optionmenu

I was wondering if there is any way for me to see what the User has selected among the list displaying, let's say: ["Apple","Orange","Grapes"] right after they select either one of them? Like when user clicks the optionbox, and clicks Apple, Tkinter will return something then if he switches his selection to, let's say, Orange, then that will also return something on the spot. Thanks! How to put parameter correctly? from Tkinter import * def option_changed(a): print "the user chose the value {}".format(variable.get()) print a master = Tk() a = "Foo" variable = StringVar(master) variable.set(

I am using option selected menu item, attached three item (share, login, logout) am select login item, go login activity login social sign (Facebook or google) any one, if login hide login item at same time show logout item, this same type if logout the social sign show login item menu, please help me... step:1) menu.xml define all three menu item. login ,logout and share after that make logout visibility to false by default android:visible="false" and make remaining two items visible.its optional because by default all items are visible in android Step:2)when you are in login Activity inflate

I'm trying to modify the code here to have the user confirm the items selected from the optionmenus . If the user clicks on the Submit button, a message box should open prompting confirmation. Finally, I want the selected items to be returned to the program as variables so they can be used in other functions for further processing. However, my modification is not working; it just returns an empty window. Thoughts on what I am missing? Many thanks. from tkinter import * import tkinter.messagebox class App(Frame): def __init__(self, master): Frame.__init__(self, master) self.dict = {'Asia': [

In this example, if a user selects any option in any of the drop downs, then clicks on another drop down, the previously selected item displayed a check mark beside it. Even though that choice was picked in a different menu. from Tkinter import * from ttk import * choices = ['1st Choice', '2nd Choice', '3rd Choice', '4th Choice'] root = Tk() for each in range(10): OptionMenu(root, StringVar(), choices[0], *choices).pack() root.mainloop() This happens on both Python 2.7 and 3.5. I've even moved the choices list into the loop so it generates on each iteration and the problem still occurs. I'm

I have a search view which is set as expanded by default with default search query but i don't want the virtual keyboard.In below code i tried to hide keyboard in onCreateOptionsMenu but still keyboard is visible. imm = (InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE); MenuItem item = menu.findItem(R.id.menu_search); item.expandActionView(); mSearchView = (SearchView) item.getActionView(); mSearchView.setIconifiedByDefault(false); mSearchView.setQuery(query, true); imm.hideSoftInputFromWindow(mSearchView.getWindowToken(), 0); I am using sherlock search view widget. any