reshape

Transpose / reshape dataframe without “timevar” from long to wide format

早过忘川 提交于 2021-02-05 09:29:21
问题 I have a data frame that follows the below long Pattern: Name MedName Name1 atenolol 25mg Name1 aspirin 81mg Name1 sildenafil 100mg Name2 atenolol 50mg Name2 enalapril 20mg And would like to get below (I do not care if I can get the columns to be named this way, just want the data in this format): Name medication1 medication2 medication3 Name1 atenolol 25mg aspirin 81mg sildenafil 100mg Name2 atenolol 50mg enalapril 20mg NA Through this very site I have become familiarish with the reshape

Transpose / reshape dataframe without “timevar” from long to wide format

我怕爱的太早我们不能终老 提交于 2021-02-05 09:29:20
问题 I have a data frame that follows the below long Pattern: Name MedName Name1 atenolol 25mg Name1 aspirin 81mg Name1 sildenafil 100mg Name2 atenolol 50mg Name2 enalapril 20mg And would like to get below (I do not care if I can get the columns to be named this way, just want the data in this format): Name medication1 medication2 medication3 Name1 atenolol 25mg aspirin 81mg sildenafil 100mg Name2 atenolol 50mg enalapril 20mg NA Through this very site I have become familiarish with the reshape

Reshape horizontal to to long format using pivot_longer

久未见 提交于 2021-02-05 08:09:10
问题 I am trying to reshape my data to long instead of wide format using the same code provided earlier link , however it doesn't work even after several trials to modify names_pattern = "(.*)_(pre|post.*)", My data sample is data1<-read.table(text=" Serial_ID pre_EDV pre_ESV pre_LVEF post_EDV post_ESV post_LVEF 1 76.2 32.9 56.8 86.3 36.6 57.6 2 65.4 35.9 45.1 60.1 26.1 56.7 3 64.4 35.1 45.5 72.5 41.1 43.3 4 50 13.9 72.1 46.4 18.4 60.4 5 89.6 32 64.3 70.9 19.3 72.8 6 62 20.6 66.7 55.9 17.8 68.2 7

Plotting 3D bars over a grid in Matlab

落花浮王杯 提交于 2021-02-05 07:51:55
问题 I have a matrix, A, that contains 50 rows and 4 columns, and the entries are filled with integers. My interest is to construct a stacked 3D bar plot from this data. However, using bar3(A,'stacked') creates a row of 50 bars, whereas I want the bars to be plotted at the coordinates of a grid of size 5 (vertical) x 10 (horizontal). So the first bar in the row would be at location (1,1), second bar at (1,2), 11th bar at (2,1) and so on until the 50th bar which would be at (5,10). I can't seem to

Plotting 3D bars over a grid in Matlab

拈花ヽ惹草 提交于 2021-02-05 07:51:29
问题 I have a matrix, A, that contains 50 rows and 4 columns, and the entries are filled with integers. My interest is to construct a stacked 3D bar plot from this data. However, using bar3(A,'stacked') creates a row of 50 bars, whereas I want the bars to be plotted at the coordinates of a grid of size 5 (vertical) x 10 (horizontal). So the first bar in the row would be at location (1,1), second bar at (1,2), 11th bar at (2,1) and so on until the 50th bar which would be at (5,10). I can't seem to

R reshape name value pairs from wide to long using pivot_longer

一个人想着一个人 提交于 2021-02-04 16:35:06
问题 I am trying to figure out how to reshape a dataset of the names of political parties from wide to long using dplyr and pivot_longer . For each Party_ID , there is a number of constant columns attached (Party_Name_Short, Party_Name, Country, Party_in_orig_title) and a number of time changing factors as well: election, Date, Rename, Reason, Party_Title, alliance, member_parties, split, parent_party, merger, child_party, successor, predecessor . The time changing factors were recorded up to 11

split character columns and get names of field in string

荒凉一梦 提交于 2021-02-02 09:17:06
问题 I need to split a column that contains information into several columns. I'd use tstrsplit but the same kind of information is not in the same order among the rows and I need to extract the name of the new column within the variable. Important to know: there can be many pieces of information (fields to become new variables) and I don't know all of them, so I don't want a "field by field" solution. Below is an example of what I have: library(data.table) myDT <- structure(list(chr = c("chr1",

split character columns and get names of field in string

你。 提交于 2021-02-02 09:16:09
问题 I need to split a column that contains information into several columns. I'd use tstrsplit but the same kind of information is not in the same order among the rows and I need to extract the name of the new column within the variable. Important to know: there can be many pieces of information (fields to become new variables) and I don't know all of them, so I don't want a "field by field" solution. Below is an example of what I have: library(data.table) myDT <- structure(list(chr = c("chr1",

split character columns and get names of field in string

只谈情不闲聊 提交于 2021-02-02 09:14:34
问题 I need to split a column that contains information into several columns. I'd use tstrsplit but the same kind of information is not in the same order among the rows and I need to extract the name of the new column within the variable. Important to know: there can be many pieces of information (fields to become new variables) and I don't know all of them, so I don't want a "field by field" solution. Below is an example of what I have: library(data.table) myDT <- structure(list(chr = c("chr1",

Is there an R function to reshape this data from long to wide?

十年热恋 提交于 2021-01-30 02:40:04
问题 How the data looks now: Coach ID | Student | score | --------------------------------- 1 | A | 8 | 1 | B | 3 | 2 | A | 5 | 2 | B | 4 | 2 | C | 7 | To look like this: Coach ID | Student | score | student_2|score_2| student_3|score_3 ------------------------------------------------------------------ 1 | A | 8 | B | 3 | 2 | A | 5 | B | 4 | C | 7 Is there anyway to reshape data from long to wide? Thanks! 回答1: You could create a new identifier column with unique value for every student and then