precision

问题 When creating a new LocalDateTime using LocalDateTime.now() on my Mac and Windows machine i get a nano precision of 6 on my Mac and a nano precision of 3 on my Windows machine. Both are running jdk-1.8.0-172 . Is it possible to limit or increase the precision on one of the machines? And why is the precision actually different? 回答1: The precision is different because LocalDateTime.now() uses a system default Clock. Obtains the current date-time from the system clock in the default time-zone.

问题 When creating a new LocalDateTime using LocalDateTime.now() on my Mac and Windows machine i get a nano precision of 6 on my Mac and a nano precision of 3 on my Windows machine. Both are running jdk-1.8.0-172 . Is it possible to limit or increase the precision on one of the machines? And why is the precision actually different? 回答1: The precision is different because LocalDateTime.now() uses a system default Clock. Obtains the current date-time from the system clock in the default time-zone.

问题 When creating a new LocalDateTime using LocalDateTime.now() on my Mac and Windows machine i get a nano precision of 6 on my Mac and a nano precision of 3 on my Windows machine. Both are running jdk-1.8.0-172 . Is it possible to limit or increase the precision on one of the machines? And why is the precision actually different? 回答1: The precision is different because LocalDateTime.now() uses a system default Clock. Obtains the current date-time from the system clock in the default time-zone.

问题 I have the Sign Bit, Exponent and Mantissa (as shown in the code below). I'm trying to take this value and turn it into the float. The goal of this is to get 59.98 (it'll read as 59.9799995 ) uint32_t FullBinaryValue = (Converted[0] << 24) | (Converted[1] << 16) | (Converted[2] << 8) | (Converted[3]); unsigned int sign_bit = (FullBinaryValue & 0x80000000); unsigned int exponent = (FullBinaryValue & 0x7F800000) >> 23; unsigned int mantissa = (FullBinaryValue & 0x7FFFFF); What I originally

问题 I wonder how calculators work with precision. For example the value of sin(M_PI) is not exactly zero when computed in double precision: #include <math.h> #include <stdio.h> int main() { double x = sin(M_PI); printf("%.20f\n", x); // 0.00000000000000012246 return 0; } Now I would certainly want to print zero when user enters sin(π). I can easily round somewhere on 1e–15 to make this particular case work, but that’s a hack, not a solution. When I start to round like this and the user enters

问题 I'm currently working on some sort of database benchmark application. Basically, what I'm trying to do is to simulate using threads a certain number of clients that all repeat the same operation (example: a read operation) against the database during a certain period of time. During this time, I want, in each thread, to measure the average delay for getting an answer from the database. My first choice was to rely on ThreadMXBean's getThreadCpuTime() method (http://docs.oracle.com/javase/7

问题 0.1 + 0.2 // => 0.30000000000000004 0.2 + 0.2 // => 0.4 0.3 + 0.2 // => 0.5 I understand it has to do with floating points but what exactly is happening here? As per @Eric Postpischil's comment, this isn't a duplicate: That one only involves why “noise” appears in one addition. This one asks why “noise” appears in one addition and does not appear in another. That is not answered in the other question. Therefore, this is not a duplicate. In fact, the reason for the difference is not due to

问题 0.1 + 0.2 // => 0.30000000000000004 0.2 + 0.2 // => 0.4 0.3 + 0.2 // => 0.5 I understand it has to do with floating points but what exactly is happening here? As per @Eric Postpischil's comment, this isn't a duplicate: That one only involves why “noise” appears in one addition. This one asks why “noise” appears in one addition and does not appear in another. That is not answered in the other question. Therefore, this is not a duplicate. In fact, the reason for the difference is not due to

来源： https://stackoverflow.com/questions/60147860/rounding-issues-net-core-3-1-vs-net-core-2-0-net-framework

来源： https://stackoverflow.com/questions/60147860/rounding-issues-net-core-3-1-vs-net-core-2-0-net-framework