pack-expansion

问题 To expand flexible function parameters, there is a method using std::initializer_list . However I couldn't understand it. Can anyone explain this in an understandable way? template<typename T, typename... Args> auto print(T value, Args... args) { std::cout << value << std::endl; return std::initializer_list<T>{([&] { std::cout << args << std::endl; }(), value)...}; } 回答1: This is a very confused way of doing things, but C++14 requires that we do something similar. I'll explain the limitations

问题 To expand flexible function parameters, there is a method using std::initializer_list . However I couldn't understand it. Can anyone explain this in an understandable way? template<typename T, typename... Args> auto print(T value, Args... args) { std::cout << value << std::endl; return std::initializer_list<T>{([&] { std::cout << args << std::endl; }(), value)...}; } 回答1: This is a very confused way of doing things, but C++14 requires that we do something similar. I'll explain the limitations

问题 To expand flexible function parameters, there is a method using std::initializer_list . However I couldn't understand it. Can anyone explain this in an understandable way? template<typename T, typename... Args> auto print(T value, Args... args) { std::cout << value << std::endl; return std::initializer_list<T>{([&] { std::cout << args << std::endl; }(), value)...}; } 回答1: This is a very confused way of doing things, but C++14 requires that we do something similar. I'll explain the limitations

问题 I asked a similar question earlier without realizing that that wasn't quite specific enough. So I have this function that has to take in all the arguments of a print function, with the ... and all, and then put it into a queue that will call the actual print function later. Something like: std::queue<SOMETHING> queue; template <typename... Params> void printLater(int a, int b, char* fmt, Params ...args) { queue.push(args); } template <typename... Params> void print(int a, int b, char* fmt,