playframework

Play Framework Controller Handling Multiple Futures

早过忘川 提交于 2020-05-01 06:22:08
问题 I have a Play controller that takes in a Model object that comes in from the user interface. This model object is a User that I'm trying to insert into the database. But before I insert this User in the table, I check if there is a duplicate user that already exist for the given EMail address. If yes, I reject the request and if not I insert. I'm using Slick and Play framework and here is my controller code: def registerNewUser(user: User) = { dbService.registerNewUser(User.toUserRow(user))

Where is the object Action in play.api.mvc?

给你一囗甜甜゛ 提交于 2020-03-25 18:01:06
问题 I am a novice of Play Framework. When I learn it on its webpages. I found some code like this: import play.api.mvc._ def logging[A](action: Action[A]) = Action.async(action.parser) { request => logger.info("Calling action") action(request) } I checked its document and there is a function async in ActionBuilder . How does Action.async works? It seems there is no object Action in play.api.mvc 回答1: object Action has been removed in Play 2.8 by Remove deprecated play.api.mvc.Action #9288, and has

Play Framework: Manually open JPA context for Spring RabbitMQ listener

时间秒杀一切 提交于 2020-03-18 10:07:29
问题 I am using Spring-AMQP to monitor a RabbitMQ message queue in a Play application. The problem is I can not access my database from the listener code since the JPA context is not open in this scope. I understand Play Framework manages the JPA context so that it is open when processing HTTP requests, but is there a way I can use JPA from outside Play controllers/jobs? 回答1: Just found the answer was to use JPAPlugin! Example listener method: public void process(Message message) { JPAPlugin

Play Framework: Manually open JPA context for Spring RabbitMQ listener

三世轮回 提交于 2020-03-18 10:04:46
问题 I am using Spring-AMQP to monitor a RabbitMQ message queue in a Play application. The problem is I can not access my database from the listener code since the JPA context is not open in this scope. I understand Play Framework manages the JPA context so that it is open when processing HTTP requests, but is there a way I can use JPA from outside Play controllers/jobs? 回答1: Just found the answer was to use JPAPlugin! Example listener method: public void process(Message message) { JPAPlugin

Play Framework: Manually open JPA context for Spring RabbitMQ listener

孤街醉人 提交于 2020-03-18 10:03:42
问题 I am using Spring-AMQP to monitor a RabbitMQ message queue in a Play application. The problem is I can not access my database from the listener code since the JPA context is not open in this scope. I understand Play Framework manages the JPA context so that it is open when processing HTTP requests, but is there a way I can use JPA from outside Play controllers/jobs? 回答1: Just found the answer was to use JPAPlugin! Example listener method: public void process(Message message) { JPAPlugin

Play-json: Error on updating an object attribute inside an array

荒凉一梦 提交于 2020-02-25 08:41:31
问题 I am playing with play-json library to manipulate my json files. I have followed this official document and everything is working fine but they haven't told the case when we want to update a value of an object inside an array so I am trying this my own example. i.e. [ { "key1": [ { "key12": [ { "key121": "text1", "key122": 121212, "key123": "text2", "key124": [] } ], "key13": 0 } ], "key2": "value2" } ] In above example I am trying to update value of "key123" but getting this error again and

Play-json: Error on updating an object attribute inside an array

£可爱£侵袭症+ 提交于 2020-02-25 08:41:04
问题 I am playing with play-json library to manipulate my json files. I have followed this official document and everything is working fine but they haven't told the case when we want to update a value of an object inside an array so I am trying this my own example. i.e. [ { "key1": [ { "key12": [ { "key121": "text1", "key122": 121212, "key123": "text2", "key124": [] } ], "key13": 0 } ], "key2": "value2" } ] In above example I am trying to update value of "key123" but getting this error again and

Intellij: Not a valid project ID:

我怕爱的太早我们不能终老 提交于 2020-02-24 03:57:24
问题 I updated Intellij Idea to 2018.2.6 Now I can not start my Play-Project with a Play-Configuration - it gives me this: [error] Not a valid project ID: myProject [error] project myProject [error] ^ I tried all of these proposals: https://intellij-support.jetbrains.com/hc/en-us/community/posts/115000530510-SBT-Shell-Error-Not-a-valid-key-idea-shell?flash_digest=650678ba2e9ae36479f2c3e0ab460379a393d2ce A plain SBT configuration works. 回答1: I could solve the problem: Close Project in Intellij.

Intellij: Not a valid project ID:

三世轮回 提交于 2020-02-24 03:57:15
问题 I updated Intellij Idea to 2018.2.6 Now I can not start my Play-Project with a Play-Configuration - it gives me this: [error] Not a valid project ID: myProject [error] project myProject [error] ^ I tried all of these proposals: https://intellij-support.jetbrains.com/hc/en-us/community/posts/115000530510-SBT-Shell-Error-Not-a-valid-key-idea-shell?flash_digest=650678ba2e9ae36479f2c3e0ab460379a393d2ce A plain SBT configuration works. 回答1: I could solve the problem: Close Project in Intellij.

How to use play frameworks Secure module to login a user after that user has been created

陌路散爱 提交于 2020-02-21 10:23:55
问题 I am using the "Secure" module from play framework and its mostly working great. I can login a user by posting a from the the /login route in my application. However, when I "create/signup" a new user, I would like for that user to be automatically logged in after user creation. This, I can't seem to get working programmatically, i.e., by not having to post a form to login. My current code for my user create action is like: public static void create(@Required @Email String email, @Required