operator-keyword

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 8 years ago . For instance, these are defined in the operator module and can be used as such: import operator print operator.__add__ # alias add -> + print operator.__sub__ # alias sub -> - print operator.__and__ # alias and_

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 8 years ago . For instance, these are defined in the operator module and can be used as such: import operator print operator.__add__ # alias add -> + print operator.__sub__ # alias sub -> - print operator.__and__ # alias and_

问题 We can define intrinsic operators of Python as stated here. Just for curiosity, can we define new operators like $ or *** ? (If so, then we can define ternary condition operators or rotate operators.) 回答1: Expanding on @fasouto answer, but adding a bit more code. While you cannot define new operators AND you cannot redefine existing operators for built-in types, what you can do is to define a class (instantiated to any valid Python name, e.g. op ) that act as an intermediate binding for two

问题 I am trying to overload the << operator. I have successfully overload the other operators but this last one is giving me trouble. Maybe it just needs a new set of eyes. I have a feeling it is all being caused by a const qualifier. Where I need the operator to work. for(UINT i = 0; i < setVector.size(); ++i) { outStream << "SET " << i << setVector[i] << endl; } where setVector is a vector of type Set. Set is a vector of int . This is my operators.cpp /******************************************

问题 I am trying to overload the << operator. I have successfully overload the other operators but this last one is giving me trouble. Maybe it just needs a new set of eyes. I have a feeling it is all being caused by a const qualifier. Where I need the operator to work. for(UINT i = 0; i < setVector.size(); ++i) { outStream << "SET " << i << setVector[i] << endl; } where setVector is a vector of type Set. Set is a vector of int . This is my operators.cpp /******************************************

问题 From cplusplus.com, I saw that ostream class's member function operator<< looks like this: ostream& operator<< (bool val); ostream& operator<< (int val); .... and so on. It does make sense because when you use the Cout object like cout<<x you activate the ostream& operator<< (int val) function, so you actually use the << operator on Cout object. This is very much like every other operator and sends the int variable to the function. What is the difference and what exactly happens when I want

问题 Here, I have a class called Value which simply can get and set float . class Value { public: Value(float f) :f(f){}; float get() { return f; } void set(float f) { this->f = f; } private: float f; }; And I want my class to be able to work like the following example. Value value(3); std::cout << value * 2 - 1 << std::endl; // -> 5 std::cout << value == 5 << std::endl; // -> true value /= 2; std::cout << value << std::endl; // -> 2.5 Should I manually add all operator methods to my class? Or

问题 I have a class and i want to overload the fuction-call operator. But since the C++ standard forbids declaring two similar methods which only differ in return type, i get the compile error C2556. I want to use the functions as getter and setter methods. I know i can achieve this by creating a get and a set function. So the question is : Is there a way to achieve this somehow? class Foo { private: std::vector<int> m_vec; public: Foo() { m_vec.push_back(1); m_vec.push_back(2); m_vec.push_back(3)

问题 I read that Dart does not support function overloading. Does it support operator overloading. If yes, would be kind and show me how in a simple example how its done. And what are some advantages etc. I am new to programming. Thanks. 回答1: The chosen answer is no longer valid when you try overloads the == operator in new version .Now you need do like this: class MyClass { @override bool operator ==(other) { // compare this to other } } But it's not safe. other is not specified as a type,

问题 This question already has an answer here : Order of implicit conversions in c# (1 answer) Closed last year . Consider the following code: public class Test { public static implicit operator int(Test t) { return 42; } public override string ToString() { return "Test here!"; } } var test = new Test(); Console.WriteLine(test); // 42 Console.WriteLine((Test)test); // 42 Console.WriteLine((int)test); // 42 Console.WriteLine(test.ToString()); // "Test here!" Why in the first three cases we have