random

问题 I want to generate a random binary sequence with a ratio of 50%, that is, the same amounts of 0s and 1s. This is what I have so far: length_sequence = 1000; ratio = 0.5; A = logical(randi([0 1],length_sequence,1)); The only problem is that I dont know how to set the ratio. 回答1: The ratio can be interpreted as deterministic (you want 500 ones and 500 zeros in each realization of 1000 values) or as probabilistic (a realization may have more ones than zeros, but the ratio holds over a very large

问题 How can you generate a random number from a specific range, for example the integer 34 in the range [1, 100]? I looked at the Random structure but it doesn't give me what I want, at least from what I can understand. 回答1: I think you have to use the Random structure in the given link like this ... - val nextInt = Random.randRange (1,100); - val r = Random.rand (1,1); - val x1 = nextInt r; - val x2 = nextInt r; 回答2: To get 34 integers between 1 and 100, you could use: let val seed = Random.rand

问题 How can you generate a random number from a specific range, for example the integer 34 in the range [1, 100]? I looked at the Random structure but it doesn't give me what I want, at least from what I can understand. 回答1: I think you have to use the Random structure in the given link like this ... - val nextInt = Random.randRange (1,100); - val r = Random.rand (1,1); - val x1 = nextInt r; - val x2 = nextInt r; 回答2: To get 34 integers between 1 and 100, you could use: let val seed = Random.rand

问题 This question already has answers here : Simple method to shuffle the elements of an array in BASH shell? (3 answers) Closed 2 years ago . Given an array of elements (servers), how do I shuffle the array to obtain a random new array ? inarray=("serverA" "serverB" "serverC") outarray=($(randomize_func ${inarray[@]}) echo ${outarray[@]} serverB serverC serverA There is a command shuf (man page) but it does not exist on every linux. This is my first attempt to post a self-answered question

问题 Given a numpy array consisting of data which has been generated for ongoing time from a simulation. Based on this I'm using tensorflow and keras to train a neural network and my question refers to this line of code in my model: model.fit(X1, Y1, epochs=1000, batch_size=100, verbose=1, shuffle=True, validation_split=0.2) After having read in the documentation of Keras I found out that the validation data set (in this case 20% of the original data) is sliced from the end. As Im generating data

问题 Does Java SecureRandom.nextLong() return all possible values given it inherits from Random which uses only 48 bits? If not, can I still do it in Java maybe by modifying the Random class and how to do it? I just want to use an all random long number generator where all possible long values can be returned, if possible. 回答1: While SecureRandom inherits from Random, it doesn't use the same maths or have the same limitation. It will produce all possible 64-bit values eventually. This class

问题 I need to do a linear congruential generator that will successfully pass the selected statistical tests. My question is: how to choose numbers for the generator properly and which statistical tests should I choose? I thought about: Chi-Square Frequency Test for Uniformity Collect 10,000 numbers per generation method Sub-divide[0.1) into 10 equal subdivisions Kolmogorov-Smirnov Test for uniformity Since K-S Test works better with a smaller set of numbers, you may use the first 100 out fo the

问题 I have generated random data which follows normal distribution using the below code: import numpy as np import matplotlib.pyplot as plt import seaborn as sns rng = np.random.default_rng() number_of_rows = 10000 mu = 0 sigma = 1 data = rng.normal(loc=mu, scale=sigma, size=number_of_rows) dist_plot_data = sns.distplot(data, hist=False) plt.show() The above code generates the below distribution plot as expected: If I want to create a distribution plot that is exactly an inverse curve like below

问题 If the rand() function creates a random number that is 4 bytes in length, and I wanted to create a random number that is 1024 bits in length (128 bytes), is the easiest method to get this by concatenating the rand() function 256 times or is there an alternative method? #include <stdio.h> #include <string.h> int main(void) { const char data[128]; memset(&data, 0x36, 128); printf("%s\n", data); puts(""); printf("%d\n", sizeof(data)/sizeof(data[0])); puts(""); int i = 0; unsigned long rez = 0;

问题 If the rand() function creates a random number that is 4 bytes in length, and I wanted to create a random number that is 1024 bits in length (128 bytes), is the easiest method to get this by concatenating the rand() function 256 times or is there an alternative method? #include <stdio.h> #include <string.h> int main(void) { const char data[128]; memset(&data, 0x36, 128); printf("%s\n", data); puts(""); printf("%d\n", sizeof(data)/sizeof(data[0])); puts(""); int i = 0; unsigned long rez = 0;