On a nonconst object, why won't C++ call the const version of a method with public-const and private-nonconst overloads?

问题

class C
{
public:
    void foo() const {}
private:
    void foo() {}
};

int main()
{
    C c;
    c.foo();
}

MSVC 2013 doesn't like this:

> error C2248: 'C::foo' : cannot access private member declared in class 'C'

If I cast to a const reference, it works:

const_cast<C const &>(c).foo();

Why can't I call the const method on the nonconst object?

回答1:

From the standard:

13.3.3 If a best viable function exists and is unique, overload resolution succeeds and produces it as the result. Otherwise overload resolution fails and the invocation is ill-formed. When overload resolution succeeds, and the best viable function is not accessible (Clause 11) in the context in which it is used, the program is ill-formed.

回答2:

The object is not const, so the non-const overload is a better match. Overload resolution happens before access checking. This ensures that overload resolution is not inadvertently changed by changing the access of a member function.

来源：https://stackoverflow.com/questions/25316779/on-a-nonconst-object-why-wont-c-call-the-const-version-of-a-method-with-publ