oracleforms

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 years ago . In short. After patch 19 has been installed I can't run any form: compiled with patch 18 or 19, by myself or others. Immediately after starting I get Windows error: -------------------------------- ifrun60.exe .... -------------------------------- The application failed to initialize properly (0xC0000005). .....

问题 I am using oracle forms 10g. It is web based oracle form application. I want to generate Excel Report from Oracle Forms 10g. I configured WEBUTIL and use CLIENT_OLE2 package. Procedure declared in trigger WHEN-BUTTON-PRESSED. When button pressed then suddenly the form freezes and they cannot do anything. Exit button and menu options stops working. It does not give any message and does not do any action also. Procedure Code: declare application client_ole2.obj_type; workbooks client_ole2.obj

问题 I have just installed Oracle - DevSuitehome2, Oracle Database 10g Express Edition and Oracle Developer Suit - DevSuiteHome2. I am new to this Oracle forms, Oracle Reports, etc. During installation, it asked for the password. I entered it. It was written that use your password in SYS and SYSTEM Database accounts. After installation was completed I started SQL *Plus. I entered SYSTEM as username and my password. ERROR: ORA-12154 :TNS:could not resolve the connect identifier specified I also

问题 I am creating form in which user select "CSV" File and import "CSV" Data into oracle forms Data Block.I have date column when I import date column values into data block then getting following error "FRM-50026 date must be entered in a format like DD-MON-YYYY" My Date Column format in "CSV" File: My Form: Code: DECLARE application Client_OLE2.Obj_Type; workbooks Client_OLE2.Obj_Type; workbook Client_OLE2.Obj_Type; worksheets Client_OLE2.Obj_Type; worksheet Client_OLE2.Obj_Type; worksheet2

问题 I have a multi-record block and what I wanted is to fire insert record after leaving a record (going up or down). I tried to put create_record in WHEN-VALIDATE-RECORD but it say that its an illegal restricted procedure. How can I do create_record in WHEN-VALIDATE-RECORD ? Do I need a procedure/timer? Please show me how. Thanks! 回答1: You might use WHEN-NEW-RECORD-INSTANCE trigger, where using create_record built-in is not restricted , at that mentioned multiple-record block level instead of

问题 I am new in Oracle PL/SQL and I am creating application which will read data from .CVS and insert into database. But problem cames when I run application, it came to the end and I get success message but the data is not inserted to database. declare import_file text_io.file_type; import_file_name varchar2(1000); import_log_file text_io.file_type; import_log_file_name varchar2(1000); vec_importovano number; brojac number; brojac_redova number; linebuf varchar2(10000); p_rbr varchar2(4); p

问题 We've inherited a large Oracle project that was originally Oracle 9 and is now Oracle 11. We don't have much confidence in the Forms change register. Are there any tools we could use to compare the two Forms projects? (By virtue of the fact that two different versions of Forms are involved, there will be differences even though the underlying code hasn't changed). 回答1: The general consensus of the Oracle Tools Developers Users Group is that the ORCL Toolbox FormsTool diff ability is the best

问题 I have a view in my database that has a bunch of fields derived from other information in the database, this is how the view is defined: create view patient_account_view AS select patient.p_mrn, p_fname, p_lname, ammount_paid, quantity*item_cost + repeats*item_cost "ammount_owing", (quantity*item_cost + repeats*item_cost) - ammount_paid "balance" from patient_account, patient, diagnosis, prescribed_treatment, items_used, item, perscription where patient.p_mrn = diagnosis.p_mrn AND patient

问题 I am working on an application that created by oracle forms(6i). I try to use timer in one of my forms every thing was fine during testing and I move my form to production. when I move to production when I open my form, I try to access to another form when my form was opened I faced with problem. unfortunately, I don't know why my menu not working correctly, I mean my menu open another form when this form is running. there isn't any relation between menu and that form, kindly please advise me

问题 how to change the block or form status to 'insert' in oracle forms 10g using when-button-pressed trigger. I want to do the same thing like the 'insert record' button in the default tool bar but using a custom button any ideas? 回答1: Call do_key('create_record'); in your when-button-pressed trigger. This will insert a new record in the current block with all, what state changes accordingly. Changing the state with set_record_property(:system.cursor_record, :system.cursor_block, state, 'INSERT')