public

On a nonconst object, why won't C++ call the const version of a method with public-const and private-nonconst overloads?

我只是一个虾纸丫 提交于 2019-12-01 13:42:54
问题 class C { public: void foo() const {} private: void foo() {} }; int main() { C c; c.foo(); } MSVC 2013 doesn't like this: > error C2248: 'C::foo' : cannot access private member declared in class 'C' If I cast to a const reference, it works: const_cast<C const &>(c).foo(); Why can't I call the const method on the non const object? 回答1: From the standard: 13.3.3 If a best viable function exists and is unique, overload resolution succeeds and produces it as the result. Otherwise overload

Access child user control's property in parent user control

三世轮回 提交于 2019-12-01 10:38:10
I have included a user control in another statically following code : place the folowing directive in the asp code of the parent page or usercontrol: <%@ Register src="Name_of_your_child_control.ascx" tagname="Name_of_your_child_control" tagprefix="uc1" %> use the following tag in the asp-code of the parent page/control: <uc1:Name_of_your_child_control ID="Name_of_your_child_control1" runat="server" /> ..... But the issue is...i am not able to access the public properties of user control which got included(child user control) in given user control(parent user control)... Please help :( Say

Why won't Ruby allow me to specify self as a receiver inside a private method?

旧城冷巷雨未停 提交于 2019-12-01 08:28:22
Ruby as an Object Oriented Language. What that means is whatever message I send, I strictly send it on some object/instance of class. Example: class Test def test1 puts "I am in test1. A public method" self.test2 end def test2 puts "I am in test2. A public Method" end end makes sense I call method test2 on self object But I cannot do this class Test def test1 puts "I am in test1. A public method" self.test2 # Don't work test2 # works. (where is the object that I am calling this method on?) end private def test2 puts "I am in test2. A private Method" end end When test2 is public method I can

Java - Method accessibility inside package-private class?

ⅰ亾dé卋堺 提交于 2019-12-01 03:17:50
If I have a java class which is package-private (declared with "class", not "public class"), there is really no difference if the methods inside are declared public or protected or package-private, right? So which should I use, or when should I use which? I'm a bit confused. If I have a java class which is package-private (declared with "class", not "public class"), there is really no difference if the methods inside are declared public or protected or package-private, right? Well maybe not immediately. But if you then (or in the future) declare a 'protected' or 'public' class that inherits

Scala trait - Is there an equivalent of Java interface public static field?

一世执手 提交于 2019-12-01 02:16:39
In Java: public interface Foo { public static final int Bar = 0; } And in Scala, how can I create a trait Foo that has Bar , and I can access it as: Foo.Bar ? You can create a companion object (to make it the equivalent of static) and define the variable there using the final val keywords (to make it the equivalent of a final constant): trait Foo { } object Foo { final val Bar = 0 } Lots more on this here 来源: https://stackoverflow.com/questions/8867316/scala-trait-is-there-an-equivalent-of-java-interface-public-static-field

What is the difference between 'open' and 'public' in Kotlin?

只愿长相守 提交于 2019-12-01 02:07:51
I am new to Kotlin and I am confused between open and public keywords. Could anyone please tell me the difference between those keywords? The open keyword means “open for extension“: The open annotation on a class is the opposite of Java's final : it allows others to inherit from this class. By default , all classes in Kotlin are final , which corresponds to Effective Java, Item 17: Design and document for inheritance or else prohibit it . You also need to be explicit about methods you want to make overridable, also marked with open : open class Base { open fun v() {} fun nv() {} } The public

C# Make everything following public / private like in C++? [closed]

廉价感情. 提交于 2019-12-01 01:47:19
问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 7 years ago . I recently started learning C#, but I have some background in C++. I was wondering how I would do something like class employee { public: .... ... methods ... .... private: .... ... private member variables ....

PHP classes why use public keyword?

可紊 提交于 2019-12-01 00:10:50
问题 Why should I declare class properties (variables) or methods (functions) using the keyword public , if they're public by default? Or, are they? To phrase my question differently, is public redundant? I understand private and protected , but why declare public if class members are public anyway? 回答1: Yes, public is the default (see visibility docs). People add it, so it is consistent with all the other methods / properties. Furthermore, if you want to declare a property public and don't want

Any performance reason to put attributes protected/private?

别说谁变了你拦得住时间么 提交于 2019-11-30 23:56:00
I "learned" C++ at school, but there are several things I don't know, like where or what a compiler can optimize, seems I already know that inline and const can boost a little... If performance is an important thing (gaming programming for example), does putting class attributes not public ( private or protected ) allow the compiler to make more optimized code ? Because all my previous teacher were saying was it's more "secure" or "prevent not wanted or authorized class access/behavior", but in the end, I'm wonder if putting attributes not public can limit the scope and thus fasten things. I

Scala trait - Is there an equivalent of Java interface public static field?

被刻印的时光 ゝ 提交于 2019-11-30 22:36:25
问题 In Java: public interface Foo { public static final int Bar = 0; } And in Scala, how can I create a trait Foo that has Bar , and I can access it as: Foo.Bar ? 回答1: You can create a companion object (to make it the equivalent of static) and define the variable there using the final val keywords (to make it the equivalent of a final constant): trait Foo { } object Foo { final val Bar = 0 } Lots more on this here 来源: https://stackoverflow.com/questions/8867316/scala-trait-is-there-an-equivalent