range

Ranging over map keys of array type and slicing each array gives the same array for each iteration

两盒软妹~` 提交于 2021-02-05 12:14:17
问题 When trying to add int array keys of a map to a slice of int slices, ranging and using arr[:] to slice array doesn't work as expected. The resultant slice contains only duplicates of the "first" key in the map(commented out for loop). However, copying the array key to another variable and slicing the new variable works, and the resultant slice contains distinct map key values. I wonder why the copying is necessary. Isn't k , the array key, copied from the map as a new array at each iteration?

IN Operator equivalence in indexedDB

我的梦境 提交于 2021-02-05 05:37:27
问题 I want to execute this query select * from properties where propertyCode IN ("field1", "field2", "field3") How can I achieve this in IndexedDB I tried this thing getData : function (indexName, params, objectStoreName) { var defer = $q.defer(), db, transaction, index, cursorRequest, request, objectStore, resultSet, dataList = []; request = indexedDB.open('test'); request.onsuccess = function (event) { db = request.result; transaction = db.transaction(objectStoreName); objectStore = transaction

IN Operator equivalence in indexedDB

假如想象 提交于 2021-02-05 05:37:11
问题 I want to execute this query select * from properties where propertyCode IN ("field1", "field2", "field3") How can I achieve this in IndexedDB I tried this thing getData : function (indexName, params, objectStoreName) { var defer = $q.defer(), db, transaction, index, cursorRequest, request, objectStore, resultSet, dataList = []; request = indexedDB.open('test'); request.onsuccess = function (event) { db = request.result; transaction = db.transaction(objectStoreName); objectStore = transaction

Identify groups of continuous numbers from consecutive list in python

徘徊边缘 提交于 2021-02-04 19:17:49
问题 What is the most efficient way in python for picking multiple n consecutive integers from n consecutive list, picking up one integer from each list. Here n is quite large..say in the order of 100s. L1 = [5,3,2,7,1] L2 = [3,5,6,8,9,21,2] L3 = [5,3,6,7,3,9] I'd like to print out the ranges of consecutive integers from consecutive lists, where first element is picked up from first list, second element from second list and so on and so forth: Candidate solution [5,6,7], [1,2,3], [7,8,9] 回答1: L1 =

How to use in Google Sheets setValue only for range of filtered rows (getRange for not hidden cells)?

泄露秘密 提交于 2021-02-02 09:41:53
问题 I want to know, how to use setValue, if there are filtered rows, so that only the shown rows (C1 + one row down to last row of C) get a value. x(){ var sheet = SpreadsheetApp.getActiveSheet(); var lastRow = sheet.getLastRow(); sheet.getRange(C2, lastRow).setValue('x'); } Update It works, but very slowly. I have tested the following code and it works fast. It must start in the second shown row. The following solution works both with and without filter. What is not yet running is the second row

How to use in Google Sheets setValue only for range of filtered rows (getRange for not hidden cells)?

假装没事ソ 提交于 2021-02-02 09:41:06
问题 I want to know, how to use setValue, if there are filtered rows, so that only the shown rows (C1 + one row down to last row of C) get a value. x(){ var sheet = SpreadsheetApp.getActiveSheet(); var lastRow = sheet.getLastRow(); sheet.getRange(C2, lastRow).setValue('x'); } Update It works, but very slowly. I have tested the following code and it works fast. It must start in the second shown row. The following solution works both with and without filter. What is not yet running is the second row

Check if one Range is within another [closed]

喜夏-厌秋 提交于 2021-01-29 18:03:21
问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 4 months ago . Improve this question let smallRange = 1..<2 let largeRange = 0..<10 largeRange ~= smallRange // False Why does this compile at the first place!? But if it compiles the answer should be True The next code works: smallRange.clamped(to: largeRange) == smallRange // True Is

Strideable Date

非 Y 不嫁゛ 提交于 2021-01-29 08:41:38
问题 I'm looking for cool ways to stride through Date ranges with different increments (either seconds aka TimeInterval or with DateComponents aka .hour , .minute ) import Foundation extension Date: Strideable { // typealias Stride = SignedInteger // doesn't work (probably because declared in extension public func advanced(by n: Int) -> Date { self.addingTimeInterval(TimeInterval(n)) } public func distance(to other: Date) -> Int { return Int(self.distance(to: other)) } } let now = Date() let

Focus/unfocus an input on range slider handler's use

社会主义新天地 提交于 2021-01-29 06:52:33
问题 I have a form where the inputs values are controlled by range sliders. There's a calculation every time there's a new entry on each input which operates on focusout. Though, the calculation doesn't work when only the range sliders are used. Is there a way to focus the inputs while using the range sliders? I can't change the way of calculation, because, it's on all the inputs. So, it has to be this way. My form is bigger, but, here's an example of what I have: <label class="va1">Option a price

Python: Rotate nested lists -90°

大憨熊 提交于 2021-01-29 02:55:01
问题 I'm new to programming and I'm having trouble with a school assignment. I need to print the heart from 'Automate the Boring Stuff Chapter 4', (I already did that.) So now I need to rotate it -90°, I tried multiple solutions, (like reversing the range) but nothing works. What im trying to print is this: ....O.... ...OOO... ..OOOOO.. .OOOOOOO. .OOOOOOO. ..OO.OO.. Here is my code (Spoilers ahead): grid = [['.', '.', '.', '.', '.', '.'], ['.', 'O', 'O', '.', '.', '.'], ['O', 'O', 'O', 'O', '.', '