oracle11g

问题 In oracle I have a DOC_ID column RAW(16) for my UUID/GUID in hibernate I mapped it this way @ID @GeneratedValue(Generator= "uuid") @GenericGenerator(name="uuid", strategy="uuid2") @Type(type="uuid-char") @Column(name="DOC_ID", unique= true) private UUID id; during insertion, it keeps complaining ORA-01465: invalid hex number. May I know what is that issue? 回答1: A char representation of a UUID is 36 chars, whereas the binary representation is 16 bytes. Try with @Type(type="uuid-binary")

问题 I have a few time fields that are INTERVAL DAY(0) TO SECOND(0) Datatypes to store various times of the day. Currently on normal retrieval, my fields display as such: +00 19:00:00.000000 How am I able to format this such that it displays as 19:00? 回答1: You want hours and minutes from an interval. If that interval cannot exceed 24 hours, then you can add the interval to a date without time part and then use TO_CHAR to get the formatted hours and minutes: select to_char(trunc(sysdate) +

问题 I am trying to generate a stacked area graph in r using below command: ggplot(p_ash_r_100,aes(x=SMPL_TIME,y=SMPL_CNT,col=EVENT,group=1))+ geom_area() Here EVENT is the 3rd variable which I want to chart out based on time and sample counts in the ORACLE DB. But the graph with above commands is returning empty. My questions are: How to fix the empty graph problem. How to filter only the 10 top variables based on the amount of data when displaying or earlier? We can do it easily in excel as I

问题 Probably a silly mistake, but I couldn't figure this out myself. When I run this query in Oracle 11g. If this question is answered in SO, please let me know the link. with LAST_BUSINESS_DAY as (select DECODE(to_char(last_day(to_date('29-mar-2013')), 'D'), , '7', to_char((last_day('29-mar-2013') - 1), 'DD-MON-YYYY') , '1', to_char((last_day('29-mar-2013') - 2), 'DD-MON-YYYY') , to_char(last_day('29-apr-2013'), 'DD-MON-YYYY')) as LAST_BD from dual), HOLIDAYS as (select distinct rpt_day from rpt

问题 Hi I have a column with number datatype the data like 1310112000 this is a date, but I don't know how to make it in an understandable format: ex: 10-mar-2013 12:00:00 pm Can any one please help me. 回答1: That is EPOCH time: number of seconds since Epoch(1970-01-01). Use this: SELECT CAST(DATE '1970-01-01' + ( 1 / 24 / 60 / 60 ) * '1310112003' AS TIMESTAMP) FROM DUAL; Result: 08-JUL-11 08.00.03.000000000 AM 回答2: Please try select from_unixtime(floor(EPOCH_TIMESTAMP/1000)) from table; This will

问题 We use Hibernate as a JPA provider and we have a class with a large object field marked with @Lob @Type( type = "org.hibernate.type.TextType" ) private String someString; The column is created as SOMESTRING LONG() This works flawlessly with PostgreSQL and MySQL. With Oracle when persisting the object entityManager.persist( object ); we get an org.hibernate.exception.GenericJDBCException: Could not execute JDBC batch update exception. Removing the @Type( type = "org.hibernate.type.TextType" )

问题 I want to add letter T between date and time using oracle Like this: 2015/01/01T00:00:00 Script for date to_char(l.date_generated, 'yyyy/mm/dd hh24:mi:ss') 回答1: Oracle docs: You can include these characters in a date format model: ...Character literals, enclosed in double quotation marks so, TO_CHAR(l.date_generated, 'yyyy/mm/dd"T"hh24:mi:ss') 来源： https://stackoverflow.com/questions/28146645/how-to-add-letter-t-between-date-and-time-using-oracle

问题 I want to add letter T between date and time using oracle Like this: 2015/01/01T00:00:00 Script for date to_char(l.date_generated, 'yyyy/mm/dd hh24:mi:ss') 回答1: Oracle docs: You can include these characters in a date format model: ...Character literals, enclosed in double quotation marks so, TO_CHAR(l.date_generated, 'yyyy/mm/dd"T"hh24:mi:ss') 来源： https://stackoverflow.com/questions/28146645/how-to-add-letter-t-between-date-and-time-using-oracle

问题 I want to add letter T between date and time using oracle Like this: 2015/01/01T00:00:00 Script for date to_char(l.date_generated, 'yyyy/mm/dd hh24:mi:ss') 回答1: Oracle docs: You can include these characters in a date format model: ...Character literals, enclosed in double quotation marks so, TO_CHAR(l.date_generated, 'yyyy/mm/dd"T"hh24:mi:ss') 来源： https://stackoverflow.com/questions/28146645/how-to-add-letter-t-between-date-and-time-using-oracle

问题 I want to add letter T between date and time using oracle Like this: 2015/01/01T00:00:00 Script for date to_char(l.date_generated, 'yyyy/mm/dd hh24:mi:ss') 回答1: Oracle docs: You can include these characters in a date format model: ...Character literals, enclosed in double quotation marks so, TO_CHAR(l.date_generated, 'yyyy/mm/dd"T"hh24:mi:ss') 来源： https://stackoverflow.com/questions/28146645/how-to-add-letter-t-between-date-and-time-using-oracle