onresume

what does onBackPress call in a Fragment

时光毁灭记忆、已成空白 提交于 2019-12-24 11:07:05
问题 In a Fragment i have this: onPause(){ super.onPause(); if(flag){ getActivity.finish(); }else{ } } onResume(){ flag = true; super.onResume(); } and there is a Button, on click i set this flag to false: Button.onClick{ flag = false; } The idea is: when the button is clicked don't finish this Activity. But when device BackButton is pressed finish(). But this logic isn't working. The reason is, when i press BackButton of the device, onPause is not being called. This is the 4th Fragment in the

how to avoid handling a deep link twice on android?

戏子无情 提交于 2019-12-24 06:46:04
问题 I have an android test app that handles a custom URL deep link (e.g. myapp://xxx/yyy) inside onResume as follows: if (intent.getAction() != Intent.ACTION_VIEW) return; String data = intent.getDataString(); if (data == null) return; // do stuff with 'data' which is the custom URL The problem is that this code processes the URL again and again every time the app resumes, even if it wasn't reopened using a deep link! So let's say I: run the app once using a custom url the URL gets processed

How to detect OnResume and onPause on react native Es6

大城市里の小女人 提交于 2019-12-23 23:14:15
问题 How can I detect any method from background to foreground es6? Is this possible in React-native? and is there any class or tool that could help with this type of method? 回答1: Try this, it working for me import React, {Component} from 'react' import {AppState, Text} from 'react-native' class AppStateExample extends Component { state = { appState: AppState.currentState } componentDidMount() { AppState.addEventListener('change', this._handleAppStateChange); } componentWillUnmount() { AppState

Locking screen of Android phone results in several subsequent onPause/onResume events

ⅰ亾dé卋堺 提交于 2019-12-23 07:30:15
问题 I encountered this somewhat strange behavior while developing on Android and during my googling the only answer I could find was that this is by design and that I should not care about it. My application fetches location data while active, and I was about to implement a way to preserve battery by stopping location updates when the onPause event is called, and later resume fetching when the onResume event is called. While debugging I noticed this strange behavior when locking the phone,

Can not getIntExtra() at onActivityResult

女生的网名这么多〃 提交于 2019-12-23 03:23:09
问题 I got a problem with sending and receiving int types from one activity to another via Intent; I'm sending it with onActivityResult() function which is placed at the receiving activity. The code: The Sending Activity: Intent ba=new Intent(); MyPoints = fgv.getPoints(); int MP=(int)MyPoints; Log.i("Problem","MyPoints MP = "+MP); ba.putExtra("FocusScore",MP); Log.i("Problem","MyPoints = "+MP); setResult(RESULT_OK,ba); finish(); The Receiving Activity: //At the onClick in order to move the the

Pausing threads properly onPause() and onResume() with a SurfaceView and Thread in Android

被刻印的时光 ゝ 提交于 2019-12-21 06:08:06
问题 To run the games that I've created on Android, I've been using a GamePanel contains the methods onDraw() and onTouch(). I also have been using a GameThread class that calls onDraw() and update() repeatedly. My activity instantiates the GamePanel and my GamePanel instantiates the GameThread. My onPause() just sets the condition in the while-loop inside the thread, run, to false. My onResume() used to just set that equal to true, however that would give me a force close error ( see edit #1 )

Android WebView Save State

谁说我不能喝 提交于 2019-12-20 03:55:22
问题 I have an app with a WebView. There is a page with Upload Photo button so I use the openFileChooser. Sometimes I have a problem when the camera is chosen. The activity restarts and the webview is back on the beginning. How I can save the state of the activity? Please give an example (I saw that a good example of this would be useful). 回答1: You can save the Webview in Android Cache : Use WebView Setting : webView.getSettings().setCacheMode(WebSettings.LOAD_CACHE_ELSE_NETWORK); This will help

Replacing a Fragment with itself does not show anything

99封情书 提交于 2019-12-19 07:28:09
问题 I'm trying to decide and show a fragment in activity's onResume method, but in case a previously added fragment is chosen again, then the activity goes blank. Sample code (with one fragment): @Override protected void onResume(){ FragmentTransaction trans = getSupportFragmentManager().beginTransaction(); trans.replace(R.id.myLayout, fragA); trans.commit(); getSupportFragmentManager().executePendingTransactions(); } With above code, when the activity is created for the first time, it shows

Why is onResume() called when an activity starts?

◇◆丶佛笑我妖孽 提交于 2019-12-18 12:34:44
问题 I have an app where after sign in it throws you at the welcome screen. I put a Toast to see when the onResume fires, but it also fires after onCreate protected void onResume(){ super.onResume(); Database openHelper = new Database(this);//create new Database to take advantage of the SQLiteOpenHelper class myDB2 = openHelper.getReadableDatabase(); // or getWritableDatabase(); myDB2=SQLiteDatabase.openDatabase("data/data/com.example.login2/databases/aeglea", null, SQLiteDatabase.OPEN_READONLY);/

Android - How to start the exact same activity every time the app is opened up?

前提是你 提交于 2019-12-18 09:39:55
问题 In a nutshell, to give you an example, I basically have an app with 3 activities: Activity1 Activity2 StartActivity StartActivity contains two buttons that correspond to the other two activities respectively, starting them up. If I exit the application from Activity1, when I later click on the app icon from the phone, Activity1 is restarted since Android keeps track of this. I need to have the app restart to bring me to the StartActivity, so that I can choose where to go by clicking the