pagination

Google Cloud Data Fusion — building pipeline from REST API endpoint source

只谈情不闲聊 提交于 2021-02-11 06:12:23
问题 Attempting to build a pipeline to read from a 3rd party REST API endpoint data source. I am using the HTTP (version 1.2.0) plugin found in the Hub. The response request URL is: https://api.example.io/v2/somedata?return_count=false A sample of response body: { "paging": { "token": "12456789", "next": "https://api.example.io/v2/somedata?return_count=false&__paging_token=123456789" }, "data": [ { "cID": "aerrfaerrf", "first": true, "_id": "aerfaerrfaerrf", "action": "aerrfaerrf", "time": "1970

How to append several dictionaries while looping through pagination (API) - python 3

白昼怎懂夜的黑 提交于 2021-02-10 16:51:09
问题 I would like to loop through several pages of data which I am accessing through an API, and concatenate the pages to the same dictionary as the loop progresses. So far I managed to loop through all the pages and could print out as the loop goes on, so when the loop is over, all the pages are printed out. But my dictionary contains only the last page! page = 5 i = 0 for i in range(0, page): url =f'http://hotell.difi.no/api/json/npd/wellbore/withcoordinates?page={i+1}' dataset_all = requests

How to have ellipses clickable to show the next sequence of pagination

依然范特西╮ 提交于 2021-02-10 04:31:31
问题 In jQuery DataTables pagination control is displayed like: 1 ... 4 5 6 ... 14 How can I make the ellipses clickable so if it's clicked it will show: 1 ... 7 8 9 ... 14 回答1: SOLUTION Use the code below: $('#example').on('init.dt draw.dt', function(e, settings){ var api = new $.fn.dataTable.Api(settings); $('.dataTables_paginate span a:first + .ellipsis', api.table().container()).replaceWith( $('<a class="paginate_button">...</a>').on('click', function(e){ api.page('previous').draw('page'); e

How to have ellipses clickable to show the next sequence of pagination

雨燕双飞 提交于 2021-02-10 04:29:31
问题 In jQuery DataTables pagination control is displayed like: 1 ... 4 5 6 ... 14 How can I make the ellipses clickable so if it's clicked it will show: 1 ... 7 8 9 ... 14 回答1: SOLUTION Use the code below: $('#example').on('init.dt draw.dt', function(e, settings){ var api = new $.fn.dataTable.Api(settings); $('.dataTables_paginate span a:first + .ellipsis', api.table().container()).replaceWith( $('<a class="paginate_button">...</a>').on('click', function(e){ api.page('previous').draw('page'); e

proper use of Laravel's paginate method?

笑着哭i 提交于 2021-02-10 03:08:30
问题 When I use the paginate method with the following statement: $user = User::where('id', 1)->first(); $images = $user->images->paginate(3); I get the following error: Method Illuminate\Database\Eloquent\Collection::paginate does not exist However when I call it with the following statement: $images = Image::where('user_id', $user->id)->paginate(3); It works accordingly... I'm fairly new to Laravel, so forgive my ignorance, but what is the cause of the difference in results? Don't both statement

Correct way to handle pagination with form submission?

折月煮酒 提交于 2021-02-08 11:21:51
问题 I have a form for doing a search on a search page: <form action="{{ url_for('searchresults') }}" method="get" name="noname" id="theform"> {{ form2.page(id="hiddenpage") }} ... some form inputs <button id = "mybutton" type = "submit" >Apply</button> </form> The form is a SearchForm , where class SearchForm(Form): page = HiddenField() categories = SelectMultipleField(u'Text', validators=[Optional()]) # some other stuff... The view for searchresults handles the form: @app.route('/searchresults',

CakePHP 3 Custom Route in Pagination

穿精又带淫゛_ 提交于 2021-02-08 11:02:55
问题 in my routes file i define a route for my controller method $routes->connect('/category/:cat', ['controller' => 'Categories', 'action' => 'category']); My controller method is this public function category(){ $this->paginate = [ 'limit' => 2 ]; $this->viewBuilder()->layout('newLayout'); $cat = $this->request->params['cat']; $id = $this->Categories->findBySlug($cat)->select(['id'])->hydrate(false)->toArray(); $cid = $id[0]['id']; $category = $this->ProductCategories ->find("all") ->select(['id

CakePHP 3 Custom Route in Pagination

半城伤御伤魂 提交于 2021-02-08 11:02:11
问题 in my routes file i define a route for my controller method $routes->connect('/category/:cat', ['controller' => 'Categories', 'action' => 'category']); My controller method is this public function category(){ $this->paginate = [ 'limit' => 2 ]; $this->viewBuilder()->layout('newLayout'); $cat = $this->request->params['cat']; $id = $this->Categories->findBySlug($cat)->select(['id'])->hydrate(false)->toArray(); $cid = $id[0]['id']; $category = $this->ProductCategories ->find("all") ->select(['id

Timber pagination with custom post type

安稳与你 提交于 2021-02-08 09:42:49
问题 I am trying to use the example shown in the Timber docs for pagination with a custom post type. This is not working as I'd expect. The only way I've gotten a pagination to output is to add query_posts($args); after I set up my query $args and before I pass them into a new Timber\PostQuery but from everything I've read, I shouldn't be doing this. I have read this issue thread, but it seems to rely on using WP_Query directly, and I'm trying to keep this task as simple as possible. Any tips

Timber pagination with custom post type

纵然是瞬间 提交于 2021-02-08 09:41:41
问题 I am trying to use the example shown in the Timber docs for pagination with a custom post type. This is not working as I'd expect. The only way I've gotten a pagination to output is to add query_posts($args); after I set up my query $args and before I pass them into a new Timber\PostQuery but from everything I've read, I shouldn't be doing this. I have read this issue thread, but it seems to rely on using WP_Query directly, and I'm trying to keep this task as simple as possible. Any tips