Oracle

What was the cost for the most expensive movie(s) in the collection? [duplicate]

由 旧巷老猫 提交于 2021-02-11 07:04:27
问题 This question already has answers here : Oracle SELECT TOP 10 records (6 answers) Oracle SQL - How to Retrieve highest 5 values of a column [duplicate] (5 answers) Closed 2 months ago . Hey guys I know the code to show the most expensive movie but what's the one that will show the most expensive and ones right below it. I think that's the question. This is the code I got for one movie. SELECT * FROM movie WHERE purchase_price = (SELECT MAX(purchase_price) FROM movie); 回答1: Well since your

What was the cost for the most expensive movie(s) in the collection? [duplicate]

由 末鹿安然 提交于 2021-02-11 07:03:18
问题 This question already has answers here : Oracle SELECT TOP 10 records (6 answers) Oracle SQL - How to Retrieve highest 5 values of a column [duplicate] (5 answers) Closed 2 months ago . Hey guys I know the code to show the most expensive movie but what's the one that will show the most expensive and ones right below it. I think that's the question. This is the code I got for one movie. SELECT * FROM movie WHERE purchase_price = (SELECT MAX(purchase_price) FROM movie); 回答1: Well since your

How to create incrementing columns?

由 寵の児 提交于 2021-02-11 06:42:12
问题 I have table with these column names. Province/State Country/Region Lat Long 1/22/20 1/23/20 1/24/20 1/25/20 ... ... 3/21/20 I know to create first 4 columns but I don't know how create date column and increment it. How can I implement such number of columns at once? Thank you! Infected Dead Recovered Object relational data model created by me Question -: Submit working Oracle script for your database schema. 回答1: Don't try to create a column-per-day; just create a table with columns for

Replacing null based on a condition

由 泪湿孤枕 提交于 2021-02-11 04:24:13
问题 I am having a table with many columns (but posting only col1, col2, col3 here for simplified post): id col1 col2 col3 source_id a1 765.3 23-Apr-08 cat a5 a2 3298.3 (null) dog a4 a3 8762.1 27-Nov-10 rat a8 a4 (null) (null) (null) (null) a5 (null) (null) (null) a6 a6 (null) (null) (null) (null) I want to fill null values of source _id with values from id . For example, source_id a5 row has null which has to replaced with id a1 values , subsequently, source_id a6 row having null to be replaced

Replacing null based on a condition

由 梦想与她 提交于 2021-02-11 04:24:13
问题 I am having a table with many columns (but posting only col1, col2, col3 here for simplified post): id col1 col2 col3 source_id a1 765.3 23-Apr-08 cat a5 a2 3298.3 (null) dog a4 a3 8762.1 27-Nov-10 rat a8 a4 (null) (null) (null) (null) a5 (null) (null) (null) a6 a6 (null) (null) (null) (null) I want to fill null values of source _id with values from id . For example, source_id a5 row has null which has to replaced with id a1 values , subsequently, source_id a6 row having null to be replaced

Replacing null based on a condition

由 给你一囗甜甜゛ 提交于 2021-02-11 04:23:24
问题 I am having a table with many columns (but posting only col1, col2, col3 here for simplified post): id col1 col2 col3 source_id a1 765.3 23-Apr-08 cat a5 a2 3298.3 (null) dog a4 a3 8762.1 27-Nov-10 rat a8 a4 (null) (null) (null) (null) a5 (null) (null) (null) a6 a6 (null) (null) (null) (null) I want to fill null values of source _id with values from id . For example, source_id a5 row has null which has to replaced with id a1 values , subsequently, source_id a6 row having null to be replaced

JAVA -- JDK JRE JAR

由 百般思念 提交于 2021-02-11 02:25:08
转载：http://blog.csdn.net/wym19830218/article/details/5399401 JDK里面的工具也是用JAVA编写的，它们本身运行的时候也需要一套JRE，如C:/Program Files/Java/jdk1.5.x/目录下的JRE。而C:/Program Files/Java/目录下的JRE是用来执行我们自己编写的JAVA程序。当然，两套JRE中的任何一套都可以用来执行我们自己编写的JAVA程序， 但是JDK里面的工具只能由C:/Program Files/Java/jdk1.5.x/目录下的JRE来执行。 也就是说 jdk(java development kit)是开发工具包，相当于是一个编译器。 jre(java runtime environment)是运行环境，相当于jvm虚拟机。jdk开发出来的java程序必须在jvm中运行，jre就提供了这么一个环境。 ---------------------------------------------------------------------------- JDK就是Java Development Kit.简单的说JDK是面向开发人员使用的SDK，它提供了Java的开发环境和运行环境。SDK是Software Development Kit 一般指软件开发包，可以包括函数库

Generate series of months for every row in Oracle

由 安稳与你 提交于 2021-02-10 23:47:10
问题 I am porting PostgreSQL select statement to Oracle. I cannot figure out how to re-write the following into Oracle syntax: select id, generate_series(date_trunc('month', st_date), en_date,'1 month')::date as dist_date from tst I have a basic idea how I can generate range of months in Oracle, but I think different approach is neeeded as I don't see a way how to plug the following into my sql: select add_months(trunc(sysdate, 'month'), level) from dual connect by level <= months_between(sysdate,

Oracle decode函数

由 ぃ、小莉子 提交于 2021-02-10 23:03:18
decode函数在Oracle SQL查询语句中的使用非常广泛，也经常应用到PL/SQL语句块中。 decode()函数语句的基本表达式是： decode(expr1,expr2,expr3,[expr4]) 作如下理解该表达式： 　　(1)，如果expr1 = expr2,decode函数返回expr3表达式的值; 　　(2)，如果expr1 != expr2,decode函数返回expr4表达式的值,如果expr4未指定，则返回null; 补充： Decode函数的语法结构还包括如下: decode (expression, search_1, result_1) decode (expression, search_1, result_1, search_2, result_2) decode (expression, search_1, result_1, search_2, result_2, ...., search_n, result_n) decode (expression, search_1, result_1, default) decode (expression, search_1, result_1, search_2, result_2, default) decode (expression, search_1, result_1, search_2

Regex101 vs Oracle Regex

由 不羁的心 提交于 2021-02-10 21:32:15
问题 My regex: ^\+?(-?)0*([[:digit:]]+,[[:digit:]]+?)0*$ It is removing leading + and leading and tailing 0s in decimal number. I have tested it in regex101 For input: +000099,8420000 and substitution \1\2 it returns 99,842 I want the same result in Oracle database 11g: select REGEXP_REPLACE('+000099,8420000','^\+?(-?)0*([[:digit:]]+,[[:digit:]]+?)0*$','\1\2') from dual; But it returns 99,8420000 (tailing 0s are still present...) What I'm missing? EDIT It works like greedy quantifier * at the end
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