perspective

问题 Here's a stumper... Porting some old code, I have this 2D hex grid being rendered in 2.5D: The y-scale & position of the tiles is calculated for perspective, but I'd like to scale & position them for perspective horizontally as well (the toons at the top of the board look squished). Here's the current code: const SCALE_X = PixiStages.game._width * 0.0012; const SCALE_Y = PixiStages.game._height * 0.0018; this.scale.x = SCALE_X; this.scale.y = SCALE_Y * ( 0.5 + 0.5 * gamePiece.y / Game.TILE

问题 Whenever I hit a breakpoint in my code, I see an obnoxious dialog informing me that "Perspective switch job has encountered a problem", the details of which simply say "NullPointerException". The error log shows this stack trace: java.lang.NullPointerException at org.eclipse.ui.internal.WorkbenchPage.showPart(WorkbenchPage.java:1298) at org.eclipse.ui.internal.WorkbenchPage.busyShowView(WorkbenchPage.java:1269) at org.eclipse.ui.internal.WorkbenchPage$13.run(WorkbenchPage.java:4144) at org

问题 Would it be possible to set via CSS or jquery video perspective to fit exactly where and how I need it ? See picture: I want the video to fit in the red area. Thanks in advance! 回答1: Yes, it is possible. You will need to familiarize yourself with CSS3 transform and perspective properties. .video-wrapper { perspective: 1000px; } video { transform: rotateY(-30deg); } <div class="video-wrapper"> <video width="400" controls> <source src="http://www.w3schools.com/HTML/mov_bbb.mp4" type="video/mp4"

问题 I am attempting to project a series of 3D points onto the screen using a perspective camera matrix. I do not have world space (or consider it being an identity matrix) and my camera does not have camera space (or consider it an identity matrix), I do have a 4x4 matrix for my object space. I am taking the object matrix and multiplying it by the camera perspective matrix, generated with the following method: Matrix4 createPerspectiveMatrix( Float fov, Float aspect, Float near, Float far ) {

问题 I'm working with a homography calculated by OpenCV. I currently use this homography to transform points using the function below. This function performs the task I require however I have no clue how it actually works. Can anyone explain, line by line exactly, the logic/theory behind the last 3 lines of code, I understand that this transforms the point x,y but I'm unclear as to why this works: Why are Z , px and py calculated in this way, what do the elements in h correspond to? Your comments

问题 I'm working with a homography calculated by OpenCV. I currently use this homography to transform points using the function below. This function performs the task I require however I have no clue how it actually works. Can anyone explain, line by line exactly, the logic/theory behind the last 3 lines of code, I understand that this transforms the point x,y but I'm unclear as to why this works: Why are Z , px and py calculated in this way, what do the elements in h correspond to? Your comments

问题 I'm working with a homography calculated by OpenCV. I currently use this homography to transform points using the function below. This function performs the task I require however I have no clue how it actually works. Can anyone explain, line by line exactly, the logic/theory behind the last 3 lines of code, I understand that this transforms the point x,y but I'm unclear as to why this works: Why are Z , px and py calculated in this way, what do the elements in h correspond to? Your comments

问题 I have a Matrix3D object that defines a 2d plane with perspective. (think a large painting that has fallen on the floor, away from you) How can I get the 2d point that relates to the new location after the translation ? If the 'painting' was three horizontal stripes then once the 'painting' is transformed those three stripes of equal width are now a trapezoid where the top stripe is smaller than the middle and bottom one. 回答1: You need to transform a 3D vector of the form (X, Y, 0) using this

问题 Ok, I have to admit that I am a novice to OpenCV and that my MATLAB/lin. Algebra knowledge might be introducing a bias. But what I want to do is really simple, while I still did not manage to find an answer. When trying to rectify an image (or part of an image) under a perspective transformation, you basically perform two steps (assuming you have the 4 points that define the distorted object): find the transformation between some perfect rectangle and the distorted shape (in OpenCV, via

问题 I'm creating some plugins for Eclipse, and I have selected as Target Platform another Eclipse installation, when I run the plugin it launch the Eclipse instance successfully but it always is opened on the Resources perspective, anyone knows how to specify the default for example Java EE perspective when launching another instance of Eclipse selected as target platform? 回答1: You can set the default perspective in the plugin_customization.ini file in the target platform plugins/org.eclipse.sdk