in-place

I'm implementing a CUDA program for transposing an image. I created 2 kernels. The first kernel does out of place transposition and works perfectly for any image size. Then I created a kernel for in-place transposition of square images. However, the output is incorrect. The lower triangle of the image is transposed but the upper triangle remains the same. The resulting image has a stairs like pattern in the diagonal and the size of each step of the stairs is equal to the 2D block size which I used for my kernel. Out-of-Place Kernel: Works perfectly for any image size if src and dst are

In Python 3.x the __div__() operator was deprecated in favor of __floordiv__() and __truediv__() . Are the __rdiv__() and __idiv__() operators still used to refer to the reversed and in-place versions of __truediv__() ? If so, what are the operator names for the reversed and in-place versions of __floordiv__() ? __rdiv__ and __idiv__ no longer exist. The new names are the obvious choices of __rtruediv__ , __itruediv__ , __rfloordiv__ , and __ifloordiv__ , following the standard format. This is visible in the link in the second answer on the question you linked, or by doing dir(int) in a Python

I know my title is not much self-explanatory but let me try to explain it here. I have a file name test.txt which has some duplicate lines. Now, what I want to do is remove those duplicate lines and at the same time update test.txt with the new content. test.txt AAAA BBBB AAAA CCCC I know I can use sort -u test.txt to remove the duplicates but to update the file with new content how do I redirect it's output to the same file. The below command doesn't work. sort -u test.txt > test.txt So, why the above command is not working and whats the correct way? Also is there any other way like sort_and

If I have a list in Prolog such as X = [1, 2, 3, 4], how do I add the element 5 to the end of the list to have X = [1, 2, 3, 4, 5]? The append function needs two lists, ie append(A,B,C) to get A and B concatenated to the list C. I can do this with a temporary list Y = [1, 2, 3, 4] and Z = [5], to then do an append(Y, Z, X), but I don't like having a temporary list. The usual disclaimers apply here - this is not homework and I am just learning Prolog. Variables in Prolog can only be assigned once. As soon as X has the value [1,2,3,4] it can never have another value. A temporary variable and

I have the following 3 arrays: int[] indexes = new int[]{0,2,8,5}; String[] sources = new String[]{"how", "are", "today", "you"}; String[] targets = new String[]{"I", "am", "thanks", "fine"}; I want to sort the three arrays based on the indexes: indexes -> {0,2,5,8} sources -> {"how", "are", "you", "today"} targets -> {"I", "am", "fine", "thanks"} I can create a new class myClass with all three elements: class myClass { int x; String source; String target; } Reassign everything to myClass, then sort myClass using x . However, this would required additional spaces. I am wondering if it is