naming class and its uses ? 回答1: The difference is that Naming is a utility class with static methods, while Registry is a remote interface. Unsurprisingly, Naming calls Registry internally. Note that the name arguments you pass to java.rmi.Naming are in URL format, and include the location of the registry, whereas with java.rmi.registry.Registry , the name

问题 I'm trying to make a Java RMI client/server app. I'm running into problems starting up the server side of my app, as it keeps running into a ClassNotFoundException during the call to the Registry.bind() method when I attempt to start up the server side of the app. I started with the simple tutorial here: http://docs.oracle.com/javase/1.5.0/docs/guide/rmi/hello/hello-world.html. After following those instructions, it was initially throwing a ClassNotFoundException complaining that it couldn't